( 难度：中等)在Hive中，以下哪个SQL语句是错误的A.hive＞ SELECT ID, NAME, o.AMOUNT, o.DATE ＞ FROM CUSTOMERS c ＞ LEFT OUTER JOIN ORDERS o ＞ ON (ID = o.CUSTOMER_ID);B.hive＞ SELECT ID, NAME, o.AMOUNT, o.DATE ＞ FROM CUSTOMERS c ＞ RIGHT OUTER JOIN ORDERS o ＞ ON (ID = o.CUSTOMER_ID);C.hive＞ SELECT ID, NAME, o.AMOUNT, o.DATE ＞ FROM CUSTOMERS c ＞ FULL OUTER JOIN ORDERS o ＞ ON (ID = o.CUSTOMER_ID);D.hive＞ SELECT ID, NAME, o.AMOUNT, o.DATE ＞ FROM CUSTOMERS c ＞ FULL OUTER JOIN ORDERS o ＞ ON (ID = o.CUSTOMER_ID OR Name = o.Name);
( 难度：中等)在Hive中，以下哪个SQL语句是错误的
A.hive＞ SELECT ID, NAME, o.AMOUNT, o.DATE
＞ FROM CUSTOMERS c
＞ LEFT OUTER JOIN ORDERS o
＞ ON (ID = o.CUSTOMER_ID);
B.hive＞ SELECT ID, NAME, o.AMOUNT, o.DATE
＞ FROM CUSTOMERS c
＞ RIGHT OUTER JOIN ORDERS o
＞ ON (ID = o.CUSTOMER_ID);
C.hive＞ SELECT ID, NAME, o.AMOUNT, o.DATE
＞ FROM CUSTOMERS c
＞ FULL OUTER JOIN ORDERS o
＞ ON (ID = o.CUSTOMER_ID);
D.hive＞ SELECT ID, NAME, o.AMOUNT, o.DATE
＞ FROM CUSTOMERS c
＞ FULL OUTER JOIN ORDERS o
＞ ON (ID = o.CUSTOMER_ID OR Name = o.Name);
A.hive＞ SELECT ID, NAME, o.AMOUNT, o.DATE
＞ FROM CUSTOMERS c
＞ LEFT OUTER JOIN ORDERS o
＞ ON (ID = o.CUSTOMER_ID);
B.hive＞ SELECT ID, NAME, o.AMOUNT, o.DATE
＞ FROM CUSTOMERS c
＞ RIGHT OUTER JOIN ORDERS o
＞ ON (ID = o.CUSTOMER_ID);
C.hive＞ SELECT ID, NAME, o.AMOUNT, o.DATE
＞ FROM CUSTOMERS c
＞ FULL OUTER JOIN ORDERS o
＞ ON (ID = o.CUSTOMER_ID);
D.hive＞ SELECT ID, NAME, o.AMOUNT, o.DATE
＞ FROM CUSTOMERS c
＞ FULL OUTER JOIN ORDERS o
＞ ON (ID = o.CUSTOMER_ID OR Name = o.Name);
相关考题：
You need to produce a report for mailing labels for all customers. The mailing label must have only the customer name and address. The CUSTOMERS table has these columns:CUST_ID NUMBER(4) NOT NULLCUST_NAME VARCHAR2(100) NOT NULLCUST_ADDRESS VARCHAR2(150)CUST_PHONE VARCHAR2(20)Which SELECT statement accomplishes this task?（）A. SELECT* FROM customers;B. SELECT name, address FROM customers;C. SELECT id, name, address, phone FROM customers;D. SELECT cust_name, cust_address FROM customers;E. SELECT cust_id, cust_name, cust_address, cust_phone FROM customers;
Examine the structure of the EMPLOYEES and DEPARTMENTS tables: EMPLOYEESColumn name Data type RemarksEMPLOYEE_ID NUMBER NOT NULL, Primary KeyEMP_NAME VARCHAR2 (30)JOB_ID VARCHAR2 (20)SALARY NUMBERMGR_ID NUMBER References EMPLOYEE_ID COLUMNDEPARTMENT ID NUMBER Foreign key to DEPARTMENT ID column of the DEPARTMENTS tableDEPARTMENTSColumn name Data type RemarksDEPARTMENT_ID NUMBER NOT NULL, Primary Key DEPARTMENT_NAME VARCHAR2(30)MGR_ID NUMBER References MGR_ID column of the EMPLOYEES tableEvaluate this SQL statement:SELECT employee_id, e.department_id, department_name, salaryFROM employees e, departments dWHERE e. department_id = d.department_id;Which SQL statement is equivalent to the above SQL statement? （）A. SELECT employee_id, department_id, department_name, salary FROM employees WHERE department_id IN (SELECT department_id FROM departments);B. SELECT employee_id, department_id, department_name, salary FROM employees NATURAL JOIN departments;C. SELECT employee_id, d.department_id, department_name, salary FROM employees e JOIN departments d ON e.department _ id = d. department_id;D. SELECT employee_id, department_id, department_name, Salary FROM employees JOIN departments USING (e.department_id, d.department_id);
