有如下程序: Private Sub Command1_Click() Dim k As Integer,m As Integer Dim op As Integer k=4:m=1 p=PPC(k,m):Print op; p=PPC(k.m):Print op End Sub Private Function PPC(a As Integer,b As Integer) Static m As Integer,i As Integer m=0:i=2 i=i+m+1 m=i+a+b PPC=m End Function 程序运行后,输出的结果为A.4 6B.6 6C.8 8D.10 12

有如下程序: Private Sub Command1_Click() Dim k As Integer,m As Integer Dim op As Integer k=4:m=1 p=PPC(k,m):Print op; p=PPC(k.m):Print op End Sub Private Function PPC(a As Integer,b As Integer) Static m As Integer,i As Integer m=0:i=2 i=i+m+1 m=i+a+b PPC=m End Function 程序运行后,输出的结果为

A.4 6

B.6 6

C.8 8

D.10 12


相关考题:

下列程序中,实现将封装数据类型Integer和基本数据类型int之间的转换,以及Integer,int类型和String类型之间的转换。请将程序补充完整。程序运行结果如下:123456456public class ex7_1{public static void main(String[]args) {Integer intObj;int n;String s;intObj = new Integer(123);n=intObj.__________;System.out.printin(Integer.toString(n));s=new String("456");intObj=Integer._________;System.out.println(intObj.__________);n=Integer.parseInt(s);System.out.println(Integer.toString(n));}}

下列程序的运行结果为______。 #define MS DOS #ifdef MS DOS #define INTEGER SIZE 32 #else #define INTEGER SIZE 16 #endif main () { printf ("integer_size=%d\n", INTEGER_SIZE); }A.integersize=32B.integer_size=16C.integersize=32,integer_size=16D.错误

最小生成树A.Prim算法:procedure prim(v0:integer);varlowcost,closest:array[1..maxn] of integer;i,j,k,min:integer;

C.选择排序:procedure sort;var i,j,k:integer;

D. 冒泡排序procedure bubble_sort;var i,j,k:integer;

E.堆排序:procedure sift(i,m:integer);{调整以i为根的子树成为堆,m为结点总数}var k:integer;

组合的生成(1..n中选取k个数的所有方案)procedure solve(dep,pre:integer);vari:integer;

折半查找function binsearch(k:keytype):integer;var low,hig,mid:integer;

有如下程序。Private Sub Command1_Click()Dim k As Integer, m As IntegerDim op As Integerk=4: m=1op=PPC(k, m) : Print op;op=PPC(k, m) : Print opEnd SubPrivate Function PPC(a As Integer, b As Integer)Static m As Integer, i As Integerm=0: i=2i=i + m + 1m=i + a + bPPC=mEnd Function程序运行后,输出的结果为A.4 6B.6 6C.8 8D.10 12

有如下程序:Private Sub Command1_Click() Dim k As Integer,m As Integer Dim op As Integer k=4:m=1 op:PPC(k,m):Print op; op:PPC(k,m):Print opEnd SubPrivate Function,PPC(a As Integer,b As Integer) Static m As Integer,i As Integer m=0:i=2 i=i+m+1 m=i+a+b PPC=mEnd Function程序运行后,输出的结果为A.4 6B.6 6C.8 8D.10 12