If a firm has a quick ratio of 1, the subsequent payment of an account payable will cause the ratio to increase.() 此题为判断题(对，错)。
If a firm has a quick ratio of 1, the subsequent payment of an account payable will cause the ratio to increase.()
此题为判断题(对，错)。
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阅读以下技术说明和C代码，将C程序中(1)～(5)空缺处的内容填写完整。[说明]某种传感器的输出值Ratio依赖于环境温度temp(-40℃≤temp≤50℃)。对一组环境温度值(ITEMS个)，已经测量得到了相应的Ratio值(如表4-10表格所示)。表4-10粗略地描述了曲线Ratio(temp)。校正系数K是Ratio的倒数，因此也依赖于环境温度temp。在数据处理中，需要用更多的列表值细致地描述曲线K(temp)，如表4-11所示。在表4-11中，各温度值所对应的K值是对表4-10进行线性插值再求倒数得到的，具体的计算方法如下。1) 根据temp值，在表4-10中用二分法查找；2) 若找到相应的温度值，则按相应的Ratio值求倒数得到K值；3) 若没找到相应的温度值，则可确定temp所在的温度区间[Tp1,Tp2]，同时获得了相应的Ratio1和 Ratio2，再按如下公式计算K值：在程序中，当temp高于50℃或低于-40℃C时，设定K=0。[C程序]includetypedef struct {int Temp; /* 环境温度 */double Ratio; /* 传感器的输出值 */}CURVE;define ITEMS 7double GetK(int Temp,CURVE *p,int n){ /* 用二分法在n个元素的有序表p中查找与Temp对应的传感器输出值 */int low, high, m;double Step;low = 0;high = n-1;if ((Temp＜p-＞Temp) || (Temp＞(p+high)-＞Temp))return 0.0; /* 超出温度范围时返回 0.0 */while (low＜=high){ m=(1);if (Temp==(p+m)-＞Temp)return (2);if (Temp＜(p+m) ＞Temp)high=m-1;elselow=(3);}p+=high;Step=( (4) )/((p+1)-＞Temp-p-＞Temp);return 1.0/ (p-＞Ratio + Step*( (5) ) ;}void main(){ int Degree;double k;CURVE Curve [ITEMS]={{-40,0.2},{-20,0.60.},{-10,0.8},{0,1.0},{10,1.17},{30,1.50},{50,1.8}};printf ("环境温度 校正系数\n");for (Degree=-40;Degree＜=50;Degree++){ k=GetK ( Degree, Curve, ITEMS);printf("%3d %4.2f\n",Degree,k);}}
阅读以下说明和C程序，将应填入(n)处。[说明]某种传感器的输出值Ratio依赖于环境温度temp(-40℃≤temp≤50℃)。对一组环境温度值(ITEMS个)，人们已经测量得到了相应的Ratio值(见表1)。该表粗略地描述了曲线Ratio(temp)。校正系数K是Ratio的倒数，因此也依赖于环境温度temp。在数据处理中，人们需要用更多的列表值细致地描述曲线K(temp)，如表2所示。在表2中，各温度值所对应的K值是对表1进行线性插值再求倒数得到的，具体的计算方法如下：1．根据temp值，在表1中用二分法查找；2．若找到相应的温度值，则按相应的Ratio值求倒数得到K值：3．若没找到相应的温度值，则可确定temp所在的温度区间[Tp1, Tp2]，同时获得了相应的Ratio1和Ratio2，再按如下公式计算K值：Step=(Ratlo1-Ratio2)/(Tp1-Tp2)K=1.0/(Ratio1+Step*(temp-Tp1))在程序中，当temp高于50℃或低于-40℃时，设定K=0。[程序]include ＜stdio.h＞typedef struct {int Temp; /*环境温度*/double Ratio; /*传感器的输出值*/}CURVE;define ITEMS 7double GetK(int, CURVE*, int);void main(){int Degree;double k;CURVE Curve[ITEMS]={ {-40,0.2},{-20,0.60},{-10,0.8},{0,1,0},{10,1.17},{30,1.50}, {50,1.8} };printf("环境温度 校正系数\n");for( Degree= 40; Degree＜=50; Degree++){k=GetK(Degree, Curve, ITEMS);printf(" %3d %4.2f\n",Degree,k);}}double GetK(int Temp, CURVE *p, int n){/*用二分法在n个元素的有序表p中查找与Temp对应的传感器输出值*/int low,high,m; double Step;low=0; high=n-1;if((Temp＜p-＞Temp) ||( Temp＞(p+high)-＞Temp))return 0.0; /*超出温度范围时返回0.0*/while (low＜=high){m=(1) ;if(Temp==(p+m)-＞Temp)return (2);if (Temp＜(p+m)-＞Temp)high=m-1;else low=(3);}p+= high;Step=((4))/((p+1)-＞Temp-p-＞Temp);return 1.0/(p-＞Ratio +Step *((5)));}
You are the administrator of a Windows Server 2003 computer named Testking1.Backups of the System State data of Testking1 occur each day by using the localAdministrator account.A new requirement restricts you from running services by using theAdministrator account. To meet the requirement, you create a new service accountnamed BackupTestking1 to be used for backups. You want this account to have theminimum permissions necessary to perform backups.You need to grant the appropriate permissions to the BackupTestking1 account andto configure the backup job to use the BackupTestking1 account.What should you do?（）A. Add the BackupTestking1 account to the Server Operators group. Modify the backup Scheduled Task to use the BackupTestking1 account.B. Add the BackupTestking1 account to the Backup Operators group. Modify the backup Scheduled Task to use the BackupTesking1 account.C. Add the BackupTestking1 account to the Server Operators group. Modify the Task Scheduler service to use the BackupTestking1 account.D. Add the BackupTestking1 account to the Backup Operators group. Modify the Task Scheduler service to use the BackupTestking1 account.
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RATIO压缩比选择用来确定超过阈值的信号的噪声比。