单选题有以下程序:#include #include typedef struct{ char name[10]; char sex; int age;}STU;void fun(STU *t){ strcpy((*t).name,Tong); (*t).age++;}main(){ STU s[2] = {Hua, 'm', 18, Qin, 'f', 19}; fun(s+1); printf(%s,%d,%s,%d, s[0].name, s[0].age, s[1].name, s[1].age);}程序运行后的输出结果是(  )。AHua,18,Tong,20BHua,18,Qin,19CTong,19,Qin,19DHua,19,Tong,19

单选题
有以下程序:#include #include typedef struct{ char name[10]; char sex; int age;}STU;void fun(STU *t){ strcpy((*t).name,Tong); (*t).age++;}main(){ STU s[2] = {Hua, 'm', 18, Qin, 'f', 19}; fun(s+1); printf(%s,%d,%s,%d, s[0].name, s[0].age, s[1].name, s[1].age);}程序运行后的输出结果是(  )。
A

Hua,18,Tong,20

B

Hua,18,Qin,19

C

Tong,19,Qin,19

D

Hua,19,Tong,19


参考解析

解析:
程序执行过程为:定义STU类型数组,长度为2,并初始化:s[0].name ="Hua",s[0].sex = 'm',s[0].age = 18,s[1].name = "Qin",s[1].sex = 'f',s[1].age = 19。调用函数fun(s+1)将变量s[1]地址传入函数,因此对形参操作就等价于对实参进行操作,函数执行后s[1].name = "Tong",s[1].age = 20。依次输出Hua,18,Tong,20,答案选择A选项。

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