YouareimplementinganASP.NETMVC2Webapplicationthatcontainsthefollowingclass.YoucreateastronglytypedviewthatdisplaysdetailsforaDepartmentinstance.Youwanttheviewtoalsoincludealistingofdepartmentemployees.YouneedtowriteacodesegmentthatwillcalltheListEmployeesactionmethodandoutputtheresultsinplace.Whichcodesegmentshouldyouuse?()A.%=Html.Action(ListEmployees,Model)%B.%=Html.ActionLink(ListEmployees,Department,DepartmentController)%C.%Html.RenderPartial(ListEmployees,Model);%D.%=Html.DisplayForModel(ListEmployees)%
Examine the structure of the EMPLOYEES and DEPARTMENTS tables: EMPLOYEESColumn name Data type RemarksEMPLOYEE_ID NUMBER NOT NULL, Primary KeyEMP_NAME VARCHAR2 (30)JOB_ID VARCHAR2 (20)SALARY NUMBERMGR_ID NUMBER References EMPLOYEE_ID COLUMNDEPARTMENT ID NUMBER Foreign key to DEPARTMENT ID column of the DEPARTMENTS tableDEPARTMENTSColumn name Data type RemarksDEPARTMENT_ID NUMBER NOT NULL, Primary Key DEPARTMENT_NAME VARCHAR2(30)MGR_ID NUMBER References MGR_ID column of the EMPLOYEES tableEvaluate this SQL statement:SELECT employee_id, e.department_id, department_name, salaryFROM employees e, departments dWHERE e. department_id = d.department_id;Which SQL statement is equivalent to the above SQL statement? ()A. SELECT employee_id, department_id, department_name, salary FROM employees WHERE department_id IN (SELECT department_id FROM departments);B. SELECT employee_id, department_id, department_name, salary FROM employees NATURAL JOIN departments;C. SELECT employee_id, d.department_id, department_name, salary FROM employees e JOIN departments d ON e.department _ id = d. department_id;D. SELECT employee_id, department_id, department_name, Salary FROM employees JOIN departments USING (e.department_id, d.department_id);
ExhibitExamine the data in the EMPLOYEES and DEPARTMENTS tables.You want to retrieve all employees‘ last names, along with their manager‘s last names and their department names. Which query would you use?()A. SELECT last_name, manager_id, department_name FROM employees e FULL OUTER JOIN department d ON (e.department_id = d.department_id);B. SELECT e.last_name, m.last_name, department_name FROM employees e LEFT OUTER JOIN employees m on ( e.managaer_id = m.employee_id) LEFT OUTER JOIN department d ON (e.department_id = d.department_id);C. SELECT e.last_name, m.last_name, department_name FROM employees e RIGT OUTER JOIN employees m on ( e.manager_id = m.employee_id) FULL OUTER JOIN department d ON (e.department_id = d.department_id);D. SELECT e.last_name, m.last_name, department_name FROM employees e LEFT OUTER JOIN employees m on ( e.manager_id = m.employee_id) RIGT OUTER JOIN department d ON (e.department_id = d.department_id);E. SELECT e.last_name, m.last_name, department_name FROM employees e RIGHT OUTER JOIN employees m on ( e.manager_id = m.employee_id) RIGHT OUTER JOIN departments d ON (e.department_id = d.department_id)F. SELECT last_name, manager_id, department_name FROM employees e JOIN department d ON (e.department_id = d.department_id);
Examine the data in the EMPLOYEES and DEPARTMENTS tables.EMPLOYEESLAST_NAME DEPARTMENT_ID SALARYGetz 10 3000Davis 20 1500Bill 20 2200Davis 30 5000Kochhar 5000DEPARTMENTSDEPARTMENT_ID DEPARTMENT_NAME10 Sales20 Marketing30 Accounts40 AdministrationYou want to retrieve all employees, whether or not they have matching departments in the departments table.Which query would you use?()A. SELECT last_name, department_name FROM employees , departments(+);B. SELECT last_name, department_name FROM employees JOIN departments(+);C. SELECT last_name, department_name ON (e. department_ id = d. departments_id); FROM employees(+) e JOIN departments dD. SELECT last_name, department_name FROM employees e RIGHT OUTER JOIN departments d ON (e.department_id = d.department_id);E. SELECT last_name, department_name FROM employees(+) , departments ON (e. department _ id = d. department _id);F. SELECT last_name, department_name FROM employees e LEFT OUTER JOIN departments d ON (e. department _ id = d. department _id);
