现需配制0.1000mol/LK2Cr2O7溶液,请从下列量器中选用一最合适的量器()?A、容量瓶B、移液管C、量筒D、酸式滴定管

现需配制0.1000mol/LK2Cr2O7溶液,请从下列量器中选用一最合适的量器()?

  • A、容量瓶
  • B、移液管
  • C、量筒
  • D、酸式滴定管

相关考题:

II型呼吸衰竭合并代谢性酸中毒()。 A、Pa0/sub2/supsubno60mHl.PaCO/sub2/supsubno50mmlgB、Pa0/sub2/supsubno60mHgPaCO/sub2/supsubno45mmgC、Pa0/sub2/supsubno60mmHgPaCO/sub2/supsubno50mmHD、Pa0/sub2/supsubno60mHg、PaCO/sub2/supsubno45mmHgE、Pa0/sub2/supsubno60mHg、PaC0/sub2supsubno45mmHg

现需要配制0.1000mol/L K2Cr2O7溶液,下列量器中最合适的量器是( )A.容量瓶B.量筒C.刻度烧杯D.酸式滴定管

A、PH7.38,PaOSUB2/SUB50mmHg,PaCOSUB2/SUB40mmHgB、PH7.30,PaOSUB2/SUB50mmHg,PaCOSUB2/SUB80mmHgC、PH7.40,PaOSUB2/SUB60mmHg,PaCOSUB2/SUB65mmHgD、PH7.35,PaOSUB2/SUB80mmHg,PaCOSUB2/SUB20mmHgE、PH7.25,PaOSUB2/SUB70mmHg,PaCOSUB2/SUB20mmHg血气分析结果符合代偿性代谢性酸中毒( )

下列检查结果哪项最符合该患者目前的病情变化( )A.PaCOSUB2/SUB降低B.PaOSUB2/SUB降低;PaCOSUB2/SUB升高C.PaOSUB2/SUB降低;PaCOSUB2/SUB降低D.肺活量正常,残气量增加E.FEVI减低,残气量正常

PaOSUB2/SUB↓,PaCOSUB2/SUB↑提示( )

在窗体中添加一个命令按钮,编写如下程序: Private Sub Test(p,m,n) p=p+1:m=m+1:n=n+1 Print "Sub: ";p;m;n End Sub Private Sub Command1.Click() a1=1:b=2:c1=3 Call Test((a,b1+3,(c1)) Print "Main:";a1;b1;c1 End Sub 程序运行后,输出结果为A.Sub: 2 6 4 Main: 2 6 4B.Sub: 2 6 4 Main: 2 6 4C.Sub: 2 6 4 Main: 1 2 3D.Sub: 2 6 4 Main: 2 2 3

在窗体中添加一个命令按钮,编写如下程序:Private Sub Sub1(p,m,n)p=p+1:m=m+1:n=n+1Print "sub1:";p;m;nEnd SubPrivate Sub Command1_Click()a1=1:b=2:c1=3Call Sub1(a,b1+3,c1)Print"Main:";a1;b1;c1End Sub程序运行后,输出结果为A.Sub: 2 6 4 Main: 2 6 4B.Sub: 2 6 4 Main: 2 6 4C.Sub: 2 6 4 Main: 1 2 3D.Sub: 2 6 4 Main: 2 2 3

在窗体中添加一个命令按钮,编写如下程序: Private Sub Sub1(p,m,n) p=p+1:m=m+1:n=n+1 Print "sub1:";p;m;n End Sub Private Sub Command1_Click() a1=1:b=2:c1=3 Call Sub1(a,b1+3,c1) Print"Main:";a1;b1;c1 End Sub 程序运行后,输出结果为A.Sub: 2 6 4 Main: 2 6 4B.Sub: 2 6 4 Main: 2 6 4C.Sub: 2 6 4 Main: 1 2 3D.Sub: 2 6 4 Main: 2 2 3

中度哮喘发作时下述检测结果可能有误的是( )A.PaOSUB2/SUB降低B.PaCOSUB2/SUB降低C.pH降低D.SaOSUB2/SUB正常E.PaCOSUB2/SUB升高

class Super {  public int i = 0;  public Super(String text) {  i = 1; }  }  public class Sub extends Super {  public Sub(String text) {  i = 2;  }   public static void main(String args[]) {  Sub sub = new Sub(“Hello”);  System.out.println(sub.i);  }  }  What is the result?()  A、 0B、 1C、 2D、 Compilation fails.

