按解释中的要求在下列程序划线处填入的正确语句是:() #include <iostream.h> class Base{ public: void fun() {cout<<"Base::fun"<<endl;} }; class Derived:public Base{ public: void fun() { _______________________//在此空格处调用基类的函数fun() cout<<"Derived::fun"<<endl;} };A.fun();B.Base.fun();C.Base::fun();D.Base->fun();
按解释中的要求在下列程序划线处填入的正确语句是:() #include <iostream.h> class Base{ public: void fun() {cout<<"Base::fun"<<endl;} }; class Derived:public Base{ public: void fun() { _______________________//在此空格处调用基类的函数fun() cout<<"Derived::fun"<<endl;} };
A.fun();
B.Base.fun();
C.Base::fun();
D.Base->fun();
参考答案和解析
A解析:Test类实现了Runnable接口。
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