单选题Evaluate these two SQL statements: SELECT last_name, salary, hire_dateFROM EMPLOYEES ORDRE BY salary DESC; SELECT last_name, salary, hire_dateFROM EMPOLYEES ORDER BY 2 DESC; What is true about them? ()AThe two statements produce identical results.BThe second statement returns a syntax error.CThere is no need to specify DESC because the results are sorted in descending order by default.DThe two statements can be made to produce identical results by adding a column alias for the salary column in the second SQL statement.

单选题
Evaluate these two SQL statements: SELECT last_name, salary, hire_dateFROM EMPLOYEES ORDRE BY salary DESC; SELECT last_name, salary, hire_dateFROM EMPOLYEES ORDER BY 2 DESC; What is true about them? ()
A

The two statements produce identical results.

B

The second statement returns a syntax error.

C

There is no need to specify DESC because the results are sorted in descending order by default.

D

The two statements can be made to produce identical results by adding a column alias for the salary column in the second SQL statement.


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Evaluate these two SQL statements: SELECT last_name, salary, hire_dateFROM EMPLOYEES ORDRE BY salary DESC; SELECT last_name, salary, hire_dateFROM EMPOLYEES ORDER BY 2 DESC; What is true about them? ()A. The two statements produce identical results.B. The second statement returns a syntax error.C. There is no need to specify DESC because the results are sorted in descending order by default.D. The two statements can be made to produce identical results by adding a column alias for the salary column in the second SQL statement.

The EMPLOYEES table contains these columns:LAST_NAME VARCHAR2 (25)SALARY NUMBER (6,2)COMMISSION_PCT NUMBER (6)You need to write a query that will produce these results:1. Display the salary multiplied by the commission_pct.2. Exclude employees with a zero commission_pct.3. Display a zero for employees with a null commission value. Evaluate the SQL statement:SELECT LAST_NAME, SALARY*COMMISSION_PCT FROM EMPLOYEESWHERE COMMISSION_PCT IS NOT NULL;What does the statement provide? ()A. All of the desired resultsB. Two of the desired resultsC. One of the desired resultsD. An error statement

Evaluate these two SQL statements:SELECT last_name, salary , hire_dateFROM EMPLOYEESORDER BY salary DESC;SELECT last_name, salary, hire_dateFROM EMPLOYEESORDER BY 2 DESC;What is true about them? () A. The two statements produce identical results.B. The second statement returns a syntax error.C. There is no need to specify DESC because the results are sorted in descending order by default.D. The two statements can be made to produce identical results by adding a column alias for the salary column in the second SQL statement.

The EMPLOYEE tables has these columns:LAST_NAME VARCHAR2(35)SALARY NUMBER(8,2)COMMISSION_PCT NUMBER(5,2)You want to display the name and annual salary multiplied by the commission_pct for all employees. For records that have a NULL commission_pct, a zero must be displayed against the calculated column.Which SQL statement displays the desired results? ()A. SELECT last_name, (salary * 12) * commission_pct FROM EMPLOYEES;B. SELECT last_name, (salary * 12) * IFNULL(commission_pct, 0) FROM EMPLOYEES;C. SELECT last_name, (salary * 12) * NVL2(commission_pct, 0) FROM EMPLOYEES;D. SELECT last_name, (salary * 12) * NVL(commission_pct, 0) FROM EMPLOYEES;

Evaluate these two SQL statements:What is true about them?() A. The two statements produce identical results.B. The second statement returns a syntax error.C. There is no need to specify DESC because the results are sorted in descending order by default.D. The two statements can be made to produce identical results by adding a column alias for the salary column in the second SQL statement.

Examine the data in the EMPLOYEES table:LAST_NAME DEPARTMENT_ID SALARYGetz 10 3000Davis 20 1500Bill 20 2200Davis 30 5000...Which three subqueries work? () A. SELECT * FROM employees where salary (SELECT MIN(salary) FROM employees GROUP BY department _ id);B. SELECT * FROM employees WHERE salary = (SELECT AVG(salary) FROM employees GROUP BY department _ id);C. SELECT distinct department_id FROM employees Where salary ANY (SELECT AVG(salary) FROM employees GROUP BY department _ id);D. SELECT department_id FROM employees WHERE SALARY ALL (SELECT AVG(salary) FROM employees GROUP BY department _ id);E. SELECT last_name FROM employees Where salary ANY (SELECT MAX(salary) FROM employees GROUP BY department _ id);F. SELECT department_id FROM employees WHERE salary ALL (SELECT AVG(salary) FROM employees GROUP BY ANG (SALARY));

