char（n）和varchar（n）的区别是什么？其中n的含义是什么？各占用多少空间？
char（n）和varchar（n）的区别是什么？其中n的含义是什么？各占用多少空间？
相关考题：
假定一个函数的二维数组参数说明为char w[][N],与之等价的指针参数说明为()。 A. char (*w)[N]B. char *w[N]C. char (*w)ND. char**a
有以下程序include stdio.hint fun(char s[]){ int n=0;while(*s='9'stdio.hint fun(char s[]){ int n=0;while(*s='9'*s='0') {n=10*n+*s-'0';s++;}return(n);}main(){ char s[10]={ '6', '1', '*', '4', '*', '9', '*', '0', '*'};printf("%d\n",fun(s));}程序运行的结果是A ) 9B ) 61490C ) 61D ) 5
以下结构体类型说明和变量定义中正确的是A)typedef struct{int n; char c;} REC;REC t1,t2;B)struct REC;{int n; char c;};REC t1,t2;C)typedef struct REC ;{int n=0; char c='A';} t1,t2D)struct{int n;char c;}REC;REC t1,t2;
以下程序中函数 fun 的功能是：统计 person 所指结构体数组中所有性别 (sex) 为 M 的记录的个数 ， 存入变量 n 中，并做为函数值返回。请填空：#include stdio.h#define N 3typedef struct{ int num;char nam[10]; char sex;} SS;int fun(SS person[]){ int i,n=0;for(i=0;iN;i++)if( 【 14 】 =='M') n++;return n;}main(){ SS W[N]={{1, "AA", 'F'},{2, "BB",'M'},{3,"CC", 'M'}}; int n;n=fun(W); printf("n=%d\n",n);}
●试题一阅读下列函数说明和C代码，把应填入其中n处的字句写在答卷的对应栏内。【函数1．1说明】函数strcpy(char*to，char*from)将字符串from复制到字符串to。【函数1．1】void strcpy(char*to，char*from){while( ( 1 ) )；}【函数1．2说明】函数merge(int a［ ］，int n，int b［ ］，int m，int *c)是将两个从小到大有序数组a和b复制合并出一个有序整数序列c，其中形参n和m分别是数组a和b的元素个数。【函数1．2】void merge(int a［ ］，int n，int b［ ］，int m，int *c){ int i，j；for(i=j=0；i＜n j＜m；)*c++=a［i］＜b［j］? a［i++］:b［j++］；while( (2) )*c++=a［i++］；while( (3) )*c++=b［j++］；}【函数1．3说明】递归函数sum(int a［ ］，int n)的返回值是数组a［ ］的前n个元素之和。【函数1．3】int sum(int a［ ］，int n){ if(n＞0)return (4) ；else (5) ；}
若有以下说明和语句：sturct st { int n;char *ch;}; struct st a[3]={5, "abc",7, "def",9, "ghk"},*p=a;则值为6的表达式是（ ）。A）p++-n B）p-n++C）(*p).n++ D）++p-n
以下结构体类型说明和变量定义中正确的是( )。A．typedef structB．struct REC; {int n；char c；}REC； {int n；char c；}； REC t1，t2； REC t1，t2；C．typedef struct REC;D．struct {int n=0；char c='A'；}t1，t2； {int n；char c；}REC； REC t1,t2；
有以下程序: include using namespace std; constxntN=5; int fun(char*s,char a,int 有以下程序：include ＜iostream＞using namespace std；const xnt N=5；int fun(char *s，char a，int n){int j；*s=a；j=n；while(a＜s[j])j--；return j；}int main(){char s[N+1]；int k；
请补充函数fun()，该函数的功能是：返回字符数组中指定子符的个数，指定字符从键盘输入。注意：部分源程序给出如下。请勿改动主函数main和其他函数中的任何内容，仅在函数fun()的横线上填入所编写的若干表达式或语句。试题程序：include ＜stdio.h＞define N 80int fun (char s[],char ch){int i=0, n=0;while(【 】){if(【 】)n++;i++;}【 】;}main ( ){int n;char str[N], ch;clrscr ();printf ("\nInput a string: \n");gets (str);printf ("\nInput a charactor: \n" ;scanf ("%c", ch);n=fun (str, ch);printf("\nnumber of %c:%d", ch, n);}
以下程序运行后的输出结果是( )。main(){char c；int n=100；loat f=10；double x；x=f*=n/=(c=50)；printf("%d%f\n",n,x)；}
str为一个字符序列。请补充函数fun()，该函数的功能是：查找str中值为x的元素，返回该字符序列中值为x的元素个数，并把这些值为x的元素下标依次保存在数组bb中。例如，在“abcdefahij”中查找‘a’，结果为：2个‘a’，下标依次为 0、6。注意：部分源程序给出如下。请勿改动主函数main和其他函数中的任何内容，仅在函数fun()的横线上填入所编写的若干表达式或语句。试题程序：include＜stdio.h＞include＜conio.h＞define N 20int bb[N];int fun(char *str,char ch){int i=0, n=0;char t=ch;char *p=str;while(*p){if (【 】)【 】;p++;i++;}return【 】;}main(){char str[N];char ch;int i, j,n;clrscr();printf("***Input the original string***\n");gets(str);printf("***The Original ***\n");puts(str);printf("***Input character ***\n");scanf("%c",ch);n=fun(str,ch);printf("\nThe numbr of character is:%d\n", n);printf{"***The suffix of character***\n");for(i=0;i＜n;i++)printf("%d ",bb[i]);}
