由于CaCO3固体的分解反应是吸热的,故它的标准摩尔生成焓是负值。
由于CaCO3固体的分解反应是吸热的,故它的标准摩尔生成焓是负值。
相关考题:
在通用声明中定义a,在窗体中添加一个命令按钮Command1,编写如下程序代码:DimaAsIntegerSubtest()a=a+1:b=b+1:c=c+1PrintSub:;a;,;b;,;cEndSubPrivateSubCommand1_Click()a=2:b=3:c=4CalltestCalltestEndSub程序运行后,单击命令按钮,窗体中将显示( )A.Sub:3,4,5Sub:4,5,6B.Sub:2,3,4Sub:2,3,4C.Sub:3,1,1Sub:4,1,1D.Sub:1,1,1Sub:1,1,1
运行以下程序后,输出结果为_____________。 Private Sub Command1_Click() a=1:b=2:c=3 Call test(a,b+3,(c)) Print "main:";a;b;c End Sub Private Function test(p,m,n) p=p+1:m=m+1:n=n+1 Print "sub:";p;m;n End Function:A. sub:2 6 4 main:1 2 3B. sub:2 6 4 main:2 2 3C. sub:2 6 4 main:2 6 4D. sub:2 6 4 main:1 6 4
写出程序运行的结果Public class BasePublic virtual string Hello() {return “Base”;}Public class Sub:BasePublic override string Hello() {return “Sub”;}1. Base b = new Base(); b.Hello;2. Sub s = new Sub(); s.Hello;3. Base b = new Sub (); b.Hello;4. Sub s = new Base(); s.Hello;
在窗体中添加一个命令按钮,编写如下程序:Private Sub Sub1(p,m,n)p=p+1:m=m+1:n=n+1Print "sub1:";p;m;nEnd SubPrivate Sub Command1_Click()a1=1:b=2:c1=3Call Sub1(a,b1+3,c1)Print"Main:";a1;b1;c1End Sub程序运行后,输出结果为A.Sub: 2 6 4 Main: 2 6 4B.Sub: 2 6 4 Main: 2 6 4C.Sub: 2 6 4 Main: 1 2 3D.Sub: 2 6 4 Main: 2 2 3
在某菜单中,有一菜单项(Caption)内容是”NEW”,名字(Name)是“Create”,则单击该菜单项所产生的事件过程应是()。A.Private Sub MnuNEW_Click()B.Private Sub Create_Click()C.Private Sub NEW_Click()D.Sub Mnu_Create_Click()
在窗体中添加一个命令按钮,编写如下程序: Private Sub Sub1(p,m,n) p=p+1:m=m+1:n=n+1 Print "sub1:";p;m;n End Sub Private Sub Command1_Click() a1=1:b=2:c1=3 Call Sub1(a,b1+3,c1) Print"Main:";a1;b1;c1 End Sub 程序运行后,输出结果为A.Sub: 2 6 4 Main: 2 6 4B.Sub: 2 6 4 Main: 2 6 4C.Sub: 2 6 4 Main: 1 2 3D.Sub: 2 6 4 Main: 2 2 3
在某菜单中,有一菜单项(Caption)内容是”NEW”,名字(Name)是“Create”,则单击该菜单项所产生的事件过程应是()。A、Private Sub MnuNEW_Click()B、Private Sub Create_Click()C、Private Sub NEW_Click()D、Sub Mnu_Create_Click()
单选题酶促反应速度(v)达到最大反应速度(Vmax)的80%时,底物浓度[S]为Ap1Ksubm/sub/pBp2Ksubm/sub/pCp3Ksubm/sub/pDp4Ksubm/sub/pEp5Ksubm/sub/p
单选题A pIsub2/sub=Isub3/sub/pB pIsub2/sub=4Isub3/sub/pC pIsub2/sub=2Isub3/sub/pD pIsub3/sub=4Isub2/sub/p
单选题正态分布时,算术平均数、中位数、众数的关系为()Amsub0/sub<msube/sub<(xBmsub0/sub=msube/sub=(xCmsub0/sub>msube/sub>(xDmsube/sub<msub0/sub<(x
单选题( )被称为广义货币。ApMsub0/sub/pBpMsub1/sub/pCpMsub2/sub/pDpMsub3/sub/p