ExhibitExamine the data in the EMPLOYEES and DEPARTMENTS tables.You want to retrieve all employees‘ last names, along with their manager‘s last names and their department names. Which query would you use?（）A. SELECT last_name, manager_id, department_name FROM employees e FULL OUTER JOIN department d ON (e.department_id = d.department_id);B. SELECT e.last_name, m.last_name, department_name FROM employees e LEFT OUTER JOIN employees m on ( e.managaer_id = m.employee_id) LEFT OUTER JOIN department d ON (e.department_id = d.department_id);C. SELECT e.last_name, m.last_name, department_name FROM employees e RIGT OUTER JOIN employees m on ( e.manager_id = m.employee_id) FULL OUTER JOIN department d ON (e.department_id = d.department_id);D. SELECT e.last_name, m.last_name, department_name FROM employees e LEFT OUTER JOIN employees m on ( e.manager_id = m.employee_id) RIGT OUTER JOIN department d ON (e.department_id = d.department_id);E. SELECT e.last_name, m.last_name, department_name FROM employees e RIGHT OUTER JOIN employees m on ( e.manager_id = m.employee_id) RIGHT OUTER JOIN departments d ON (e.department_id = d.department_id)F. SELECT last_name, manager_id, department_name FROM employees e JOIN department d ON (e.department_id = d.department_id);
Examine the data in the EMPLOYEES and DEPARTMENTS tables.EMPLOYEESLAST_NAME DEPARTMENT_ID SALARYGetz 10 3000Davis 20 1500Bill 20 2200Davis 30 5000Kochhar 5000DEPARTMENTSDEPARTMENT_ID DEPARTMENT_NAME10 Sales20 Marketing30 Accounts40 AdministrationYou want to retrieve all employees, whether or not they have matching departments in the departments table.Which query would you use?（）A. SELECT last_name, department_name FROM employees , departments(+);B. SELECT last_name, department_name FROM employees JOIN departments(+);C. SELECT last_name, department_name ON (e. department_ id = d. departments_id); FROM employees(+) e JOIN departments dD. SELECT last_name, department_name FROM employees e RIGHT OUTER JOIN departments d ON (e.department_id = d.department_id);E. SELECT last_name, department_name FROM employees(+) , departments ON (e. department _ id = d. department _id);F. SELECT last_name, department_name FROM employees e LEFT OUTER JOIN departments d ON (e. department _ id = d. department _id);
Click the Exhibit button and examine the data in the EMPLOYEES and DEPARTMENTS tables.You want to retrieve all employees‘ last names, along with their managers‘ last names and their department names. Which query would you use?（）A.SELECT last_name, manager_id, department_name FROM employees e FULL OUTER JOIN departments d ON (e.department_id = d.department_id);B.SELECT e.last_name, m.last_name, department_name FROM employees e LEFT OUTER JOIN employees m on ( e.manager_id = m.employee_id) LEFT OUTER JOIN departments d ON (e.department_id = d.department_id);C.SELECT e.last_name, m.last_name, department_name FROM employees e RIGHT OUTER JOIN employees m on ( e.manager_id = m.employee_id) LEFT OUTER JOIN departments d ON (e.department_id = d.department_id);D.SELECT e.last_name, m.last_name, department_name FROM employees e LEFT OUTER JOIN employees m on ( e.manager_id = m.employee_id) RIGHT OUTER JOIN departments d ON (e.department_id = d.department_id);E.SELECT e.last_name, m.last_name, department_name FROM employees e RIGHT OUTER JOIN employees m on ( e.manager_id = m.employee_id) RIGHT OUTER JOIN departments d ON (e.department_id = d.department_id);F.SELECT last_name, manager_id, department_name FROM employees e JOIN departments d ON (e.department_id = d.department_id) ;