Click the Exhibit button and examine the data in the EMPLOYEES table.Which three subqueries work? () A.SELECT * FROM employees where salary (SELECT MIN(salary) FROM employees GROUP BY department_id);B.SELECT * FROM employees WHERE salary = (SELECT AVG(salary) FROM employees GROUP BY department_id);C.SELECT distinct department_id FROM employees WHERE salary ANY (SELECT AVG(salary) FROM employees GROUP BY department_id);D.SELECT department_id FROM employees WHERE salary ALL (SELECT AVG(salary) FROM employees GROUP BY department_id);E.SELECT last_name FROM employees WHERE salary ANY (SELECT MAX(salary) FROM employees GROUP BY department_id);F.SELECT department_id FROM employees WHERE salary ALL (SELECT AVG(salary) FROM employees GROUP BY AVG(SALARY));

下面哪条语句可以取出薪水最高的前三个人:()A、SELECT * FROM (SELECT * FROM EMPLOYEES ORDER BY SALARY );B、SELECT * FROM (SELECT * FROM EMPLOYEES ORDER BY SALARY ) WHERE ROWNUM=3;C、SELECT * FROM (SELECT * FROM EMPLOYEES ORDER BY SALARY DESC) WHERE ROWNUM=3;D、SELECT * FROM EMPLOYEES WHERE ROWNUM=3 ORDER BY SALARY DESC;

The EMPLOYEE tables has these columns: LAST_NAME VARCHAR2(35) SALARY NUMBER(8,2) COMMISSION_PCT NUMBER(5,2) You want to display the name and annual salary multiplied by the commission_pct for all employees. For records that have a NULL commission_pct, a zero must be displayed against the calculated column. Which SQL statement displays the desired results?()A、SELECT last_name, (salary * 12) * commission_pct FROM EMPLOYEES;B、SELECT last_name, (salary * 12) * IFNULL(commission_pct, 0) FROM EMPLOYEES;C、SELECT last_name, (salary * 12) * NVL2(commission_pct, 0) FROM EMPLOYEES;D、SELECT last_name, (salary * 12) * NVL(commission_pct, 0) FROM EMPLOYEES;

Management has asked you to calculate the value 12*salary* commission_pct for all the employees in the EMP table. The EMP table contains these columns: LAST NAME VARCNAR2(35) NOT NULL SALARY NUMBER(9,2) NOT NULL COMMISION_PCT NUMBER(4,2) Which statement ensures that a value is displayed in the calculated columns for all employees?()A、SELECT last_name, 12*salary* commission_pct FROM emp;B、SELECT last_name, 12*salary* (commission_pct,0) FROM emp;C、SELECT last_name, 12*salary*(nvl(commission_pct,0)) FROM emp;D、SELECT last_name, 12*salary*(decode(commission_pct,0)) FROM emp;

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The EMPLOYEES table contains these columns: LAST_NAME VARCHAR2 (25) SALARY NUMBER (6,2) COMMISSION_PCT NUMBER (6) You need to write a query that will produce these results: 1. Display the salary multiplied by the commission_pct. 2. Exclude employees with a zero commission_pct. 3. Display a zero for employees with a null commission value. Evaluate the SQL statement: SELECT LAST_NAME, SALARY*COMMISSION_PCT FROM EMPLOYEES WHERE COMMISSION_PCT IS NOT NULL; What does the statement provide? ()A、All of the desired resultsB、Two of the desired resultsC、One of the desired resultsD、An error statement

Examine the structure of the EMPLOYEES table: EMPLOYEE_ID NUMBER Primary Key FIRST_NAME VARCHAR2(25) LAST_NAME VARCHAR2(25) DEPARTMENT_ID NUMBER SALARY NUMBER What is the correct syntax for an inline view? ()A、SELECT a.last_name, a.salary, a.department_id, b.maxsal FROM employees a, (SELECT department_id, max(salary)maxsal FROM employees GROUP BY department_id) b WHERE a.department_id = b.department_id AND a.salary b.maxsal;B、SELECT a.last name, a.salary, a.department_id FROM employees a WHERE a.department_id IN (SELECT department_id FROM employees b GROUP BY department_id having salary = (SELECT max(salary) from employees))C、SELECT a.last_name, a.salary, a.department_id FROM employees a WHERE a.salary = (SELECT max(salary) FROM employees b WHERE a.department _ id = b.department _ id);D、SELECT a.last_name, a.salary, a.department_id FROM employees a WHERE (a.department_id, a.salary) IN (SELECT department_id, a.salary) IN (SELECT department_id max(salary) FROM employees b GROUP BY department_id ORDER BY department _ id);

