称取大理石(CaCO3)试样0.2500g,用HCL溶解,加入PH=10的缓冲溶液和少许K--B指示剂,用CEDAT=0.1000mol/L的EDTA溶液滴定至终点时,消耗25.00ml,计算试样中CaO的质量分数是多少?

称取大理石(CaCO3)试样0.2500g,用HCL溶解,加入PH=10的缓冲溶液和少许K--B指示剂,用CEDAT=0.1000mol/L的EDTA溶液滴定至终点时,消耗25.00ml,计算试样中CaO的质量分数是多少?


相关考题:

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写出程序运行的结果Public class BasePublic virtual string Hello() {return “Base”;}Public class Sub:BasePublic override string Hello() {return “Sub”;}1. Base b = new Base(); b.Hello;2. Sub s = new Sub(); s.Hello;3. Base b = new Sub (); b.Hello;4. Sub s = new Base(); s.Hello;

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单选题酶促反应速度(v)达到最大反应速度(Vmax)的80%时,底物浓度[S]为Ap1Ksubm/sub/pBp2Ksubm/sub/pCp3Ksubm/sub/pDp4Ksubm/sub/pEp5Ksubm/sub/p

单选题A pIsub2/sub=Isub3/sub/pB pIsub2/sub=4Isub3/sub/pC pIsub2/sub=2Isub3/sub/pD pIsub3/sub=4Isub2/sub/p

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多选题1. class Super {  2. private int a;  3. protected Super(int a) { this.a = a; }  4. }  .....  11. class Sub extends Super {  12. public Sub(int a) { super(a); }  13. public Sub() { this.a= 5; }  14. }  Which two, independently, will allow Sub to compile?()AChange line 2 to: public int a;BChange line 2 to: protected int a;CChange line 13 to: public Sub() { this(5); }DChange line 13 to: public Sub() { super(5); }EChange line 13 to: public Sub() { super(a); }

多选题在过程控制中,若TL=-3,Tu=3,u=1,σ=1,则(  )。ACsubP/sub=1 BCsubP/sub=2/3 CCsubPk/sub=1 DCsubPk/sub=2/3

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