单选题Which SQL statement generates the alias Annual Salary for the calculated column SALARY*12?()ASELECT ename, salary*12 ‘Annual Salary’ FROM employees;BSELECT ename, salary*12 “Annual Salary” FROM employees;CSELECT ename, salary*12 AS Annual Salary FROM employees;DSELECT ename, salary*12 AS INITCAP(“ANNUAL SALARY”) FROM employees

单选题
Which SQL statement generates the alias Annual Salary for the calculated column SALARY*12?()
A

SELECT ename, salary*12 ‘Annual Salary’   FROM employees;

B

SELECT ename, salary*12 “Annual Salary”   FROM employees;

C

SELECT ename, salary*12 AS Annual Salary   FROM employees;

D

SELECT ename, salary*12 AS INITCAP(“ANNUAL SALARY”)   FROM employees


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The EMPLOYEE tables has these columns:LAST_NAME VARCHAR2(35)SALARY NUMBER(8,2)COMMISSION_PCT NUMBER(5,2)You want to display the name and annual salary multiplied by the commission_pct for all employees. For records that have a NULL commission_pct, a zero must be displayed against the calculated column.Which SQL statement displays the desired results? ()A. SELECT last_name, (salary * 12) * commission_pct FROM EMPLOYEES;B. SELECT last_name, (salary * 12) * IFNULL(commission_pct, 0) FROM EMPLOYEES;C. SELECT last_name, (salary * 12) * NVL2(commission_pct, 0) FROM EMPLOYEES;D. SELECT last_name, (salary * 12) * NVL(commission_pct, 0) FROM EMPLOYEES;

Examine the description of the EMPLOYEES table:EMP_ID NUMBER(4) NOT NULLLAST_NAME VARCHAR2(30) NOT NULLFIRST_NAME VARCHAR2(30)DEPT_ID NUMBER(2)JOB_CAT VARCHARD2(30)SALARY NUMBER(8,2)Which statement shows the maximum salary paid in each job category of each department? ()A. SELECT dept_id, job_cat, MAX(salary) FROM employees WHERE salary MAX (salary);B. SELECT dept_id, job_cat, MAX(salary) FROM employees GROUP BY dept_id,job_cat;C. SELECT dept_id, job_cat, MAX(salary) FROM employees;D. SELECT dept_id, job_cat, MAX(salary) FROM employees GROUP BY dept_id;E. SELECT dept_id, job_cat, MAX(salary) FROM employees GROUP BY dept _ id job _ cat salary;

Examine the data in the EMPLOYEES table:LAST_NAME DEPARTMENT_ID SALARYGetz 10 3000Davis 20 1500Bill 20 2200Davis 30 5000...Which three subqueries work? () A. SELECT * FROM employees where salary (SELECT MIN(salary) FROM employees GROUP BY department _ id);B. SELECT * FROM employees WHERE salary = (SELECT AVG(salary) FROM employees GROUP BY department _ id);C. SELECT distinct department_id FROM employees Where salary ANY (SELECT AVG(salary) FROM employees GROUP BY department _ id);D. SELECT department_id FROM employees WHERE SALARY ALL (SELECT AVG(salary) FROM employees GROUP BY department _ id);E. SELECT last_name FROM employees Where salary ANY (SELECT MAX(salary) FROM employees GROUP BY department _ id);F. SELECT department_id FROM employees WHERE salary ALL (SELECT AVG(salary) FROM employees GROUP BY ANG (SALARY));

Click the Exhibit button and examine the data in the EMPLOYEES table.Which three subqueries work? () A.SELECT * FROM employees where salary (SELECT MIN(salary) FROM employees GROUP BY department_id);B.SELECT * FROM employees WHERE salary = (SELECT AVG(salary) FROM employees GROUP BY department_id);C.SELECT distinct department_id FROM employees WHERE salary ANY (SELECT AVG(salary) FROM employees GROUP BY department_id);D.SELECT department_id FROM employees WHERE salary ALL (SELECT AVG(salary) FROM employees GROUP BY department_id);E.SELECT last_name FROM employees WHERE salary ANY (SELECT MAX(salary) FROM employees GROUP BY department_id);F.SELECT department_id FROM employees WHERE salary ALL (SELECT AVG(salary) FROM employees GROUP BY AVG(SALARY));

