单选题Would you please _____ these books to your classmates?Ahand outBhand downChand inDhand over

单选题
Would you please _____ these books to your classmates?
A

hand out

B

hand down

C

hand in

D

hand over


参考解析

解析:
句意为:你能把那些书发给同学们吗?hand out意为“分发”;hand down意为“把……传下去”;hand in意为“交上”;hand over意为“移交”。

相关考题:

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阅读下列函数说明和C++代码,回答问题[说明]任何一种程序都是为了解决问题而撰写的,解决问题时需要实现一些特定的运算法则。在策略(Strategy)模式下,可以更换实现算法的部分而不留痕迹,切换整个算法,简化改为采用其他方法来解决同样问题。以下是一个“剪刀石头布”游戏。猜拳时的“策略”有2种方法:第一种是“猜赢后继续出同样的招式”(WinningStrategy),第二种是“从上一次出的招式中,以概率分配方式求出下一个招式的几率”(ProbStrategy)。程序中定义了Hand类表示猜拳时的“手势”,类内部以0(石头)、1(剪刀)、2(布)来表示。Hand类的实例只会产生3个。以下是C++语言实现,能够正确编译通过。[C++代码]class Hand{private:int handvalue;static Hand *hand0;static Hand *hand1;static Hand *hand2;(1) ;Hand(int handvalue){this-handvalue = handvalue;}public:(2) Hand* getHand(int handvalue){/*省略具体实现*/}};Hand *Hand::hand0 = new Hand(0);Hand *Hand::hand1 = new Hand(1);Hand *Hand::hand2 = new Hand(2);class Strategy{public:(3) Hand* nextHand() = 0;};class WinningStrategy : public Strategy{private:bool won;Hand *prevHand;public:winningStrategy(){won = false;}Hand* nextHand(){if(!won){prevHand = Hand::getHand(rand()%3);}return prevHand;}};class probstrategy : public Strategy{public:Hand* nextHand(){int handvalue = 0;/*省略具体实现*/return Hand::getHand(handvalue);}};class Player{private:string name;Strategy* strategy;public:Player(string name, (4) strategy){this-name = name;this-strategy = strategy;}Hand *nextHand()(//向战略请示手势return (5) ;}};

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名词解释题hand over hand(步行模型)

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