The adjusted trial balance verifies that total debits equals total credits before the adjusting entries are prepared.() 此题为判断题(对,错)。

The adjusted trial balance verifies that total debits equals total credits before the adjusting entries are prepared.()

此题为判断题(对,错)。


相关考题:

以下代码的运行结果为:public class Calc {public static void main (String args []) {int total = 0;for (int i = 0, j = 10; total >30; ++i, --j) {System.out.println(" i = " + i + " : j = " + j);total += (i + j);}System.out.println("Total " + total);}}A. 产生运行错误B. 产生编译错误C. 输出 "Total 0"D. 产生如下输出:i = 0 : j = 10i = 1 : j = 9i = 2 : j = 8Total 30

下列程序段执行后,输出结果是: def square(x): total = x * x x += total x = -5 total = 0 square(x) print(x, total, sep=',')A.出错B.-5,25C.20,25D.-5,0

定时/计数器T0工作方式1计数时,将计数结果实时读取到参数total中,读取方法为()。请填写正确答案的编号的大写字母。 A. total=TH0+TL0 B. total=TH0-TL0 C.total=TH0*256+TL0 D.total=TL0*256+TH0

下面哪个语句不能完成1到10的累加功能, total初值为0。A.for i in range(10,0):total+=iB.for i in range(1,11):total+=iC.for i in range(10,0,-1):total+=iD.for i in (10,9,8,7,6,5,4,3,2,1):total+=i

若要实现total=1+2+3+4+5求和,以下程序段错误的是()A.int i=1,total=1; while(i<5) { total+=i; i+=1; }B.int i=1,total=0; while(i<=5) { total+=i; i+=1; }C.int i=0,total=0; while(i<5) { i+=1; total+=i; }D.int i=0,total=0; while(i<=5) { total+=i; i+=1; }

34、若要实现total=1+2+3+4+5求和,以下程序段错误的是()A.int i=1,total=1; while(i<5) { total+=i; i+=1; }B.int i=1,total=0; while(i<=5) { total+=i; i+=1; }C.int i=0,total=0; while(i<5) { i+=1; total+=i; }D.int i=0,total=0; while(i<=5) { total+=i; i+=1; }

在total=0前提下,以下for语句中,不能完成1~10的累加功能的是:A.for i in range(10,0): total += iB.for i in range(1,11): total += iC.for i in range(10,0,-1): total +=iD.for i in (10,9,8,7,6,5,4,3,2,1): total +=i

5、以下for语句结构中,_______不能完成1~10的累加功能。A.for i in range(10, 0): total += iB.for i in range(1, 11): total += iC.for i in range(10, 0, -1): total += iD.for i in (10, 9, 8, 7, 6, 5, 4, 3, 2, 1): total += i

定时/计数器T0工作方式1计数时,将计数结果实时读取到参数total中,读取方法为()。 A. total=TH0+TL0 B. total=TH0-TL0 C. total=TH0*256+TL0 D. total=TL0*256+TH0

下列正确的求和语句是()A.total=1B.total+1C.total*1D.total by 1