● 设有职工表emp(Eno,Ename,Sex,Age)(Eno为职工号,Ename为职工姓名,Sex为性别,Age为年龄)和salary(Eno,Hour,Month,Wage)(Hour为工作时长为多少小时,Month表示几月份,Wage为薪水),建立一个视图V-Salary(Eno,Ename,Hour,Month,Wage),并按Eno升序排序的SQL语句为:(1)CREATE ( )AS SELECT emp.Eno,emp.Ename ,salary.Hour,salary.Month,salary.WageFROM emp, salaryWHERE emp.Eno=salary.EnoORDER BY ENO在此视图上查均月工资在3000以上的职工工资情况的SQL语句为:SELECT Eno,Ename,AVG(Wage)FROM V-SalaryGROUP BY ( )HAVING AVG(Wage)3000( )A. CREATE TABLE V-Salary(emp.Eno,emp.Ename,salary.Hour,salary.Month,salary.Wage)B. CREATE VIEW V-Salary(Eno,Ename,Hour,Month,Wage)C. CREATE TABLE V-Salary(Eno,Ename,Hour,Month,Wage)D. CREATE INDEX V-Salary(Eno,Ename,Hour,Month,Wage)( )A. Eno B.EnameC.Month D.Wage

下面哪条语句可以取出薪水最高的前三个人:()A、SELECT * FROM (SELECT * FROM EMPLOYEES ORDER BY SALARY );B、SELECT * FROM (SELECT * FROM EMPLOYEES ORDER BY SALARY ) WHERE ROWNUM=3;C、SELECT * FROM (SELECT * FROM EMPLOYEES ORDER BY SALARY DESC) WHERE ROWNUM=3;D、SELECT * FROM EMPLOYEES WHERE ROWNUM=3 ORDER BY SALARY DESC;

The EMPLOYEE tables has these columns: LAST_NAME VARCHAR2(35) SALARY NUMBER(8,2) COMMISSION_PCT NUMBER(5,2) You want to display the name and annual salary multiplied by the commission_pct for all employees. For records that have a NULL commission_pct, a zero must be displayed against the calculated column. Which SQL statement displays the desired results?()A、SELECT last_name, (salary * 12) * commission_pct FROM EMPLOYEES;B、SELECT last_name, (salary * 12) * IFNULL(commission_pct, 0) FROM EMPLOYEES;C、SELECT last_name, (salary * 12) * NVL2(commission_pct, 0) FROM EMPLOYEES;D、SELECT last_name, (salary * 12) * NVL(commission_pct, 0) FROM EMPLOYEES;

Evaluate this SQL statement: SELECT ename, sal, 12* sal+100 FROM emp; The SAL column stores the monthly salary of the employee. Which change must be made to the above syntax to calculate the annual compensation as "monthly salary plus a monthly bonus of $100, multiplied by 12"? ()A、No change is required to achieve the desired results.B、SELECT ename, sal, 12* (sal+100) FROM emp;C、SELECT ename, sal, (12* sal)+100 FROM emp;D、SELECT ename, sal +100,*12 FROM emp;

Management has asked you to calculate the value 12*salary* commission_pct for all the employees in the EMP table. The EMP table contains these columns: LAST NAME VARCNAR2(35) NOT NULL SALARY NUMBER(9,2) NOT NULL COMMISION_PCT NUMBER(4,2) Which statement ensures that a value is displayed in the calculated columns for all employees?()A、SELECT last_name, 12*salary* commission_pct FROM emp;B、SELECT last_name, 12*salary* (commission_pct,0) FROM emp;C、SELECT last_name, 12*salary*(nvl(commission_pct,0)) FROM emp;D、SELECT last_name, 12*salary*(decode(commission_pct,0)) FROM emp;