Which SQL statement generates the alias Annual Salary for the calculated column SALARY*12?()A、SELECT ename, salary*12 'Annual Salary' FROM employees;B、SELECT ename, salary*12 "Annual Salary" FROM employees;C、SELECT ename, salary*12 AS Annual Salary FROM employees;D、SELECT ename, salary*12 AS INITCAP("ANNUAL SALARY") FROM employees

Click the Exhibit button and examine the data in the EMPLOYEES table. Which three subqueries work?()A、SELECT * FROM employees where salary (SELECT MIN(salary) FROM employees GROUP BY department_id);B、SELECT * FROM employees WHERE salary = (SELECT AVG(salary) FROM employees GROUP BY department_id);C、SELECT distinct department_id FROM employees WHERE salary ANY (SELECT AVG(salary) FROM employees GROUP BY department_id);D、SELECT department_id FROM employees WHERE salary ALL (SELECT AVG(salary) FROM employees GROUP BY department_id);E、SELECT last_name FROM employees WHERE salary ANY (SELECT MAX(salary) FROM employees GROUP BY department_id);F、SELECT department_id FROM employees WHERE salary ALL (SELECT AVG(salary) FROM employees GROUP BY AVG(SALARY));

Examine the data in the EMPLOYEES table: LAST_NAME DEPARTMENT_ID SALARY Getz 10 3000 Davis 20 1500 Bill 20 2200 Davis 30 5000 ... Which three subqueries work? ()A、SELECT * FROM employees where salary (SELECT MIN(salary) FROM employees GROUP BY department _ id);B、SELECT * FROM employees WHERE salary = (SELECT AVG(salary) FROM employees GROUP BY department _ id);C、SELECT distinct department_id FROM employees Where salary ANY (SELECT AVG(salary) FROM employees GROUP BY department _ id);D、SELECT department_id FROM employees WHERE SALARY ALL (SELECT AVG(salary) FROM employees GROUP BY department _ id);E、SELECT last_name FROM employees Where salary ANY (SELECT MAX(salary) FROM employees GROUP BY department _ id);F、SELECT department_id FROM employees WHERE salary ALL (SELECT AVG(salary) FROM employees GROUP BY ANG (SALARY));

The EMP table contains these columns: LAST_NAME VARCHAR2 (25) SALARY NUMBER (6,2) DEPARTMENT_ID NUMBER (6) You need to display the employees who have not been assigned to any department. You write the SELECT statement: SELECT LAST_NAME, SALARY, DEPARTMENT_ID FROM EMP WHERE DEPARTMENT_ID = NULL; What is true about this SQL statement ?()A、The SQL statement displays the desired results.B、The column in the WHERE clause should be changed to display the desired results.C、The operator in the WHERE clause should be changed to display the desired results.D、The WHERE clause should be changed to use an outer join to display the desired results.

Evaluate these two SQL statements:SELECT last_name, salary, hire_dateFROM EMPLOYEES ORDRE BY salary DESC; SELECT last_name, salary, hire_dateFROM EMPOLYEES ORDER BY 2 DESC; What is true about them?()A、The two statements produce identical results.B、The second statement returns a syntax error.C、There is no need to specify DESC because the results are sorted in descending order by default.D、The two statements can be made to produce identical results by adding a column alias for the salary column in the second SQL statement.

多选题Examine the data in the EMPLOYEES table: Which three subqueries work? ()ASELECT * FROM employees where salary (SELECT MIN(salary) FROM employees GROUP BY department _ id);BSELECT * FROM employees WHERE salary = (SELECT AVG(salary) FROM employees GROUP BY department _ id);CSELECT distinct department_id FROM employees Where salary ANY (SELECT AVG(salary) FROM employees GROUP BY department _ id);DSELECT department_id FROM employees WHERE SALARY ALL (SELECT AVG(salary) FROM employees GROUP BY department _ id);ESELECT last_name FROM employees Where salary ANY (SELECT MAX(salary) FROM employees GROUP BY department _ id);FSELECT department_id FROM employees WHERE salary ALL (SELECT AVG(salary) FROM employees GROUP BY ANG (SALARY));

单选题Evaluate these two SQL statements: SELECT last_name, salary , hire_date FROM EMPLOYEES ORDER BY salary DESC; SELECT last_name, salary , hire_date FROM EMPLOYEES ORDER BY 2 DESC; What is true about them?()AThe two statements produce identical results.BThe second statement returns a syntax error.CThere is no need to specify DESC because the results are sorted in descending order by default.DThe two statements can be made to produce identical results by adding a column alias for the salary column in the second SQL statement.