Click the Exhibit button and examine the data in the EMPLOYEES and DEPARTMENTS tables.You want to retrieve all employees‘ last names, along with their managers‘ last names and their department names. Which query would you use?()A.SELECT last_name, manager_id, department_name FROM employees e FULL OUTER JOIN departments d ON (e.department_id = d.department_id);B.SELECT e.last_name, m.last_name, department_name FROM employees e LEFT OUTER JOIN employees m on ( e.manager_id = m.employee_id) LEFT OUTER JOIN departments d ON (e.department_id = d.department_id);C.SELECT e.last_name, m.last_name, department_name FROM employees e RIGHT OUTER JOIN employees m on ( e.manager_id = m.employee_id) LEFT OUTER JOIN departments d ON (e.department_id = d.department_id);D.SELECT e.last_name, m.last_name, department_name FROM employees e LEFT OUTER JOIN employees m on ( e.manager_id = m.employee_id) RIGHT OUTER JOIN departments d ON (e.department_id = d.department_id);E.SELECT e.last_name, m.last_name, department_name FROM employees e RIGHT OUTER JOIN employees m on ( e.manager_id = m.employee_id) RIGHT OUTER JOIN departments d ON (e.department_id = d.department_id);F.SELECT last_name, manager_id, department_name FROM employees e JOIN departments d ON (e.department_id = d.department_id) ;
WhichcommandwouldcreateamachineaccountinActiveDirectoryundertheComputers\BusinessUnit\Department\Serversorganizationalunit?() A.netrpcjoin-mlocalhost-ldap=ldap.ldapserver.comComputers\BusinessUnit\Department\ServersB.rpcclient-cjoinComputers\BusinessUnit\Department\ServersC.netadsjoinou=Computers\BusinessUnit\Department\ServersD.netadsjoinComputers\BusinessUnit\Department\Servers
Asystemadministratorhasbeenaskedtomigratethedev_vgvolumegroupfromserverAtoserverB.Thedev_vgvolumegroupcontainsasinglefilesystemnamed"/development".Toprepareformigration,whichofthefollowingisthecorrectsequenceofcommandsforremovingthevolumegroupfromserverA?()A.exportvgdev_vg;umount/development;varyoffvgdev_vgB.varyoffvgdev_vg;umount/development;exportvgdev_vgC.umount/development;exportvgdev_vg;varyoffvgdev_vgD.umount/development;varyoffvgdev_vg;exportvgdev_vg
AcustomerhastenRS/6000ModelM80,twopSeries690Model681,fivePOWER5510andtwoPOWER6560machinesinstalledandrunningcommercialapplications.TheywanttodoaserverconsolidationstudyinordertoreplacetheexistingsystemswithPOWER7systems.Whatperformancemetricisrecommendedwhenevaluatingthereplacementsystem?()A.IBMCPWB.IBMrPerfC.SPECint_rate2006D.IDEASInternationalRPE2
There is no question that computer applications such as(71), electronic mail, and(72)publishing have changed the way people work. These computer applications have enhanced users capacity for communication and have improved their productivity. The success of these applications has prompted both vendors and researchers to continue to seek new ways to further advance the information technology revolution. Enter the latest innovation: networked(73)systems. They convey information in multiple(74): text, graphics, video, audio,(75), computer simulations, and so forth. Advocates of these systems argue that they are the next logical step in human communication; however, modifying our current networks to accommodate the variety of media will present significant technical difficulties.A.word transactionB.word processingC.word disposalD.word dealing
Software engineering is the study and an application of engineering to the design,development,and(71)of software.A.maintenance B.serviceC.runningD.deployment