请编写一个函数char *fun(char *s，int n)。函数fun()的功能是将字符串s中的字符“循环左移”n位。例如，输入“ABCDE”，则循环左移2位应输出“CDEAB”，输入“1234567”，循环左移3位应输出“4567123”。注意：部分源程序已存在文件PROC13.cpp中。请勿修改主函数和其他函数中的任何内容，仅在函数fun()的花括号中填写若干语句。文件PROC13.cpp的内容如下：//PROC13.cppinclude ＜iostream＞include ＜string＞using namespace std；char *fun(char *s，int n)；int main(){char str[81]；int n；cout＜＜"Enter a string(less than 80 char)\n”；cin＞＞str；cout＜＜"\n Enter n："；cin＞＞n；if(n＞strlen(str)){cout＜＜"\n Data overflow"；return 0；}cout＜＜"The result is: "＜＜fun(str，n)＜＜end1；return 0；}char *fun(char*s，int n){//* * * * * *}
以下程序的输出结果是()。includevoid func(char**m) {＋＋m:cout 以下程序的输出结果是( )。 #include＜iostream.h＞ void func(char**m) { ++m： cout＜＜*m＜＜endl； } void main() { static char*a[]={"MORNING","AFTERTOON","EVENING"}； char**n； n=a： func(n)； }A．为空B．MORNINGC．AFTERTOOND．EVENING
执行下列程序段,结果是includevoid main( ){int x=40; char y='C'; int n;?n=(x char y＝'C'; int n; ? n＝(x0) xff) (y＞'B') ; cout ＜ ＜ n;}A．0B．1C．2D．3
以下程序运行后输入:3,abcde回车,则输出结果是【 】include move(char *str, 以下程序运行后输入：3,abcde回车，则输出结果是【 】include ＜string.h＞move(char *str, int n){ char temp; int i;temp=str[n-1];for(i=n-1;i＞0;i--) str[i]=str[i-1];str[0]=temp;}main( ){ char s[50]; int n, i, z;scanf("%d,%s",n,s);z=strlen(s);for(i=1; i＜=n; i++) move(s, z);printf("%s\n",s);}
char str[ ]= ＂Hello＂;char *p=str;int n=10;sizeof(str)=( )sizeof(p)=( )sizeof(n)=( )void func(char str[100]){ }sizeof(str)=( )
有以下程序include using namespace std:class Base{private:char c;public:Base(cha 有以下程序#include ＜iostream＞using namespace std:class Base{private: char c;public: Base(char n) :c(n) {} ～Base ( ) { cout＜＜c; }}; class Derived : public Base{private: char c;public: Derived(char n):Base (n+1),c(n) {} ～Derived() { cout＜＜c; }};int main(){ Derived obj('x'); return 0;} 执行后的输出结果是A．xyB．yxC．xD．y
Given the following requirements:Create a table to contain employee data, with a unique numeric identifier automatically assigned when a row is added, has an EDLEVEL column that permits only the values ‘C‘, ‘H‘ and ‘N‘, and permits inserts only when a corresponding value for the employee‘s department exists in the DEPARTMENT table.Which of the following CREATE statements will successfully create this table?（）A.CREATE TABLE emp ( empno SMALLINT NEXTVAL GENERATED ALWAYS AS IDENTITY, firstname VARCHAR(30) NOT NULL, lastname VARCHAR(30) NOT NULL, workdept CHAR(3) NOT NULL, edlevel CHAR(1), PRIMARY KEY emp_pk (empno), FOREIGN KEY emp_workdept_fk ON (workdept) REFERENCES department (deptno), CHECK edlevel_ck VALUES (edlevel IN (‘C‘,‘H‘,‘N‘)), );B.CREATE TABLE emp ( empno SMALLINT NOT NULL GENERATED BY DEFAULT AS IDENTITY, firstname VARCHAR(30) NOT NULL, lastname VARCHAR(30) NOT NULL, workdept CHAR(3), edlevel CHAR(1), CONSTRAINT emp_pk PRIMARY KEY (empno), CONSTRAINT emp_workdept_fk FOREIGN KEY (workdept) REFERENCES department (deptno), CONSTRAINT edlevel_ck CHECK edlevel VALUES (‘C‘,‘H‘,‘N‘) );C.CREATE TABLE emp ( empno SMALLINT NEXTVAL GENERATED BY DEFAULT AS IDENTITY, firstname VARCHAR(30) NOT NULL, lastname VARCHAR(30) NOT NULL, workdept CHAR(3) NOT NULL, edlevel CHAR(1) CHECK IN (‘C‘,‘H‘,‘N‘)), CONSTRAINT emp_pk PRIMARY KEY (empno), CONSTRAINT emp_workdept_fk FOREIGN KEY department (deptno) REFERENCES (workdept) );D.CREATE TABLE emp ( empno SMALLINT NOT NULL GENERATED BY DEFAULT AS IDENTITY, firstname VARCHAR(30) NOT NULL, lastname VARCHAR(30) NOT NULL, workdept CHAR(3), edlevel CHAR(1), CONSTRAINT emp_pk PRIMARY KEY (empno), CONSTRAINT emp_workdept_fk FOREIGN KEY (workdept) REFERENCES department (deptno), CONSTRAINT edlevel_ck CHECK (edlevel IN (‘C‘,‘H‘,‘N‘)) );