现需要配制0.1000mol/L K2Cr2O7溶液,下列量器中最合适的量器是()A、容量瓶B、量筒C、刻度烧杯D、酸式滴定管

现需配制0.1000mol·L-1Na2CO3溶液,请选用一最合适的仪器()A、酸式滴定管B、容量瓶C、刻度烧杯D、量筒

现需要配制0.1000mol/LK2Cr2O7溶液,下列量器中最合适的量器是()A、容量瓶B、量筒C、刻度烧杯D、酸式滴定管

现需要配制0.1000mol/LK2Cr2O7溶液,下列量器中最合适的量器是()。A、容量瓶B、量筒C、刻度烧杯

0.1000mol/LK2Cr2O7标准溶液对Fe的滴定度TK2Cr2O7/Fe(MFe=55.85)为()g/ml。 TK2Cr2O7/Fe=0.1000×1×10-3×6×55.85=0.03351

单选题变直径圆管流,细断面直径d1,粗断面直径d2=2d1,粗细断面雷诺数的关系是( )。ApResub1/sub=0.5Resub2/sub/pBpResub1/sub=Resub2/sub/pCpResub1/sub=1.5Resub2/sub/pDpResub1/sub=2Resub2/sub /p

单选题class Super {  public int i = 0;  public Super(String text) {  i = 1; }  }  public class Sub extends Super {  public Sub(String text) {  i = 2;  }   public static void main(String args[]) {  Sub sub = new Sub(“Hello”);  System.out.println(sub.i);  }  }  What is the result?()A 0B 1C 2D Compilation fails.

填空题0.1000mol/LK2Cr2O7标准溶液对Fe的滴定度TK2Cr2O7/Fe(MFe=55.85)为()g/ml。 TK2Cr2O7/Fe=0.1000×1×10-3×6×55.85=0.03351

单选题煤矿井下的有害气体主要是由()、CO2、H2S、NO2、H2、NH3气体组成。ACOBpCHsub4/sub、SOsub2/sub/pCpSOsub2/sub、CO/pDpCO、CHsub4/sub、SOsub2/sub/p

单选题对窗体编写如下事件过程: Private Sub Form_MouseDown(Button As Integer,Shif tAs Integer,X As Single Y As Single) If Button=2 Then Print "AAAAA" End If End Sub Private Sub Form_MouseUp(Button As Integer,Shift As Integer,X As Single,Y As Single) Print "BBBBB" End Sub 程序运行后,如果单击鼠标右键,则输出结果为()AAAAAABBBBBBCAAAAA CR BBBBB(其中CR表示回车和换行)DBBBBB CR AAAAA

单选题A pIsub2/sub=Isub3/sub/pB pIsub2/sub=4Isub3/sub/pC pIsub2/sub=2Isub3/sub/pD pIsub3/sub=4Isub2/sub/p

单选题下列测量结果的表示中,错误的是()。ApIsubS/sub=10.0413A,Usubrel/sub=5×10sup-5/sup,k=2 /pBpIsubS/sub=10.0413(1±5×10sup-5/sup)A,k=2 /pCpIsubS/sub=(10.0413±5×10sup-5/sup)A,k=2 /pDpIsubS/sub=10.0413A,Usub95rel/sub=5×10sup-5/sup,Vsubeff/sub=9 /p

多选题1. class Super {  2. private int a;  3. protected Super(int a) { this.a = a; }  4. }  .....  11. class Sub extends Super {  12. public Sub(int a) { super(a); }  13. public Sub() { this.a= 5; }  14. }  Which two, independently, will allow Sub to compile?()AChange line 2 to: public int a;BChange line 2 to: protected int a;CChange line 13 to: public Sub() { this(5); }DChange line 13 to: public Sub() { super(5); }EChange line 13 to: public Sub() { super(a); }

多选题在过程控制中,若TL=-3,Tu=3,u=1,σ=1,则(  )。ACsubP/sub=1 BCsubP/sub=2/3 CCsubPk/sub=1 DCsubPk/sub=2/3

单选题( )被称为广义货币。ApMsub0/sub/pBpMsub1/sub/pCpMsub2/sub/pDpMsub3/sub/p

单选题对窗体编写如下事件过程: Private Sub Form_MouseDown(Button As Integer,Shift As Integer,X As Single Y As Single) If Button=2 ThenPrint"AAAAA"End IfEnd SubPrivate Sub Form_MouseUp(Button As Integer,Shift As Integer,X As Single,Y As Single) Print"BBBBB" End Sub程序运行后,如果单击鼠标右键,则输出结果为()AAAAAABBBBBBCAAAAA CR BBBBB(其中CR表示回车和换行)DBBBBB CR AAAAA

单选题现需要配制0.1000mol/LK2Cr2O7溶液,下列量器中最合适的量器是()A容量瓶B量筒C刻度烧杯D酸式滴定管