fragment的remove方法是将activity中的某个fragment进行移除。

fragment的remove方法是将activity中的某个fragment进行移除。


参考答案和解析
正确

相关考题:

下面关于Fragment的描述,正确的是()。 A.使用Fragment,能使程序更加合理和充分地利用屏幕的空间B.Android4.0版本开始提供Fragment类C.Fragment可以代替Activity使用D.Fragment不能嵌入到Activity中

要创建一个Fragment,必须创建一个Fragment的子类,或者继承自另一个已经存在的Fragment的子类。例如,要创建一个名称为NewsFragment,并重写()方法 A.onCreateView()B.onCreate()C.onDraw()D.online()

关于GetPodAction定义,下面赋值正确的是()type Fragment interface {Exec(transInfo *TransInfo) error}type GetPodAction struct {}func (g GetPodAction) Exec(transInfo *TransInfo) error {...return nil} A. var fragment Fragment = new(GetPodAction)B. var fragment Fragment = GetPodActionC. var fragment Fragment = &GetPodAction{}D. var fragment Fragment = GetPodAction{}

Which two are valid fields in an IPv6 header?() A. Hop LimitB. Next HeaderC. Fragment OffsetD. Header Checksum

If you want to test if fragmentation is causing problems on the network, which two ping command options are useful?() A. ttlB. sizeC. rapidD. do-not-fragment

RPR在对于过环的流量进行转发处理时,可以使用以下哪个队列转发模式() A.存储转发模式B.Fragment-Free模式C.剥离复制模式D.碎片转发

IP报头定义如下图,其中Flags包括MF(More Fragment)比特和DF(Don’t Fragment)比特。因特网体系结构分为哪四层?各层与OSI参考模型是如何对应的?

在LAN Switch中()转发方式,在每一个帧都进行了CRC校验。A、Cut-throughB、Store and forwardC、Fragment CheckD、Fragment Free

How does an IPv6 router deal with a packet that is larger than the outgoing interface MTU?()A、It will fragment the packet at Layer 2.B、It will fragment the packet at Layer 3.C、It will drop the packet and send an ICMPv6 message "packet too big" back to the source.D、It will drop the packet.

802.11帧中通过什么参数来重组帧片段?()A、Frame ControlB、DurationC、Address位D、Fragment number

使用Session的(),会把对象的状态从数据库中移除A、delete()B、remove()C、clear()D、removeAll()

Which two are valid fields in an IPv6 header?()A、Hop LimitB、Next HeaderC、Fragment OffsetD、Header Checksum

冈崎片断(Okazaki fragment)

RFLP(restriction fragment length polymorphism,限制性内切酶酶切片段长度多态性)标记

以太网交换机Fragment-free方式检测帧的前()字节中的错误。

使用Session的()会把对象的状态从数据库中移除。A、delete()B、remove()C、clear()

Klenow 片段(Klenow fragment)

IP报头中的Fragment Offset字段的作用?

Given this fragment from a Java EE deployment descriptor: 341. 342.java.lang.Throwable  343./mainError.jsp 344. 345. 346.java.lang.ClassCastException  347./castError.jsp 348. If the web application associated with the fragment above throws a ClassCastException.Which statement is true?()A、The deployment descriptor is invalid.B、The container invokes mainError.jsp.C、The container invokes castError.jsp.D、Neither mainError.jsp nor castError.jsp is invoked.

Which code fragments will succeed in printing the last argument given on the command line to the standard output, and exit gracefully with no output if no arguments are given?()   CODE FRAGMENT a:   public static void main(String args[]) {   if (args.length != 0)   System.out.println(args[args.length-1]);   }   CODE FRAGMENT b:   public static void main(String args[]) {   try { System.out.println(args[args.length]); }   catch (ArrayIndexOutOfBoundsException e) {}   }   CODE FRAGMENT c:   public static void main(String args[]) {   int ix = args.length;   String last = args[ix];   if (ix != 0) System.out.println(last);   }   CODE FRAGMENT d:   public static void main(String args[]) {   int ix = args.length-1;   if (ix  0) System.out.println(args[ix]);   }   CODE FRAGMENT e:   public static void main(String args[]) {   try { System.out.println(args[args.length-1]);  }catch (NullPointerException e) {}   }  A、Code fragment a.B、Code fragment b.C、Code fragment c.D、Code fragment d.E、Code fragment e.

If you want to test if fragmentation is causing problems on the network, which two ping command options are useful?()A、ttlB、sizeC、rapidD、do-not-fragment

单选题Which code fragments will succeed in printing the last argument given on the command line to the standard output, and exit gracefully with no output if no arguments are given?()   CODE FRAGMENT a:   public static void main(String args[]) {   if (args.length != 0)   System.out.println(args[args.length-1]);   }   CODE FRAGMENT b:   public static void main(String args[]) {   try { System.out.println(args[args.length]); }   catch (ArrayIndexOutOfBoundsException e) {}   }   CODE FRAGMENT c:   public static void main(String args[]) {   int ix = args.length;   String last = args[ix];   if (ix != 0) System.out.println(last);   }   CODE FRAGMENT d:   public static void main(String args[]) {   int ix = args.length-1;   if (ix  0) System.out.println(args[ix]);   }   CODE FRAGMENT e:   public static void main(String args[]) {   try { System.out.println(args[args.length-1]);  }catch (NullPointerException e) {}   }ACode fragment a.BCode fragment b.CCode fragment c.DCode fragment d.ECode fragment e.

单选题How does an IPv6 router deal with a packet that is larger than the outgoing interface MTU?()AIt will fragment the packet at Layer 2.BIt will fragment the packet at Layer 3.CIt will drop the packet and send an ICMPv6 message packet too big back to the source.DIt will drop the packet.

问答题IP报头中的Fragment Offset字段的作用?

多选题Which code fragments will succeed in initializing a two-dimensional array named tab with a size that will cause the expression tab[3][2] to access a valid element?()   CODE FRAGMENT a:  int[][] tab = {  { 0, 0, 0 },  { 0, 0, 0 }  };   CODE FRAGMENT b:  int tab[][] = new int[4][];  for (int i=0; i   CODE FRAGMENT c:  int tab[][] = {  0, 0, 0, 0,  0, 0, 0, 0,  0, 0, 0, 0,  0, 0, 0, 0  };   CODE FRAGMENT d:  int tab[3][2];   CODE FRAGMENT e:  int[] tab[] = { {0, 0, 0}, {0, 0, 0}, {0, 0, 0}, {0, 0, 0} };ACode fragment a.BCode fragment b.CCode fragment c.DCode fragment d.ECode fragment e.

名词解释题RFLP(restriction fragment length polymorphism,限制性内切酶酶切片段长度多态性)标记

名词解释题Klenow 片段(Klenow fragment)

填空题Klenow片段(Klenow fragment)具有5ˊ→3ˊ聚合酶活性及()外切酶活性,失去了()外切酶活性。