Among apple, Fuji apple, fruit and food, fruit is the basic level category and the rest are the subordinate categories.() 此题为判断题(对,错)。

Among apple, Fuji apple, fruit and food, fruit is the basic level category and the rest are the subordinate categories.()

此题为判断题(对,错)。


相关考题:

“向fruit表增加一个apple列,其数据类型为15个字符型”的SQL语句是:ALTER TABLE fruit______。

以下关于Python自带数据结构的运算结果中正确的是哪一项? A.l = [1, 2, 3, 4, 5]; del l[2:4]; 则运算之后l为[1,2, 3]。B.basket = ['apple', 'banana', 'apple', 'orange'] ;fruit = set(basket);fruit2 = set(['apple', 'melo']); len(fruit |fruit2) 的结果是5。C.basket = ['apple', 'banana', 'apple', 'orange'] ;fruit = set(basket); len(fruit) 的运算结果是4。D.l = [2, 1, 3, 5, 4]; l.remove(3); l.sort(); 则运算之后l为[1, 2, 4, 5]

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When students learn "apple, orange", the teacher gives students another word "fruit".Which principle doe, s the teacher follow in his/her vocabulary teaching?A.Word-choice principle.B.Presentation principle.C.Culture principle.D.Systematic principle.

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下列语句执行后,di['fruit'][1]值为 。 di={'fruit':['apple','banana','orange']} di['fruit'].append('watermelon')

在MySQL中,将表名food修改为fruit的语句是A.UPDATE TABLE food RENAME TO fruit;B.UPDATE TABLE fruit RENAME TO food;C.ALTER TABLE fruit RENAME TO food;D.ALTER TABLE food RENAME TO fruit;

以下关于Python自带数据结构的运算结果中正确的是哪一项?A..l = [1, 2, 3, 4, 5]; del l[2:4]; 则运算之后l为[1, 2, 3]。#B.basket = ['apple', 'banana', 'apple', 'orange'] ; fruit = set(basket); fruit2 = set(['apple', 'melo']); len(fruit | fruit2) 的结果是5。#C.basket = ['apple', 'banana', 'apple', 'orange'] ; fruit = set(basket); len(fruit) 的运算结果是4。#D.l = [2, 1, 3, 5, 4]; l.remove(3); l.sort(); 则运算之后l为[1, 2, 4, 5]

以下关于Python自带数据结构的运算结果中正确的是哪一项?A.l = [1, 2, 3, 4, 5]; del l[2:4]; 则运算之后l为[1, 2, 3]。#B.l = [2, 1, 3, 5, 4]; l.remove(3); l.sort(); 则运算之后l为[1, 2, 4, 5]。#C.basket = ['apple', 'banana', 'apple', 'orange'] ; fruit = set(basket); len(fruit) 的运算结果是4。#D.basket = ['apple', 'banana', 'apple', 'orange'] ; fruit = set(basket); fruit2 = set(['apple', 'melo']); len(fruit | fruit2) 的结果是5。

以下关于Python自带数据结构的运算结果中正确的是哪一项A.l = [1, 2, 3, 4, 5]; del l[2:4]; 则运算之后l为[1, 2, 3]。#B.basket = ['apple', 'banana', 'apple', 'orange'] ; fruit = set(basket); fruit2 = set(['apple', 'melo']); len(fruit | fruit2) 的结果是5。#C.basket = ['apple', 'banana', 'apple', 'orange'] ; fruit = set(basket); len(fruit) 的运算结果是4。#D.l = [2, 1, 3, 5, 4]; l.remove(3); l.sort(); 则运算之后l为[1, 2, 4, 5]