Please hand () your homework in time . A.onB.outC.in
Please hand () your homework in time .
A.on
B.out
C.in
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7． Hi! This is_______ new teacher．__________ name is Linda．A． your; MyB． his; YourC． your ; HerD． her; His
阅读下列函数说明和C++代码，回答问题[说明]任何一种程序都是为了解决问题而撰写的，解决问题时需要实现一些特定的运算法则。在策略(Strategy)模式下，可以更换实现算法的部分而不留痕迹，切换整个算法，简化改为采用其他方法来解决同样问题。以下是一个“剪刀石头布”游戏。猜拳时的“策略”有2种方法：第一种是“猜赢后继续出同样的招式”(WinningStrategy)，第二种是“从上一次出的招式中，以概率分配方式求出下一个招式的几率”(ProbStrategy)。程序中定义了Hand类表示猜拳时的“手势”，类内部以0(石头)、1(剪刀)、2(布)来表示。Hand类的实例只会产生3个。以下是C++语言实现，能够正确编译通过。[C++代码]class Hand{private:int handvalue;static Hand *hand0;static Hand *hand1;static Hand *hand2;(1) ;Hand(int handvalue){this-handvalue = handvalue;}public:(2) Hand* getHand(int handvalue){/*省略具体实现*/}};Hand *Hand::hand0 = new Hand(0);Hand *Hand::hand1 = new Hand(1);Hand *Hand::hand2 = new Hand(2);class Strategy{public:(3) Hand* nextHand() = 0;};class WinningStrategy : public Strategy{private:bool won;Hand *prevHand;public:winningStrategy(){won = false;}Hand* nextHand(){if(!won){prevHand = Hand::getHand(rand()%3);}return prevHand;}};class probstrategy : public Strategy{public:Hand* nextHand(){int handvalue = 0;/*省略具体实现*/return Hand::getHand(handvalue);}};class Player{private:string name;Strategy* strategy;public:Player(string name, (4) strategy){this-name = name;this-strategy = strategy;}Hand *nextHand()(//向战略请示手势return (5) ;}};
（ ） – Is Miss White __________ English teacher, Maria?– No, she teaches __________ geography.A．your；myB．you；mineC．you；usD．your；us
Your ______ working on my vessel has acknowledged the truth of and liability for the damage．A.representativeB.DPC.ship-ownerD.man