HQL不支持聚合函数有()A、count(*)B、avg(…)C、count(…)D、count(?)
HQL不支持聚合函数有()
- A、count(*)
- B、avg(…)
- C、count(…)
- D、count(?)
相关考题:
count与count(*)的区别是()。 A.无区别B.count是聚合函数,count(*)不是聚合函数C.count统计空格而COUNT(×)不统计D.count(*)统计NULL值,而COUNT不统计
求至少有两个职工的每个仓库的平均工资______。A.SELECT仓库号,COUNT(*),AVG(工资)FROM职工表; HAVINGCOUNT(*)>=2B.SELECT仓库号,COUNT(*),AVG(工资)FROM职工表; GROUPBY仓库号HAVING COUNT(*)>=2C.SELECT仓库号,COUNT(*),AVG(工资)FROM职工表; GROUPBY仓库号SET COUNT(*)>=2D.SELECT仓库号,COUNT(*),AVG(工资)FROM职工表; GROUPBY仓库号WHERE COUNT(*)>=2
检索最少有4名职工仓库的职工平均工资( )。A.SELECT 仓库号,COLINT(*) AS 人数,AVG(工资) AS 平均工资 FROM 职工; GROUP BY 仓库号 WHERE COUNT(*)>=4B.SELECT 仓库号,COUNT(*) AS 人数,AVG(工资) AS 平均工资 FROM 职工; GROUP BY 仓库号 HAVING COUNT(*)>=4C.SELECT 仓库号,COUNT(*) AS 人数,AVG (工资) AS 平均工资 FROM 职工; GROUP BY 职工号 WHERE COUNT(*)>=4D.SEIECT 仓库号,COUNT(*) AS 人数,AVG(工资) AS 平均工资 FROM 职工; GROUP BY 职工号 HAVING COUNT(*)>=4
求至少有两个职工的每个仓库的平均工资A.SELECT 仓库号,COUNT(*),AVG(工资)FROM 职工表;HAVING COUNT(*)=2B.SELECT 仓库号,COUNT(*),AVG(工资)FROM 职工表;GROUP BY 仓库号 HAVING COUNT(*)=2C.SELECT 仓库号,COUNT(*),AVG(工资)FROM 职工表;GROUP BY 仓库号 SET COUNT(*)=2D.SELECT 仓库号,COUNT(*),AVG(工资)FROM 职工表;GROUP BY 仓库号 WHERE COUNT(*)=2
检索最少有4名职工的仓库的职工平均工资( )。A)SELECT仓库号,COUNT(﹡)AS人数,AVG(工资)AS平均工资FROM职工;GROUP BY仓库号WHERE COUNT(﹡)=4B)SELECT仓库号,COUNT(﹡)AS人数,AVG(1资)AS平均工资FROM职工;GROUP BY仓库号HAVING COUNT(﹡)=4C)SELECT仓库号,COUNT(木)AS人数,AVG(工资)AS平均工资FROM职工;GROUP BY职工号WHERE COUNT(﹡)=4D)SELECT仓库号,COUNT(﹡)AS人数,AVG(工资)AS平均工资FROM职工;GROUP BY职工号HAVING COUNT(﹡)=4
count与count(*)的区别是()。A、无区别B、count是聚合函数,count(*)不是聚合函数C、count统计空格而COUNT(×)不统计D、count(*)统计NULL值,而COUNT不统计
单选题count与count(*)的区别是()。A无区别Bcount是聚合函数,count(*)不是聚合函数Ccount统计空格而COUNT(×)不统计Dcount(*)统计NULL值,而COUNT不统计
填空题SQL Server聚合函数有最大、最小、求和、平均和计数等,它们分别是()、avg和count。