Which of the following is the main point of the text?［A］ The development of the Internet.［B］ The possibility of space research.［C］ Universal information superhighway.［D］ The technological advances of the Mars mission.
Which of the following is the main point of the text?
［A］ The development of the Internet.
［B］ The possibility of space research.
［C］ Universal information superhighway.
［D］ The technological advances of the Mars mission.
相关考题：
Which of the following best summarizes the main idea of the text?[A] The Internet is posing a threat to publishers.[B] A new mode of publication is emerging.[C] Authors welcome the new channel for publication.[D] Publication is rendered easier by online service.
（ 33 ）下面程序中对一维坐标点类 Point 进行运算符重载#includeusing namespace std;class point {public:point （ int vaI ） {x=val;}point ＆ operator++ （） {x++;retum*this;}print operator++ （ int ） {point ld=*this,++ （ *this ） ;retum old;}int GetX （） const {retum x;}private:int x;};int main （）{point a （ 10 ） ;cout （ ++a ） .GetX （） ;coutA++.GETX （） ;retum （） ;}编译和运行情况是A ）运行时输出 1011B ）运行时输出 1111C ）运行时输出 1112D ）编译有错
下列程序的输出结果为: Ohject id=0 Object id=1 请将程序补充完整。 include us 下列程序的输出结果为：Ohject id=0Object id=1请将程序补充完整。include ＜iostream＞using namespaee std；class Point{public：Point(int xx=0，intyy=0){X=xx；Y=yy；countP++；}～Point( ){countP--；}int GetX( ){return X；}int GetY( ){return Y；}static void GetC( ){ cout＜＜"Object id="＜＜＜countP＜＜endl；}private：int X，Y；static int countP；}；______ //静态数据成员的初始化int main( ){Point::GetC( )；Point A(4，5)；A．GetC( )；return 0；}
使用VC6打开考生文件夹下的工程test17_3，此工程包含一个源程序文件test17_3.cpp，其中定义了用于表示点的类Point和表示内容的类Text以及二者的派生类CircleWithText，但它们的定义并不完整。请按要求完成下列操作，将它们的定义补充完整。(1)定义类Point的构造函数，请使用参数列表的形式将成员函数x和y分别初始化为参数x1和y1的值。请在注释“//**1**。”之后添加适当的语句。(2)完成类Text的构造函数Text(char *str)的定义，将char型的str指向的内容赋值给text并且输出str所指向的内容，请在注释“//**2**”之后添加适当的语句。(3)定义类CircleWithText的构造函数CircleWithText(int cx,int cy,char *msg)，int型的cx和cy用于赋值给x和y，char型的指针*msg用于赋值给text，请在注释“//**3**”之后添加适当的语句。输出结果如下：Point：3 4hello注意：除在指定位置添加语句之外，请不要改动程序中的其他内容。源程序文件test17_3.cpp清单如下：include ＜iostream.h＞include ＜string.h＞class Point{int x,y;public://**1**{cout＜＜"Point:"＜＜x＜＜' '＜＜y＜＜'\n';}～Point(){}};class Text{char text[100];public:Text(char *str){//**2**}～Text () { }};class CircleWithText:public Point,public Text{public://**3**{}～CircleWithText() {}};void main(){CircleWithText cm(3,4,"hello");}
有如下程序:includeusing namespace std;class Point{public: static int number; 有如下程序：#include＜iostream＞using namespace std；class Point{public： static int number；public： Point(){number++；} ～Point(){number--；}}；int Point::number=0；void main(){ Point*ptr； Point A，B； { Point*ptr_point=new Point[3]； ptr=pb_point； } Point C cout＜＜Point::number＜＜endl； delete[]ptr； }运行时输出的结果是A．3B．4C．6D．7
有如下程序: include using namespace std; class Point{ int x, y; public: Point(i 有如下程序：#include＜iostream＞using namespace std;class Point{int x, y;public:Point(int x1=0, int y1=0):x(x1), y(y1){}int get(){return x+y;)};class Circle{Point center;int radius;public:Circle(int CX, int cy, int r):center(cx, cy), radius(r){}int get(){return center. get()+radius;}}；int main(){circle c(3, 4, 5);cout＜＜c. get()＜＜end1;return ():}运行时的输出结果是( )。A) 5B) 7C) 9D) 12A．B．C．D．
下列程序的输出结果为: bjectid=O biectid=1 请将程序补充完整。 include using namesp 下列程序的输出结果为：bjectid=Obiectid=1请将程序补充完整。include＜iostream＞using namespace std;class Point{public:Point(int xx=0,int yy=0){X=xx;Y=yy;countP++;}～Point(){countP--;}int GetX(){return X;}int GetY(){return Y;}static void GetC(){cout＜＜"Object id="＜＜countP＜＜endl;}private:int X,Y;static int countP;};______//静态数据成员的初始化int main(){Point::GetC();Point A(4,5);A.GetC();return 0;}