Given the following table definitions:EMPLOYEEID NAME DEPTID01Smith 1002Bossy 2003 20Peterson04Goss 3005Pape 4006Avery 5007O‘Neal 6008Carter 50DEPARTMENT ID DEPTNAME05 Hardware 10 Kitchen 20 Shoes 30 Toys 40 Electronics 50 Automotive and the following query: SELECT e.id, d.deptname FROM employee e, department d WHERE e.deptid = d.id AND e.id 4Which of the following queries will produce the same result set as the query above?（）A.SELECT e.id, d.deptname FROM employee e, department d WHERE e.id 4B.SELECT e.id, d.deptname FROM employee e INNER JOIN department d ON e.deptid = d.id WHERE e.id 4C.SELECT e.id, d.deptname FROM employee e FULL OUTER JOIN department d ON e.id = d.id WHERE e.id 4D.SELECT e.id, d.deptname FROM employee e LEFT OUTER JOIN department d ON e.deptid = d.id WHERE e.id 4 UNION ALL SELECT e.id, d.deptname FROM employee e RIGHT OUTER JOIN department d ON e.deptid = d.id WHERE e.id 4
You need to produce a report for mailing labels for all customers. The mailing label must have only the customer name and address. The CUSTOMERS table has these columns: CUST_ID NUMBER(4) NOT NULL CUST_NAME VARCHAR2(100) NOT NULL CUST_ADDRESS VARCHAR2(150) CUST_PHONE VARCHAR2(20) Which SELECT statement accomplishes this task?（）A、SELECT* FROM customers;B、SELECT name, address FROM customers;C、SELECT id, name, address, phone FROM customers;D、SELECT cust_name, cust_address FROM customers;E、SELECT cust_id, cust_name, cust_address, cust_phone FROM customers;
Examine the data in the EMPLOYEES and DEPARTMENTS tables. EMPLOYEES LAST_NAME DEPARTMENT_ID SALARY Getz 10 3000 Davis 20 1500 Bill 20 2200 Davis 30 5000 Kochhar 5000 DEPARTMENTS DEPARTMENT_ID DEPARTMENT_NAME 10 Sales 20 Marketing 30 Accounts 40 Administration You want to retrieve all employees, whether or not they have matching departments in the departments table. Which query would you use?（）A、SELECT last_name, department_name FROM employees , departments(+);B、SELECT last_name, department_name FROM employees JOIN departments(+);C、SELECT last_name, department_name ON (e. department_ id = d. departments_id); FROM employees(+) e JOIN departments dD、SELECT last_name, department_name FROM employees e RIGHT OUTER JOIN departments d ON (e.department_id = d.department_id);E、SELECT last_name, department_name FROM employees(+) , departments ON (e. department _ id = d. department _id);F、SELECT last_name, department_name FROM employees e LEFT OUTER JOIN departments d ON (e. department _ id = d. department _id);
Given the following table definitions: EMPLOYEE ID NAME DEPTID 01Smith 10 02Bossy 20 03 20 Peterson 04Goss 30 05Pape 40 06Avery 50 07O'Neal 60 08Carter 50 DEPARTMENT ID DEPTNAME 05 Hardware 10 Kitchen 20 Shoes 30 Toys 40 Electronics 50 Automotive and the following query: SELECT e.id, d.deptname FROM employee e, department d WHERE e.deptid = d.id AND e.id 4 Which of the following queries will produce the same result set as the query above?（）A、SELECT e.id, d.deptname FROM employee e, department d WHERE e.id 4B、SELECT e.id, d.deptname FROM employee e INNER JOIN department d ON e.deptid = d.id WHERE e.id 4C、SELECT e.id, d.deptname FROM employee e FULL OUTER JOIN department d ON e.id = d.id WHERE e.id 4D、SELECT e.id, d.deptname FROM employee e LEFT OUTER JOIN department d ON e.deptid = d.id WHERE e.id 4 UNION ALL SELECT e.id, d.deptname FROM employee e RIGHT OUTER JOIN department d ON e.deptid = d.id WHERE e.id 4
