设字符串s1='ABCDEFG',s2='PQRST',则运算s=CONCAT(SUB(s1,2,LEN(s2)),SUB(s1,LEN(s2,2))后的串值为(65)。A.'ABCDEFEF'B.'BCDEFG'C.'BCPQRST'D.'BCQR'

设字符串s1='ABCDEFG',s2='PQRST',则运算s=CONCAT(SUB(s1,2,LEN(s2)),SUB(s1,LEN(s2,2))后的串值为(65)。

A.'ABCDEFEF'

B.'BCDEFG'

C.'BCPQRST'

D.'BCQR'


相关考题:

设串S1='ABCDEFG',S2='PQRST' ,则ConcatStr(SubStr(S1,2,LenStr(S2)),SubStr(S1,LenStr(S2),2))的结果串为()。A.'BCDEF'B.'BCDEFG'C.'BCPQRST'D.'BCDEFEF'

9、已知s1={1,2,3},s2={'1','2','3','4'},则表达式len(s1|s2)的值为:

设串s1=’ABCDEFG’,s2=’PQRST’,函数con(x,y)返回x和y串的连接串,subs(s, i, j)返回串s的从序号i开始的j个字符组成的子串,len(s)返回串s的长度,则con(subs(s1, 2, len(s2)), subs(s1, len(s2), 2))的结果串是()A.BCDEFB.BCDEFGC.BCPQRSTD.BCDEFEF

设串s1=’ABCDEFG’,s2=’PQRST’,函数con (x,y)返回x和y串的连接串,subs(s,i,j)返回串s的从序号i的字符开始的j个字符组成的子串,len(s)返回串s的长度,则con (subs (s1,2,len (s2)), subs (s1,len (s2),2))的结果串是____。A.BCDEFB.BCDEFGC.BCPQRSTD.BCDEFEF

设串s1=‘BCDEFG’,s2=‘PQRST’,函数con(x,y)返回x和y串的连接串,subs(s,I,j)返回串s的从序号i的字符开始的j个字符组成的子串,len(s)返回串s的长度,则con(sub(s1,2,len(s2)),sub(s1,len(s2),2))的结果是A.‘BCDEF’B.‘BCDEFG’C.‘BCPQRST’D.‘BCDEFEF’

设串s1=’ABCDEFG’,s2=’PQRST’,函数con(x,y)返回x和y串的连接串,subs(s, i, j)返回串s的从序号i开始的j个字符组成的子串,len(s)返回串s的长度,则con(subs(s1, 2, len(s2)), subs(s1, len(s2), 2))的结果串是()。A.BCDEFB.BCDEFGC.BCPQRSTD.BCDEFEF

【单选题】设字符串S1=“ABCDEFG”,S2=“PQRST”,则运算:S= Concat(Substr(S1,1,LEN(S2)),Substr(S1,LEN(S2),2));后的串值为()A.BCDEFB.BCDEFGC.BCDPQRSTD.BCDEFFG

已知s1={1,2,3},s2={'1','2','3','4'},则表达式len(s1|s2)的值为:

6、设串s1=’ABCDEFG’,s2=’PQRST’,函数con (x, y) 返回x与y串的连接串,函数subs (s, i, j) 返回串s的从序号i的字符开始的j个字符组成的子串,函数len (s) 返回串s的长度,则con (subs (s1, 2, len (s2)), subs (s1, len (s2), 2)) 的结果串是()A.BCDEFB.BCDEFGC.BCPQRSTD.BCDEFEF