To help with this ________, the yogurt shop TCBY has been creative to sell yogurt as well as low-fat ice cream. A.practiceB.personC.reasonD.problem

To help with this ________, the yogurt shop TCBY has been creative to sell yogurt as well as low-fat ice cream.

A.practice

B.person

C.reason

D.problem


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已知在文件IN. dat中存有100个产品销售记录,每个产品销售记录由产品代码code(字符型4位)、产品名称name(字符型10位)、单价uprice(整型)、数量amount(整型)、金额sum(长整型)5部分组成。其中:金额=单价×数量。函数Rdata()是读取这100个销售记录并存入结构数组sell中。请编写函数SortDat(),其功能要求:按金额从小到大进行排列,若金额相等,则按产品代码从小到大进行排列,最终排列结果仍存入结构数组sell中。最后调用函数Wdata(),把结果输出到OUT. dat文件中。注意:部分源程序已经给出。请勿改动主函数main()、读数据函数Rdata()和输出数据函数Wdata()的内容。include <stdio. h>include <string. h>include <conio. h>include <stdlib. h>define MAX 100typedef struct{ char code[5]; /* 产品代码 */char name[11]; /* 产品名称 */int uprice; /* 单价 */int amount; /* 数量 */long sum; /* 金额 */} PRO;PRO sell [MAX];void Rdata();void Wdata();void SortDat(){}void main (){ memset(sell, 0, sizeof(sell)Rdata();SortDat();Wdata();}void Rdata(){ FILE *fp;char str[80], ch[11];int i;fp = fopen("IN. dat", "r");for (i=0; i<100; i++){ fgets(str, 80, fp);memcpy(sell[i].code, str, 4);memcpy(sell[i].name, str+4, 10);memcpy(ch, str+14, 4);ch[4] = 0;sell[i].uprice = atoi(ch);memcpy(ch, str+18, 5);ch[5] = 0;sell[i]. amount = atoi(ch);sell[i].sum = (long)sell[i]. uprice * sell[i]. amount;}fclose(fp);}void Wdata(){ FILE *fp;int i;fp = fopen("OUT. dat", "w");for (i=0; i<100; i++){ printf("%s %s %4d %5d %5d\n", sell[i]. code, sell[i].name,sell[i].uprice, sell[i]. amount, sell[i]. sum);fprintf(fp, "%s %s %4d %5d %5d\n", sell[i]. code,sell[i]. name, sell[i]. uprice, sell[i]. amount, sell[i]. sum);}fclose(fp);}

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