Click the Exhibit button and examine the data in the EMPLOYEES and DEPARTMENTS tables.You want to retrieve all employees, whether or not they have matching departments in the departments table. Which query would you use?（）A、SELECT last_name, department_name FROM employees NATURAL JOIN departments;B、SELECT last_name, department_name FROM employees JOIN departments ;C、SELECT last_name, department_name FROM employees e JOIN departments d ON (e.department_id = d.department_id);D、SELECT last_name, department_name FROM employees e RIGHT OUTER JOIN departments d ON (e.department_id = d.department_id);E、SELECT last_name, department_name FROM employees FULL JOIN departments ON (e.department_id = d.department_id);F、SELECT last_name, department_name FROM employees e LEFT OUTER JOIN departments d ON (e.department_id = d.department_id);
Examine the structure of the EMPLOYEES and DEPARTMENTS tables: EMPLOYEESColumn name Data type Remarks EMPLOYEE_ID NUMBER NOT NULL, Primary Key EMP_NAME VARCHAR2 (30) JOB_ID VARCHAR2 (20) SALARY NUMBER MGR_ID NUMBER References EMPLOYEE_ID COLUMN DEPARTMENT ID NUMBER Foreign key to DEPARTMENT ID column of the DEPARTMENTS table DEPARTMENTSColumn name Data type Remarks DEPARTMENT_ID NUMBER NOT NULL, Primary Key DEPARTMENT_NAME VARCHAR2(30) MGR_ID NUMBER References MGR_ID column of the EMPLOYEES table Evaluate this SQL statement: SELECT employee_id, e.department_id, department_name, salary FROM employees e, departments d WHERE e. department_id = d.department_id; Which SQL statement is equivalent to the above SQL statement? （）A、SELECT employee_id, department_id, department_name, salary FROM employees WHERE department_id IN (SELECT department_id FROM departments);B、SELECT employee_id, department_id, department_name, salary FROM employees NATURAL JOIN departments;C、SELECT employee_id, d.department_id, department_name, salary FROM employees e JOIN departments d ON e.department _ id = d. department_id;D、SELECT employee_id, department_id, department_name, Salary FROM employees JOIN departments USING (e.department_id, d.department_id);
Examine the structure of the EMPLOYEES and DEPARTMENTS tables: EMPLOYEES EMPLOYEE_ID NUMBER DEPARTMENT_ID NUMBER MANAGER_ID NUMBER LAST_NAME VARCHAR2(25) DEPARTMENTS DEPARTMENT_ID NUMBER MANAGER_ID NUMBER DEPARTMENT_NAME VARCHAR2(35) LOCATION_ID NUMBER You want to create a report displaying employee last names, department names, and locations. Which query should you use?（）A、SELECT e.last_name, d. department_name, d.location_id FROM employees e NATURAL JOIN departments D USING department_id ;B、SELECT last_name, department_name, location_id FROM employees NATURAL JOIN departments WHERE e.department_id =d.department_id;C、SELECT e.last_name, d.department_name, d.location_id FROM employees e NATURAL JOIN departments d;D、SELECT e.last_name, d.department_name, d.location_id FROM employees e JOIN departments d USING (department_id );
Examine the data from the ORDERS and CUSTOMERS table. ORDERS ORD_ID ORD_DATE CUST_ID ORD_TOTAL 100 12-JAN-2000 15 10000 09-MAR- 101 40 8000 09-MAR- 102 35 12500 15-MAR- 103 15 12000 104 25-JUN-2000 15 6000 105 18-JUL-2000 20 5000 106 18-JUL-2000 35 7000 107 21-JUL-2000 20 6500 04-AUG- 108 10 8000 CUSTOMERS CUST_ID CUST_NAME CITY 10 Smith Los Angeles 15 Bob San Francisco 20 Martin Chicago 25 Mary New York 30 Rina Chicago 35 Smith New York 40 Linda New York Which SQL statement retrieves the order ID, customer ID, and order total for the orders that are placed on the same day that Martin places his orders?（） A、SELECT ord_id, cust_id, ord_total FROM orders, customers WHERE cust_name='Mating' AND ord _ date IN ('18-JUL-2000','21-JUL-2000');B、SELECT ord_id, cust_id, ord_total FROM orders Where ord_date IN (SELECT ord_date FROM orders WHERE cust_id = (SELECT cust_id FROM customers WHERE cust_name = 'MARTIN'));C、SELECT ord_id, cust_id, ord_total FROM orders Where ord_date IN (SELECT ord_date FROM orders, customers Where cust _ name = 'Martin');D、SELECT ord_id, cust_id, ord_total FROM orders WHERE cust_id IN (SELECT cust_id FROM customers WHERE cust name = 'Martin');