有以下程序: include using namespace std; class Point' { public: void SetPoint( 有以下程序： #include ＜iostream＞ using namespace std; class Point' { public: void SetPoint(int x,int y); void Move(int xOff,int yOff); int GetX() { return X; } int GetY() { return Y; } private: int X,Y; }; void Point::SetPoint(int x, int y) { X=x; Y=y; } void Point: :Move(int xOff, int yOff) X+=xOff; Y+=yOff; } int main () { Point p1; p1.SetPoint(1,2); p1.Move (5, 6); cout＜＜"Point1 is ("＜＜p1.GetX()＜＜','＜＜p1.GetY()＜＜")"＜＜end1; return 0; } 执行后的输出结果是( )。A．Point1 is (6,8)B．Point1 is (1,2)C．Point1 is (5,6)D．Point1 is (4,4)
有以下程序:includeusingnamespacestd;definePI3.14classPoint{private: intx,y;pub 有以下程序： #include ＜iostream＞ using namespace std； #define PI 3.14 class Point { private： int x，y； public： Point(int a，int b) { x=a； y=b； } int getx() { return x； } int gety() { return y； } }； class Circle ： public Point { private： int r； public： Circle(int a，int b，int c)：Point(a，b) { r=c； } int getr() { return r； } double area() { return PI*r*r； } }； int main() { Circle c1(5，7，10)； cout＜＜cl.area()＜＜endl； return 0； } 程序执行后的输出结果是A．314B．157C．78.5D．153.86
有如下程序:include using namespace std;class point{int x, y;public:point( int v 有如下程序：#include ＜iostream＞using namespace std;class point{ int x, y;public: point( int vx, int vy ) { X=vx; y=vy; } point() { x=0; y=0; } point operator+ ( point p1 ) { point p; int px = x + p1.x; int py = y+ p1.y; return point( px, py ); } point operator-( point p1 { point p; int px = x - p1.x; int py = y - p1.y; return point( px, py ); } void print() { cout＜＜x＜＜","＜＜y＜＜end1; }};int main(){ point p1( 10, 10 ), p2( 20, 20 ); p1 = p1 + p2; p1.print(); return ();}执行后的输出结果是( )。A．10, 10B．20, 20C．10, 20D．30, 30
有如下程序： #inCludeiostream using namespaCe std； Class Point{ publiC： statiC int number； publiC： Point（ ）t．number++；} ~Point（ ）{number--；} }； ， int P0int：：number=0； int main（ ）{ Point *ptr： Point A，B； Point*ptr_point=new Point[3]； ptr=ptr_point；’ } Point C； CoutPoint：：：numberendl； delete[]ptr； return 0； } 执行这个程序的输出结果是（ ）。A.3B.4C.6D.7
有如下程序:include using namespace std;class point{intx,y;public:point( int vx, 有如下程序：#include ＜iostream＞using namespace std;class point{ int x, y;public: point( int vx, int vy ) { x = vx; y = vy; } point ( ) x = 0; y= 0; } point operator+( point p1 ) { point p; int px = x+ p1.x; int py = y + p1.y; return point( px, py ); point operator-( point p1 ) { point p; int px = x -p1.x; int py = y - p1.y; return point ( px, py ); } void print() { cout＜＜x＜＜" , "＜＜y＜＜end1; }};int main (){ point p1(10, 10 ), p2( 20, 20 ); p1 = p1 - p2; p1.print (); return 0;} 执行后的输出结果是A．10，10B．20，20C．10，20D．30，30
A wireless access point supports up to 20 clients. Which of the following describes this wirelessnetwork?() A. MeshB. Point to pointC. Point to multipointD. Ring
有如下程序: include using namespace std; class point {int x,y; public:point( i 有如下程序： #include ＜iostream＞ using namespace std; class point { int x, y; public: point( int vx, int vy ) { x = vx; y = vy; } point ( ) { x = 0; y = 0; } point operator+( point pl ) { point p; int px = x + p1.x; int py = y + p1.y; return point( px, py ); } point operator-( point p1 ) { point p; int px = x - p1.x; int py = y - p1.y; return point( px, py ); } void print() { cout＜＜x＜＜", "＜＜y＜＜end1; } }; int main () { point pl ( 10, 10 ), p2 ( 20, 20 ); p1 = p1 + p2; p1.print (); return 0; } 执行后的输出结果是( )。A．10,10B．20,20C．10,20D．30,30
若有以下程序:include using namespace std;define PI 3.14class Point{private: in 若有以下程序： #include ＜iostream＞ using namespace std; #define PI 3.14 class Point { private: int x,y; public: Point(int a,int b) { x=a; y=b; } int getx() { return x; } int gety() { return y; } }; class Circle : public Point { private: int r; public: Circle(int a, int b,int c) :Point(a,b) { r=c; } int getr() { return r; } double area() { return PI*r*r; } }; int main() { Circle c1(5,7,10); cout＜＜c1.area()＜＜end1; return 0; } 程序执行后的输出结果是( )。A．314B．157C．78.5D．153.86