Examine the description of the EMPLOYEES table: EMP_ID NUMBER(4) NOT NULL LAST_NAME VARCHAR2(30) NOT NULL FIRST_NAME VARCHAR2(30) DEPT_ID NUMBER(2) JOB_CAT VARCHAR2(30) SALARY NUMBER(8,2) Which statement shows the department ID, minimum salary, and maximum salary paid in that department, only of the minimum salary is less then 5000 and the maximum salary is more than 15000?()A、SELECT dept_id, MIN(salary(, MAX(salary) FROM employees WHERE MIN(salary) 5000 AND MAX (salary) 15000;B、SELECT dept_id, MIN(salary), MAX(salary) FROM employees WHERE MIN(salary) 5000 AND MAX(salary) 15000 GROUP BY dept_id;C、SELECT dept_id, MIN(salary), MAX(salary) FROM employees HAVING MIN(salary) 5000 AND MAX (salary) 15000;D、SELECT dept_id, MIN(salary), MAX(salary) FROM employees GROUP BY dept_id HAVING MIN (salary) 5000 AND MAX(salary)E、SELECT dept_id, MIN(salary), MAX(salary) FROM employees GROUP BY dept_id, salary HAVING MIN (salary) 5000 AND MAX (salary) 15000;

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Which SQL statement generates the alias Annual Salary for the calculated column SALARY*12?()A、SELECT ename, salary*12 'Annual Salary' FROM employees;B、SELECT ename, salary*12 "Annual Salary" FROM employees;C、SELECT ename, salary*12 AS Annual Salary FROM employees;D、SELECT ename, salary*12 AS INITCAP("ANNUAL SALARY") FROM employees

Click the Exhibit button and examine the data in the EMPLOYEES table. Which three subqueries work?()A、SELECT * FROM employees where salary (SELECT MIN(salary) FROM employees GROUP BY department_id);B、SELECT * FROM employees WHERE salary = (SELECT AVG(salary) FROM employees GROUP BY department_id);C、SELECT distinct department_id FROM employees WHERE salary ANY (SELECT AVG(salary) FROM employees GROUP BY department_id);D、SELECT department_id FROM employees WHERE salary ALL (SELECT AVG(salary) FROM employees GROUP BY department_id);E、SELECT last_name FROM employees WHERE salary ANY (SELECT MAX(salary) FROM employees GROUP BY department_id);F、SELECT department_id FROM employees WHERE salary ALL (SELECT AVG(salary) FROM employees GROUP BY AVG(SALARY));

Examine the description of the EMPLOYEES table: EMP_ID NUMBER(4) NOT NULL LAST_NAME VARCHAR2(30) NOT NULL FIRST_NAME VARCHAR2(30) DEPT_ID NUMBER(2) JOB_CAT VARCHARD2(30) SALARY NUMBER(8,2) Which statement shows the maximum salary paid in each job category of each department?()A、SELECT dept_id, job_cat, MAX(salary) FROM employees WHERE salary MAX (salary);B、SELECT dept_id, job_cat, MAX(salary) FROM employees GROUP BY dept_id,job_cat;C、SELECT dept_id, job_cat, MAX(salary) FROM employees;D、SELECT dept_id, job_cat, MAX(salary) FROM employees GROUP BY dept_id;E、SELECT dept_id, job_cat, MAX(salary) FROM employees GROUP BY dept _ id job _ cat salary;

Examine the structure of the EMPLOYEES table: EMPLOYEE_ID NUMBER Primary Key FIRST_NAME VARCHAR2(25) LAST_NAME VARCHAR2(25) DEPARTMENT_ID NUMBER SALARY NUMBER What is the correct syntax for an inline view?()A、SELECT a.last_name, a.salary, a.department_id,B、maxsal FROM employees a, (SELECT department_id, max(salary)maxsal FROM employees GROUP BY department_id) b WHERE a.department_id = b.department_id AND a.salary b.maxsal;C、SELECT a.last name, a.salary, a.department_id FROM employees a WHERE a.department_id IN (SELECT department_id FROM employees b GROUP BY department_id having salary = (SELECT max(salary) from employees))D、SELECT a.last_name, a.salary, a.department_id FROM employees a WHERE a.salary = (SELECT max(salary) FROM employees b WHERE a.department _ id = b.department _ id);E、SELECT a.last_name, a.salary, a.department_id FROM employees a WHERE (a.department_id, a.salary) IN (SELECT department_id, a.salary) IN (SELECT department_id max(salary) FROM employees b GROUP BY department_id ORDER BY department _ id);