Examine the structure of the EMPLOYEES and DEPARTMENTS tables: EMPLOYEESColumn name Data type Remarks EMPLOYEE_ID NUMBER NOT NULL, Primary Key EMP_NAME VARCHAR2 (30) JOB_ID VARCHAR2 (20) SALARY NUMBER MGR_ID NUMBER References EMPLOYEE_ID COLUMN DEPARTMENT ID NUMBER Foreign key to DEPARTMENT ID column of the DEPARTMENTS table DEPARTMENTSColumn name Data type Remarks DEPARTMENT_ID NUMBER NOT NULL, Primary Key DEPARTMENT_NAME VARCHAR2(30) MGR_ID NUMBER References MGR_ID column of the EMPLOYEES table Evaluate this SQL statement: SELECT employee_id, e.department_id, department_name, salary FROM employees e, departments d WHERE e. department_id = d.department_id; Which SQL statement is equivalent to the above SQL statement?（）A、SELECT employee_id, department_id, department_name, salary FROM employees WHERE department_id IN (SELECT department_id FROM departments);B、SELECT employee_id, department_id, department_name, salary FROM employees NATURAL JOIN departments;C、SELECT employee_id, d.department_id, department_name, salary FROM employees e JOIN departments d ON e.department _ id = d. department_id;D、SELECT employee_id, department_id, department_name, Salary FROM employees JOIN departments USING (e.department_id, d.department_id);
Examine the structure of the EMPLOYEES and DEPARTMENTS tables: EMPLOYEES EMPLOYEE_ID NUMBER DEPARTMENT_ID NUMBER MANAGER_ID NUMBER LAST_NAME VARCHAR2(25) DEPARTMENTS DEPARTMENT_ID NUMBER MANAGER_ID NUMBER DEPARTMENT_NAME VARCHAR2(35) LOCATION_ID NUMBER You want to create a report displaying employee last names, department names, and locations. Which query should you use?（）A、SELECT e.last_name, d. department_name, d.location_id FROM employees e NATURAL JOIN departments D USING department_id ;B、SELECT last_name, department_name, location_id FROM employees NATURAL JOIN departments WHERE e.department_id =d.department_id;C、SELECT e.last_name, d.department_name, d.location_id FROM employees e NATURAL JOIN departments d;D、SELECT e.last_name, d.department_name, d.location_id FROM employees e JOIN departments d USING (department_id );
单选题Click the Exhibit button and examine the data from the ORDERS and CUSTOMERS tables. Which SQL statement retrieves the order ID, customer ID, and order total for the orders that are placed on the same day that Martin placed his orders?（）A SELECT ord_id, cust_id, ord_total FROM orders, customers WHERE cust_name='Martin' AND ord_date IN ('18-JUL-2000','21-JUL-2000');B SELECT ord_id, cust_id, ord_total FROM orders WHERE ord_date IN (SELECT ord_date FROM orders WHERE cust_id = (SELECT cust_id FROM customers WHERE cust_name = 'Martin'));C SELECT ord_id, cust_id, ord_total FROM orders WHERE ord_date IN (SELECT ord_date FROM orders, customers WHERE cust_name = 'Martin');D SELECT ord_id, cust_id, ord_total FROMorders WHERE cust_id IN (SELECT cust_id FROM customers WHERE cust_name = 'Martin');
