若类A和类B的定义如下,则上述定义中, 是非法的表达式。 class A { int i,j; public: void get(); //… }; class B : A //默认为私有派生 { int k; public: void make(); //… }; void B :: make() { k=i*j;}A.void get();B.int k;C.void make();D.k=i*j;

若类A和类B的定义如下,则上述定义中, 是非法的表达式。 class A { int i,j; public: void get(); //… }; class B : A //默认为私有派生 { int k; public: void make(); //… }; void B :: make() { k=i*j;}

A.void get();

B.int k;

C.void make();

D.k=i*j;


参考答案和解析
k=i*j;

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