6, 14, 30, 62, ( )A.85B.92C.126 D.250
6, 14, 30, 62, ( )
A.85
B.92
C.126 D
.250
相关考题:
设散列函数为h(k)=kmod7,现欲将关键码23,14,9,6,30,12,18依次散列于地址0~6中,用线性探测法解决冲突,则在地址空间0~6中,得到的散列表是( )。A)14,6,23,9,18,30,12B)14,l8,23,9,30,12,6C)14,12,9,23,30,18,6D)6,23,30,14,18,12,9
The 213.115.77.0 network was subnetted using a /28 subnet mask. How many usable subnets and host addresses per subnet were created as a result of this?A. 2 networks with 62 hostsB. 6 networks with 30 hostsC. 16 networks and 16 hostsD. 62 networks and 2 hostsE. 14 networks and 14 hostsF. None of the above
The 213.115.77.0 network was subnetted using a /28 subnet mask. How many usable subnets and host addresses per subnet were created as a result of this?()A、2 networks with 62 hostsB、6 networks with 30 hostsC、16 networks and 16 hostsD、62 networks and 2 hostsE、14 networks and 14 hostsF、None of the above
单选题The 213.115.77.0 network was subnetted using a /28 subnet mask. How many usable subnets and host addresses per subnet were created as a result of this?()A2 networks with 62 hostsB6 networks with 30 hostsC16 networks and 16 hostsD62 networks and 2 hostsE14 networks and 14 hostsFNone of the above
单选题192.168.1.0/24使用掩码255.255.255.240划分子网,其可用子网数为(),每个子网内可用主机地址数为()A14、14B16、14C254、6D14、62