单选题Examine the data from the ORDERS and CUSTOMERS table. ORDERS ORD_ID ORD_DATE CUST_ID ORD_TOTAL 100 12-JAN-2000 15 10000 09-MAR- 101 40 8000 09-MAR- 102 35 12500 15-MAR- 103 15 12000 104 25-JUN-2000 15 6000 105 18-JUL-2000 20 5000 106 18-JUL-2000 35 7000 107 21-JUL-2000 20 6500 04-AUG- 108 10 8000 CUSTOMERS CUST_ID CUST_NAME CITY 10 Smith Los Angeles 15 Bob San Francisco 20 Martin Chicago 25 Mary New York 30 Rina Chicago 35 Smith New York 40 Linda New York Which SQL statement retrieves the order ID, customer ID, and order total for the orders that are placed on the same day that Martin places his orders?（）ASELECT ord_id, cust_id, ord_total FROM orders, customers WHERE cust_name='Mating' AND ord _ date IN ('18-JUL-2000','21-JUL-2000');BSELECT ord_id, cust_id, ord_total FROM orders Where ord_date IN (SELECT ord_date FROM orders WHERE cust_id = (SELECT cust_id FROM customers WHERE cust_name = 'MARTIN'));CSELECT ord_id, cust_id, ord_total FROM orders Where ord_date IN (SELECT ord_date FROM orders, customers Where cust _ name = 'Martin');DSELECT ord_id, cust_id, ord_total FROM orders WHERE cust_id IN (SELECT cust_id FROM customers WHERE cust name = 'Martin');
单选题Examine the data in the EMPLOYEES and DEPARTMENTS tables. EMPLOYEES LAST_NAME DEPARTMENT_ID SALARY Getz 10 3000 Davis 20 1500 Bill 20 2200 Davis 30 5000 Kochhar 5000 DEPARTMENTS DEPARTMENT_ID DEPARTMENT_NAME 10 Sales 20 Marketing 30 Accounts 40 Administration You want to retrieve all employees, whether or not they have matching departments in the departments table. Which query would you use?（）ASELECT last_name, department_name FROM employees , departments(+);BSELECT last_name, department_name FROM employees JOIN departments(+);CSELECT last_name, department_name ON (e. department_ id = d. departments_id); FROM employees(+) e JOIN departments dDSELECT last_name, department_name FROM employees e RIGHT OUTER JOIN departments d ON (e.department_id = d.department_id);ESELECT last_name, department_name FROM employees(+) , departments ON (e. department _ id = d. department _id);FSELECT last_name, department_name FROM employees e LEFT OUTER JOIN departments d ON (e. department _ id = d. department _id);
单选题You need to produce a report for mailing labels for all customers. The mailing label must have only the customer name and address. The CUSTOMERS table has these columns: Which SELECT statement accomplishes this task?（）A SELECT* FROM customers;B SELECT name, address FROM customers;C SELECT id, name, address, phone FROM customers;D SELECT cust_name, cust_address FROM customers;E SELECT cust_id, cust_name, cust_address, cust_phone FROM customers;
单选题Examine the data in the EMPLOYEES and DEPARTMENTS tables. EMPLOYEES LAST_NAME DEPARTMENT_ID SALARY Getz 10 3000 Davis 20 1500 Bill 20 2200 Davis 30 5000 Kochhar 5000 DEPARTMENTS DEPARTMENT_ID DEPARTMENT_NAME 10 Sales 20 Marketing 30 Accounts 40 Administration You want to retrieve all employees, whether or not they have matching departments in the departments table. Which query would you use?（）ASELECT last_name, department_name FROM employees , departments(+);BSELECT last_name, department_name FROM employees JOIN departments(+);CSELECT last_name, department_name ON (e. department_ id = d. departments_id); FROM employees(+) e JOIN departments dDSELECT last_name, department_name FROM employees e RIGHT OUTER JOIN departments d ON (e.department_id = d.department_id);ESELECT last_name, department_name FROM employees(+) , departments ON (e. department _ id = d. department _id);FSELECT last_name, department_name FROM employees e LEFT OUTER JOIN departments d ON (e. department _ id = d. department _id);