Which of the following is a suitable pre-listening activity A.Writing a similar text．B.Discussing a relevant picture．C.Writing all the main knowledge about the topic．D.Do some exercises about the difficult vocabulary with the topic．
Which of the following is a suitable pre-listening activity?A．Writing a similar text.B．Discussing a relevant picture.C．Writing all the main knowledge about the topic.D．Note-taking and gap-filling.
Which of the following network topologies BEST describes a VPN? （）(Select TWO)A、Point to PointB、Point to MultipointC、VLAND、RingE、Bus
A wireless access point supports up to 20 clients. Which of the following describes this wirelessnetwork?（）A、MeshB、Point to pointC、Point to multipointD、Ring
Which of the following does not affect security on a wireless access point?（）A、EncryptionB、DHCPC、PasswordD、SSID
You are designing a strategy to ensure that DNS queries always take the most efficient route to get resolved. Which action or actions should you perform？（）A、 Configure conditional forwarding on the corporate DNS servers to point the development DNS servers.B、 Configure conditional forwarding on the development DNS servers to point the corporate DNS servers.C、 Configure conditional forwarding on the perimeter network DNS servers to point the corporate and development DNS servers.D、 Configure forwarding on the corporate and development DNS servers to point the perimeter network DNS servers.E、 Disable root hints on the perimeter network DNS Servers.
单选题Which of the following is most clearly similar to a cline as it is described in the second paragraph of the text?AA vegetable market in which the various items are grouped according to place of origin.BA wheat field in which different varieties of wheat are planted to yield a crop that will bring the maximum profit.CA flower stall in which the various species of flowers are arranged according to their price.DA housing development in which the length of the front struts supporting the porch of each house increases as houses are built up the hill.
单选题Which of the following best states the main point of the text?AThe approach of psychohistorians to historical study is currently in vogue even though it lacks the rigor and verifiability of traditional historical method.BTraditional historians can benefit from studying the techniques and findings of psychohistorians.CAreas of sociological study such as childhood and work are of ~little interest to traditional historians.DThe psychological assessment of an individual’s behavior and attitudes is more informative than the details of his or her daily life.
多选题Which are syntactically valid statement at// point x？（） class Person { private int a； public int change（int m）{ return m； } } public class Teacher extends Person { public int b； public static void main（String arg[]）{ Person p = new Person（）； Teacher t = new Teacher（）； int i； // point x } }Ai = m；Bi = b；Ci = p.a；Di = p.change（30）；Ei = t.b.
单选题Which of the following definitions can be used to define the term ‘offset ’ as a characteristic of controller action?（）AThe period of time in which the set point and the control point coincideBThe periodic change between the set point and the control pointCThe variable difference between the set point and the control pointDThe constant difference between the set point and the control point
单选题Which of the following activities is best for training detailed reading? _____ADrawing a diagram to show the text structureBGiving the text an appropriate titleCTransferring information from the text to a diagramDFinding out all the unfamiliar words