End users are failing to log in to the network.Which command is used on the ERX Edge Router to validate communications with the RADIUS server?() A. test ppp aaaB. test aaa pppC. test radius userD. test user radius
End users are failing to log in to the network.Which command is used on the ERX Edge Router to validate communications with the RADIUS server?()
A. test ppp aaa
B. test aaa ppp
C. test radius user
D. test user radius
相关考题：
Job descriptions are examples of ______communications.A upwardB downwardC horizontalD diagonalE None of the above
在路由器的“Router(confi9—if)#”模式下，执行命令end将切换到 (60) 模式。 A．Router B．Router#C．Router(config)#D．Router(confi9—line)#
一台Cisco路由器某接口的IP地址是192.168.2.110,要在该路由器上配置NTP服务,并将其指定为NTP服务器,需要使用()命令。 A.Router（config）#server192.168.2.110B.Router（config）#ntp serverC.Router（config）#master192.168.2.110D.Router（config）#ntp master
在缺省配置下,普通用户登录到Windows 2000 Professional中和Windows 2000 Server中后分别所在的组为() A.Users，UsersB.Power Users，Power UsersC.Users，Power UsersD.Power Users，Users
阅读以下说明和C++程序，将应填入(n)处的字句写在对应栏内。【说明】以下程序的功能是计算正方体、球体和圆柱体的表面积和体积并输出。程序由4个类组成：类cube、sphere和cylinder分别表示正方体、球体和圆柱体；抽象类 container为抽象类，提供了两个纯虚拟函数surface_area()和volum()，作为通用接口。【C++程序】include＜iostream.h＞define pi 3.1416class container｛protected:double radius;public:container(double radius) {container::radius=radius;}virtual double surface_area()=0;virtual double velum()=0;};class cube:(1){ //定义正方体类public:cube(double radius):container(radius){};double surface_area () {return 6 * radius * radius;}double volum() {return radius * radius * radius;}};class sphere:(2){ //定义球体类public:sphere(double radius): container(radius){};double surface_area() { return (3);}double volum() {return pi * radius * radius * radius * 4/3;}};class cylinder:(4){ //定义圆柱体类double height;public:cylinder(double radius,double height):container(radius){container::height=height;}double surface_are a () { return 2 * pi * radius * (height+radius); }double volum () {return (5);}};void main(){container * p;cube obj1 (5);sphere obj2(5);cylinder obj3(5,5);p=obj1;cout＜＜“正方体表面积”(＜＜p-＞surface_area()＜＜end1;cont＜＜“正方体体积”＜＜p-＞volume()＜＜end1;p=obj2;cout＜＜“球体表面积”＜＜p-＞surface_area()＜＜end1;cout＜＜“球体体积”＜＜p-＞volume()＜＜end1;p=obj3;cout＜＜“球体表面积”＜＜p-＞surface_area()＜＜end1;cout＜＜“球体体积”＜＜p-＞volume()＜＜end1;}
下列程序中，先声明一个圆类circle和一个桌子类table，另外声明一个圆桌类roundtable，它是由 circle和table两个类派生的，要求声明一个圆桌类对象，并输出圆桌的高度，面积和颜色。请填空完成程序include＜iostream.h＞include＜string.h＞class circle{double radius；public：circle(double r){radius=r；}double get_area(){return 3.416*radius*radius；}}；class table{double height；public：table(double h)＜height=h；}double get_height(){return height；}}；class roundtable：public table，public circle{char *color;public：roundtable(double h，double r，char c[])： 【 】 {color=new char[strlen(c) +1]；【 】；}；char*get_color(){return color；}}：void main(){roundtable rt(0.8，1.0，“白色”);cout＜＜"圆桌的高:"＜＜rt. get_height()＜＜end1;cout＜＜"圆桌面积:"＜＜rt.get_area()＜＜end1;cout＜＜"圆桌颜色:"＜＜n.get color()＜＜end1;}
Refertotheexhibit.WhichofthefollowingIOSDHCPconfigurationstatementsisrequiredsothataCiscoskinny－basedIPphonecanconnectwithCallManager?() A.ipdhcppoolClientB.network10.1.1.0255.255.255.240C.default-router10.1.1.1D.dns-server10.2.2.2E.domain-namecisco.comF.option150ip10.3.3.3
14、下列哪个是正确的Maven生命周期中阶段的顺序。A．verify-compile-test-package-validateB．validate-compile-test-package-verifyC．validate-compile-test-verify-packageD．verfify-validate-compile-test-package