Examine the data in the EMPLOYEES table: LAST_NAME DEPARTMENT_ID SALARY Getz 10 3000 Davis 20 1500 Bill 20 2200 Davis 30 5000 ... Which three subqueries work? ()A、SELECT * FROM employees where salary (SELECT MIN(salary) FROM employees GROUP BY department _ id);B、SELECT * FROM employees WHERE salary = (SELECT AVG(salary) FROM employees GROUP BY department _ id);C、SELECT distinct department_id FROM employees Where salary ANY (SELECT AVG(salary) FROM employees GROUP BY department _ id);D、SELECT department_id FROM employees WHERE SALARY ALL (SELECT AVG(salary) FROM employees GROUP BY department _ id);E、SELECT last_name FROM employees Where salary ANY (SELECT MAX(salary) FROM employees GROUP BY department _ id);F、SELECT department_id FROM employees WHERE salary ALL (SELECT AVG(salary) FROM employees GROUP BY ANG (SALARY));

单选题Examine the structure of the EMPLOYEES table: EMPLOYEE_ID NUMBER Primary Key FIRST_NAME VARCHAR2(25) LAST_NAME VARCHAR2(25) DEPARTMENT_ID NUMBER SALARY NUMBER What is the correct syntax for an inline view?()ASELECT a.last_name, a.salary, a.department_id,Bmaxsal FROM employees a, (SELECT department_id, max(salary)maxsal FROM employees GROUP BY department_id) b WHERE a.department_id = b.department_id AND a.salary b.maxsal;CSELECT a.last name, a.salary, a.department_id FROM employees a WHERE a.department_id IN (SELECT department_id FROM employees b GROUP BY department_id having salary = (SELECT max(salary) from employees))DSELECT a.last_name, a.salary, a.department_id FROM employees a WHERE a.salary = (SELECT max(salary) FROM employees b WHERE a.department _ id = b.department _ id);ESELECT a.last_name, a.salary, a.department_id FROM employees a WHERE (a.department_id, a.salary) IN (SELECT department_id, a.salary) IN (SELECT department_id max(salary) FROM employees b GROUP BY department_id ORDER BY department _ id);

单选题The EMPLOYEE tables has these columns: LAST_NAME VARCHAR2(35) SALARY NUMBER(8,2) COMMISSION_PCT NUMBER(5,2) You want to display the name and annual salary multiplied by the commission_pct for all employees. For records that have a NULL commission_pct, a zero must be displayed against the calculated column. Which SQL statement displays the desired results?()ASELECT last_name, (salary * 12) * commission_pct FROM EMPLOYEES;BSELECT last_name, (salary * 12) * IFNULL(commission_pct, 0) FROM EMPLOYEES;CSELECT last_name, (salary * 12) * NVL2(commission_pct, 0) FROM EMPLOYEES;DSELECT last_name, (salary * 12) * NVL(commission_pct, 0) FROM EMPLOYEES;

多选题Examine the data in the EMPLOYEES table: Which three subqueries work? ()ASELECT * FROM employees where salary (SELECT MIN(salary) FROM employees GROUP BY department _ id);BSELECT * FROM employees WHERE salary = (SELECT AVG(salary) FROM employees GROUP BY department _ id);CSELECT distinct department_id FROM employees Where salary ANY (SELECT AVG(salary) FROM employees GROUP BY department _ id);DSELECT department_id FROM employees WHERE SALARY ALL (SELECT AVG(salary) FROM employees GROUP BY department _ id);ESELECT last_name FROM employees Where salary ANY (SELECT MAX(salary) FROM employees GROUP BY department _ id);FSELECT department_id FROM employees WHERE salary ALL (SELECT AVG(salary) FROM employees GROUP BY ANG (SALARY));

单选题Evaluate these two SQL statements: SELECT last_name, salary , hire_date FROM EMPLOYEES ORDER BY salary DESC; SELECT last_name, salary , hire_date FROM EMPLOYEES ORDER BY 2 DESC; What is true about them?()AThe two statements produce identical results.BThe second statement returns a syntax error.CThere is no need to specify DESC because the results are sorted in descending order by default.DThe two statements can be made to produce identical results by adding a column alias for the salary column in the second SQL statement.