单选题Evaluate these two SQL statements: SELECT last_name, salary , hire_date FROM EMPLOYEES ORDER BY salary DESC; SELECT last_name, salary , hire_date FROM EMPLOYEESORDER BY 2 DESC; What is true about them?()AThe two statements produce identical results.BThe second statement returns a syntax error.CThere is no need to specify DESC because the results are sorted in descending order by default.DThe two statements can be made to produce identical results by adding a column alias for the salary column in the second SQL statement.

单选题The EMPLOYEES table contains these columns: LAST_NAME VARCHAR2 (25) SALARY NUMBER (6,2) COMMISSION_PCT NUMBER (6) You need to write a query that will produce these results: 1. Display the salary multiplied by the commission_pct. 2. Exclude employees with a zero commission_pct. 3. Display a zero for employees with a null commission value. Evaluate the SQL statement: SELECT LAST_NAME, SALARY*COMMISSION_PCT FROM EMPLOYEES WHERE COMMISSION_PCT IS NOT NULL; What does the statement provide?()AAll of the desired resultsBTwo of the desired resultsCOne of the desired resultsDAn error statement

多选题Click the Exhibit button and examine the data in the EMPLOYEES table. Which three subqueries work?()ASELECT * FROM employees where salary (SELECT MIN(salary) FROM employees GROUP BY department_id);BSELECT * FROM employees WHERE salary = (SELECT AVG(salary) FROM employees GROUP BY department_id);CSELECT distinct department_id FROM employees WHERE salary ANY (SELECT AVG(salary) FROM employees GROUP BY department_id);DSELECT department_id FROM employees WHERE salary ALL (SELECT AVG(salary) FROM employees GROUP BY department_id);ESELECT last_name FROM employees WHERE salary ANY (SELECT MAX(salary) FROM employees GROUP BY department_id);FSELECT department_id FROM employees WHERE salary ALL (SELECT AVG(salary) FROM employees GROUP BY AVG(SALARY));

单选题The EMPLOYEES table contains these columns: LAST_NAME VARCHAR2 (25) SALARY NUMBER (6,2) COMMISSION_PCT NUMBER (6) You need to write a query that will produce these results: 1. Display the salary multiplied by the commission_pct. 2. Exclude employees with a zero commission_pct. 3. Display a zero for employees with a null commission value. Evaluate the SQL statement: SELECT LAST_NAME, SALARY*COMMISSION_PCT FROM EMPLOYEES WHERE COMMISSION_PCT IS NOT NULL; What does the statement provide? ()AAll of the desired resultsBTwo of the desired resultsCOne of the desired resultsDAn error statement

单选题Evaluate these two SQL statements: SELECT last_name, salary, hire_dateFROM EMPLOYEES ORDRE BY salary DESC; SELECT last_name, salary, hire_dateFROM EMPOLYEES ORDER BY 2 DESC; What is true about them? ()AThe two statements produce identical results.BThe second statement returns a syntax error.CThere is no need to specify DESC because the results are sorted in descending order by default.DThe two statements can be made to produce identical results by adding a column alias for the salary column in the second SQL statement.

单选题Evaluate these two SQL statements: What is true about them?()A The two statements produce identical results.B The second statement returns a syntax error.C There is no need to specify DESC because the results are sorted in descending order by default.D The two statements can be made to produce identical results by adding a column alias for the salary column in the second SQL statement.

单选题下面哪条语句可以取出薪水最高的前三个人:()ASELECT * FROM (SELECT * FROM EMPLOYEES ORDER BY SALARY );BSELECT * FROM (SELECT * FROM EMPLOYEES ORDER BY SALARY ) WHERE ROWNUM=3;CSELECT * FROM (SELECT * FROM EMPLOYEES ORDER BY SALARY DESC) WHERE ROWNUM=3;DSELECT * FROM EMPLOYEES WHERE ROWNUM=3 ORDER BY SALARY DESC;

多选题Examine the data in the EMPLOYEES table: LAST_NAME DEPARTMENT_ID SALARY Getz 10 3000 Davis 20 1500 Bill 20 2200 Davis 30 5000 ... Which three subqueries work? ()ASELECT * FROM employees where salary (SELECT MIN(salary) FROM employees GROUP BY department _ id);BSELECT * FROM employees WHERE salary = (SELECT AVG(salary) FROM employees GROUP BY department _ id);CSELECT distinct department_id FROM employees Where salary ANY (SELECT AVG(salary) FROM employees GROUP BY department _ id);DSELECT department_id FROM employees WHERE SALARY ALL (SELECT AVG(salary) FROM employees GROUP BY department _ id);ESELECT last_name FROM employees Where salary ANY (SELECT MAX(salary) FROM employees GROUP BY department _ id);FSELECT department_id FROM employees WHERE salary ALL (SELECT AVG(salary) FROM employees GROUP BY ANG (SALARY));