有以下程序includevoid main(){char s[]={"01aXy"};int i,n=0;for(i=0;s[i]!=0;i++)if 有以下程序 #include<stdio.h> void main() { char s[]={"01aXy"};int i,n=0; for(i=0;s[i]!=0;i++) if(s[i]<='a's[i]>='z')n++; printf("%d\n",n); } 程序运行后的输出结果是( )。A.0B.2C.3D.5

有以下程序includevoid main(){char s[]={"01aXy"};int i,n=0;for(i=0;s[i]!=0;i++)if

有以下程序 #include<stdio.h> void main() { char s[]={"01aXy"};int i,n=0; for(i=0;s[i]!=0;i++) if(s[i]<='a'&&s[i]>='z')n++; printf("%d\n",n); } 程序运行后的输出结果是( )。

A.0

B.2

C.3

D.5


相关考题:

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有以下程序:include main ( ){ inti=0.s=0;for(;;) if( i = = 3 ‖ i = = 5 ) continu 有以下程序: #include <stdio. h> main ( ) { inti=0.s=0; for(;;) if( i = = 3 ‖ i = = 5 ) continue; if (i ==6) break; i++; s+ =i; } printf(" % d \n" ,s);程序运行后的输出结果是( )。A.10B.13C.21D.程序进入列循环

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有以下程序includeincludevoidfun(char*s[],intn){char*t;int i,j;for(i=0 有以下程序 #include <stdio.h> #include <string.h> void fun(char *s[],int n) { char *t; int i,j; for(i=0;i<n-1;++) for(j=i+1;j<n;j++) if(strlen(s[i])>strlen(s[j])) {t=s[i];s[i];s[j];s[j]=t;} } main() { char *ss[]={"bccA.xy,aaaaccB.aaaacc,xyC.bcc,aabccD.aabcc,bcc

有以下程序:includeinclude"string.h"void fun(char*s[],int n){char*t;int i,j;for( 有以下程序: #include<stdio.h> #include"string.h" void fun(char*s[],int n) { char*t;int i,j; for(i=0;i<n-1;i++) for(j=i+1;j<n;j++) if(strlen(s[i])>strlen(s[j])){t=s[i];s[i]=s[j];s[j]=t;} } main() { char*ss[]={"bee","bbcc","xy","aaaacc","aabcc"}; fun(ss,5);printf("%s,%s\n",ss[0],ss[4]); } 程序的运行结果是( )。A.xy,aaaaccB.aaaacc,xyC.bcc,aabccD.aabcc,bcc

有以下程序includeincludevoidfun(char,*s[],intn){char*t;inti,j; for(i= 有以下程序 #include <stdio.h> #include <string.h> void fun(char,*s[],int n) { char *t; int i,j; for(i=0;i<n-1;i++) for(j=i+1;j<n;j++) if(strlen(s[i])>strlen(s[j])) {t=s[i];s[i]:s[j];s[j]=t;} } main() { char *ss[]={"bcc","bbcc","xy","aaaacc","aabcc"}; fun(ss,5); printf("%s,%s\n",ss[0],ss[4]); } 程序的运行结果是A.xy,aaaaccB.aaaacc,xyC.bcc,aabccD.aabcc,bcc

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