单选题Examine the data from the ORDERS and CUSTOMERS table. ORDERS ORD_ID ORD_DATE CUST_ID ORD_TOTAL 100 12-JAN-2000 15 10000 09-MAR- 101 40 8000 09-MAR- 102 35 12500 15-MAR- 103 15 12000 104 25-JUN-2000 15 6000 105 18-JUL-2000 20 5000 106 18-JUL-2000 35 7000 107 21-JUL-2000 20 6500 04-AUG- 108 10 8000 CUSTOMERS CUST_ID CUST_NAME CITY 10 Smith Los Angeles 15 Bob San Francisco 20 Martin Chicago 25 Mary New York 30 Rina Chicago 35 Smith New York 40 Linda New York Which SQL statement retrieves the order ID, customer ID, and order total for the orders that are placed on the same day that Martin places his orders?（）ASELECT ord_id, cust_id, ord_total FROM orders, customers WHERE cust_name='Mating' AND ord _ date IN ('18-JUL-2000','21-JUL-2000');BSELECT ord_id, cust_id, ord_total FROM orders Where ord_date IN (SELECT ord_date FROM orders WHERE cust_id = (SELECT cust_id FROM customers WHERE cust_name = 'MARTIN'));CSELECT ord_id, cust_id, ord_total FROM orders Where ord_date IN (SELECT ord_date FROM orders, customers Where cust _ name = 'Martin');DSELECT ord_id, cust_id, ord_total FROM orders WHERE cust_id IN (SELECT cust_id FROM customers WHERE cust name = 'Martin');
单选题Click the Exhibit button and examine the data from the ORDERS and CUSTOMERS tables. Which SQL statement retrieves the order ID, customer ID, and order total for the orders that are placed on the same day that Martin placed his orders?（）A SELECT ord_id, cust_id, ord_total FROM orders, customers WHERE cust_name='Martin' AND ord_date IN ('18-JUL-2000','21-JUL-2000');B SELECT ord_id, cust_id, ord_total FROM orders WHERE ord_date IN (SELECT ord_date FROM orders WHERE cust_id = (SELECT cust_id FROM customers WHERE cust_name = 'Martin'));C SELECT ord_id, cust_id, ord_total FROM orders WHERE ord_date IN (SELECT ord_date FROM orders, customers WHERE cust_name = 'Martin');D SELECT ord_id, cust_id, ord_total FROMorders WHERE cust_id IN (SELECT cust_id FROM customers WHERE cust_name = 'Martin');
单选题Click the Exhibit button and examine the data in the EMPLOYEES and DEPARTMENTS tables.You want to retrieve all employees, whether or not they have matching departments in the departments table. Which query would you use?（）ASELECT last_name, department_name FROM employees NATURAL JOIN departments;BSELECT last_name, department_name FROM employees JOIN departments ;CSELECT last_name, department_name FROM employees e JOIN departments d ON (e.department_id = d.department_id);DSELECT last_name, department_name FROM employees e RIGHT OUTER JOIN departments d ON (e.department_id = d.department_id);ESELECT last_name, department_name FROM employees FULL JOIN departments ON (e.department_id = d.department_id);FSELECT last_name, department_name FROM employees e LEFT OUTER JOIN departments d ON (e.department_id = d.department_id);
单选题Examine the data in the EMPLOYEES and DEPARTMENTS tables. EMPLOYEES LAST_NAME DEPARTMENT_ID SALARY Getz 10 3000 Davis 20 1500 Bill 20 2200 Davis 30 5000 Kochhar 5000 DEPARTMENTS DEPARTMENT_ID DEPARTMENT_NAME 10 Sales 20 Marketing 30 Accounts 40 Administration You want to retrieve all employees, whether or not they have matching departments in the departments table. Which query would you use?（）ASELECT last_name, department_name FROM employees , departments(+);BSELECT last_name, department_name FROM employees JOIN departments(+);CSELECT last_name, department_name ON (e. department_ id = d. departments_id); FROM employees(+) e JOIN departments dDSELECT last_name, department_name FROM employees e RIGHT OUTER JOIN departments d ON (e.department_id = d.department_id);ESELECT last_name, department_name FROM employees(+) , departments ON (e. department _ id = d. department _id);FSELECT last_name, department_name FROM employees e LEFT OUTER JOIN departments d ON (e. department _ id = d. department _id);