单选题Evaluate this SQL statement: SELECT ename, sal, 12*sal+100 FROM emp; The SAL column stores the monthly salary of the employee. Which change must be made to the above syntax to calculate the annual compensation as "monthly salary plus a monthly bonus of $100, multiplied by 12"?()ANo change is required to achieve the desired results.BSELECT ename, sal, 12*(sal+100) FROM emp;CSELECT ename, sal, (12*sal)+100 FROM emp;DSELECT ename, sal+100,*12 FROM emp;

多选题Click the Exhibit button and examine the data in the EMPLOYEES table. Which three subqueries work?()ASELECT * FROM employees where salary (SELECT MIN(salary) FROM employees GROUP BY department_id);BSELECT * FROM employees WHERE salary = (SELECT AVG(salary) FROM employees GROUP BY department_id);CSELECT distinct department_id FROM employees WHERE salary ANY (SELECT AVG(salary) FROM employees GROUP BY department_id);DSELECT department_id FROM employees WHERE salary ALL (SELECT AVG(salary) FROM employees GROUP BY department_id);ESELECT last_name FROM employees WHERE salary ANY (SELECT MAX(salary) FROM employees GROUP BY department_id);FSELECT department_id FROM employees WHERE salary ALL (SELECT AVG(salary) FROM employees GROUP BY AVG(SALARY));

单选题Which SQL statement generates the alias Annual Salary for the calculated column SALARY*12?()ASELECT ename, salary*12 'Annual Salary' FROM employees;BSELECT ename, salary*12 Annual Salary FROM employees;CSELECT ename, salary*12 AS Annual Salary FROM employees;DSELECT ename, salary*12 AS INITCAP(ANNUAL SALARY) FROM employees

单选题Which clause would you use in a SELECT statement to limit the display to those employees whose salary is greater then 5000?()AORDER BY SALARY 5000BGROUP BY SALARY 5000CHAVING SALARY 5000DWHERE SALARY 5000

单选题下面哪条语句可以取出薪水最高的前三个人:()ASELECT * FROM (SELECT * FROM EMPLOYEES ORDER BY SALARY );BSELECT * FROM (SELECT * FROM EMPLOYEES ORDER BY SALARY ) WHERE ROWNUM=3;CSELECT * FROM (SELECT * FROM EMPLOYEES ORDER BY SALARY DESC) WHERE ROWNUM=3;DSELECT * FROM EMPLOYEES WHERE ROWNUM=3 ORDER BY SALARY DESC;

单选题Examine the structure of the EMPLOYEES table: EMPLOYEE_ID NUMBER Primary Key FIRST_NAME VARCHAR2(25) LAST_NAME VARCHAR2(25) DEPARTMENT_ID NUMBER SALARY NUMBER What is the correct syntax for an inline view? ()ASELECT a.last_name, a.salary, a.department_id, b.maxsal FROM employees a, (SELECT department_id, max(salary)maxsal FROM employees GROUP BY department_id) b WHERE a.department_id = b.department_id AND a.salary b.maxsal;BSELECT a.last name, a.salary, a.department_id FROM employees a WHERE a.department_id IN (SELECT department_id FROM employees b GROUP BY department_id having salary = (SELECT max(salary) from employees))CSELECT a.last_name, a.salary, a.department_id FROM employees a WHERE a.salary = (SELECT max(salary) FROM employees b WHERE a.department _ id = b.department _ id);DSELECT a.last_name, a.salary, a.department_id FROM employees a WHERE (a.department_id, a.salary) IN (SELECT department_id, a.salary) IN (SELECT department_id max(salary) FROM employees b GROUP BY department_id ORDER BY department _ id);

多选题Examine the data in the EMPLOYEES table: LAST_NAME DEPARTMENT_ID SALARY Getz 10 3000 Davis 20 1500 Bill 20 2200 Davis 30 5000 ... Which three subqueries work? ()ASELECT * FROM employees where salary (SELECT MIN(salary) FROM employees GROUP BY department _ id);BSELECT * FROM employees WHERE salary = (SELECT AVG(salary) FROM employees GROUP BY department _ id);CSELECT distinct department_id FROM employees Where salary ANY (SELECT AVG(salary) FROM employees GROUP BY department _ id);DSELECT department_id FROM employees WHERE SALARY ALL (SELECT AVG(salary) FROM employees GROUP BY department _ id);ESELECT last_name FROM employees Where salary ANY (SELECT MAX(salary) FROM employees GROUP BY department _ id);FSELECT department_id FROM employees WHERE salary ALL (SELECT AVG(salary) FROM employees GROUP BY ANG (SALARY));