有以下程序 include int fun(char s[ ]) { int n=0; while(*s='0 有以下程序#include ＜stdio.h＞int fun(char s[ ]){ int n=0;while(*s＜='9'*s＞='0') {n=10*n+*s-'0';s++;}retum(n);}main( ){ char s[10]={'6','1','*','4','*','9','*','0','*'};printf("%d\n",fun(s));}程序的运行结果是A．9B．61490C．61D．5
有如下程序： #include 〈iostream〉 using namespace std; class Base { private: char c; public: Base(char n) :c(n) {} ～Base ( ) { cout〈〈c; } }; class Derived : public Base { private: char c; public: Derived(char n) :Base(n+1),c(n) { } ～Derived () { cout〈〈c; } }; int main ( ) { Derived obj ('x'); return 0; } 执行上面的程序将输出( )。A．xyB．yxC．xD．y
有以下程序includeusing namespace std;class Base{private:char c;public:Base(char 有以下程序 #include＜iostream＞ using namespace std； class Base { private： char c； public： Base(char n)：c(n){} ～Base() { cout＜＜c； } }； class Derived：public Base { private： char c； public： Derived(char n)：Base(n+1)，c(n){} ～Derived() { cout＜＜c； } }； int main() { Derived obj('x')； return 0； } 执行后的输出结果是A．xyB．yxC．xD．y
Given the following requirements: Create a table to contain employee data, with a unique numeric identifier automatically assigned when a row is added, has an EDLEVEL column that permits only the values 'C', 'H' and 'N', and permits inserts only when a corresponding value for the employee's department exists in the DEPARTMENT table. Which of the following CREATE statements will successfully create this table?（）A、CREATE TABLE emp ( empno SMALLINT NEXTVAL GENERATED ALWAYS AS IDENTITY, firstname VARCHAR(30) NOT NULL, lastname VARCHAR(30) NOT NULL, workdept CHAR(3) NOT NULL, edlevel CHAR(1), PRIMARY KEY emp_pk (empno), FOREIGN KEY emp_workdept_fk ON (workdept) REFERENCES department (deptno), CHECK edlevel_ck VALUES (edlevel IN ('C','H','N')), );B、CREATE TABLE emp ( empno SMALLINT NOT NULL GENERATED BY DEFAULT AS IDENTITY, firstname VARCHAR(30) NOT NULL, lastname VARCHAR(30) NOT NULL, workdept CHAR(3), edlevel CHAR(1), CONSTRAINT emp_pk PRIMARY KEY (empno), CONSTRAINT emp_workdept_fk FOREIGN KEY (workdept) REFERENCES department (deptno), CONSTRAINT edlevel_ck CHECK edlevel VALUES ('C','H','N') );C、CREATE TABLE emp ( empno SMALLINT NEXTVAL GENERATED BY DEFAULT AS IDENTITY, firstname VARCHAR(30) NOT NULL, lastname VARCHAR(30) NOT NULL, workdept CHAR(3) NOT NULL, edlevel CHAR(1) CHECK IN ('C','H','N')), CONSTRAINT emp_pk PRIMARY KEY (empno), CONSTRAINT emp_workdept_fk FOREIGN KEY department (deptno) REFERENCES (workdept) );D、CREATE TABLE emp ( empno SMALLINT NOT NULL GENERATED BY DEFAULT AS IDENTITY, firstname VARCHAR(30) NOT NULL, lastname VARCHAR(30) NOT NULL, workdept CHAR(3), edlevel CHAR(1), CONSTRAINT emp_pk PRIMARY KEY (empno), CONSTRAINT emp_workdept_fk FOREIGN KEY (workdept) REFERENCES department (deptno), CONSTRAINT edlevel_ck CHECK (edlevel IN ('C','H','N')) );