单选题Click the Exhibit button and examine the data in the EMPLOYEES and DEPARTMENTS tables.You want to retrieve all employees, whether or not they have matching departments in the departments table. Which query would you use?（）ASELECT last_name, department_name FROM employees NATURAL JOIN departments;BSELECT last_name, department_name FROM employees JOIN departments ;CSELECT last_name, department_name FROM employees e JOIN departments d ON (e.department_id = d.department_id);DSELECT last_name, department_name FROM employees e RIGHT OUTER JOIN departments d ON (e.department_id = d.department_id);ESELECT last_name, department_name FROM employees FULL JOIN departments ON (e.department_id = d.department_id);FSELECT last_name, department_name FROM employees e LEFT OUTER JOIN departments d ON (e.department_id = d.department_id);
单选题Examine the data from the ORDERS and CUSTOMERS table. ORDERS ORD_ID ORD_DATE CUST_ID ORD_TOTAL 100 12-JAN-2000 15 10000 09-MAR- 101 40 8000 09-MAR- 102 35 12500 15-MAR- 103 15 12000 104 25-JUN-2000 15 6000 105 18-JUL-2000 20 5000 106 18-JUL-2000 35 7000 107 21-JUL-2000 20 6500 04-AUG- 108 10 8000 CUSTOMERS CUST_ID CUST_NAME CITY 10 Smith Los Angeles 15 Bob San Francisco 20 Martin Chicago 25 Mary New York 30 Rina Chicago 35 Smith New York 40 Linda New York Which SQL statement retrieves the order ID, customer ID, and order total for the orders that are placed on the same day that Martin places his orders?（）ASELECT ord_id, cust_id, ord_total FROM orders, customers WHERE cust_name='Mating' AND ord _ date IN ('18-JUL-2000','21-JUL-2000');BSELECT ord_id, cust_id, ord_total FROM orders Where ord_date IN (SELECT ord_date FROM orders WHERE cust_id = (SELECT cust_id FROM customers WHERE cust_name = 'MARTIN'));CSELECT ord_id, cust_id, ord_total FROM orders Where ord_date IN (SELECT ord_date FROM orders, customers Where cust _ name = 'Martin');DSELECT ord_id, cust_id, ord_total FROM orders WHERE cust_id IN (SELECT cust_id FROM customers WHERE cust name = 'Martin');
单选题You need to produce a report for mailing labels for all customers. The mailing label must have only the customer name and address. The CUSTOMERS table has these columns: Which SELECT statement accomplishes this task?（）A SELECT* FROM customers;B SELECT name, address FROM customers;C SELECT id, name, address, phone FROM customers;D SELECT cust_name, cust_address FROM customers;E SELECT cust_id, cust_name, cust_address, cust_phone FROM customers;
单选题Examine the data from the ORDERS and CUSTOMERS table. ORDERS ORD_ID ORD_DATE CUST_ID ORD_TOTAL 100 12-JAN-2000 15 10000 09-MAR- 101 40 8000 09-MAR- 102 35 12500 15-MAR- 103 15 12000 104 25-JUN-2000 15 6000 105 18-JUL-2000 20 5000 106 18-JUL-2000 35 7000 107 21-JUL-2000 20 6500 04-AUG- 108 10 8000 CUSTOMERS CUST_ID CUST_NAME CITY 10 Smith Los Angeles 15 Bob San Francisco 20 Martin Chicago 25 Mary New York 30 Rina Chicago 35 Smith New York 40 Linda New York Which SQL statement retrieves the order ID, customer ID, and order total for the orders that are placed on the same day that Martin places his orders?（）ASELECT ord_id, cust_id, ord_total FROM orders, customers WHERE cust_name='Mating' AND ord _ date IN ('18-JUL-2000','21-JUL-2000');BSELECT ord_id, cust_id, ord_total FROM orders Where ord_date IN (SELECT ord_date FROM orders WHERE cust_id = (SELECT cust_id FROM customers WHERE cust_name = 'MARTIN'));CSELECT ord_id, cust_id, ord_total FROM orders Where ord_date IN (SELECT ord_date FROM orders, customers Where cust _ name = 'Martin');DSELECT ord_id, cust_id, ord_total FROM orders WHERE cust_id IN (SELECT cust_id FROM customers WHERE cust name = 'Martin');