根据所测镜体反射率(R0)的平均值,可以绘制地质剖面的();根据()的变化可以判断沉积演化史。
根据所测镜体反射率(R0)的平均值,可以绘制地质剖面的();根据()的变化可以判断沉积演化史。
相关考题:
下列关于Sub过程的叙述正确的是A.一个Sub过程必须有一个Exie Sub语句B.一个Sub过程必须有一个Enb Sub语句C.在Sub过程中可以定义一个Function过程D.可以用Goto语句退出Sub过程
II型呼吸衰竭合并代谢性酸中毒()。 A、Pa0/sub2/supsubno60mHl.PaCO/sub2/supsubno50mmlgB、Pa0/sub2/supsubno60mHgPaCO/sub2/supsubno45mmgC、Pa0/sub2/supsubno60mmHgPaCO/sub2/supsubno50mmHD、Pa0/sub2/supsubno60mHg、PaCO/sub2/supsubno45mmHgE、Pa0/sub2/supsubno60mHg、PaC0/sub2supsubno45mmHg
以下程序的运行结果是( ) #define MAX 10 int a[MAX],i; main() { printf("\n");sub1();sub3(A) ,sub2(),sub3(A) ; } sub2() { int a[MAX],i,max; max=5; for(i=0;i<max;i++)a[i]=i; } sub1() {for(i=0;i<MAX;i++)a[i]=i+i; } sub3(int a[]) { int i; for(i=0;i<MAX,i++)printf("%d",a[i]); printf("\n"); }A.0 2 4 6 8 10 12 14 16 18 0 1 2 3 4B.0 1 2 3 4 0 2 4 6 8 10 12 14 16 18C.0 1 2 3 4 5 6 7 8 9 0 1 2 3 4D.0 2 4 6 8 10 12 14 16 18 0 2 4 6 8 10 12 14 16 18
有如下程序: Private Sub Command1_Click() Dim a As Single Dim b As Single a=5:b=4 Call Sub1(a,b) End Sub Sub Sub1(x As Single,y As Single) t=X X=t\Y Y=t Mod y End Sub 在调用运行上述程序后,a和b的值分别为A.0 0B. 1 1C.2 2D.1 2
有如下程序: Private Sub Commandl_Click() Dim a As Single Dim b As Single a=2:b=4 Call CS(a,b)End Sub Sub CS(x As Single,y As Single) t=X x=t\y y=t Mod y End Sub 程序运行后,单击命令按钮,a和b的值分别为A.0 0B.1 1C.0 2D.1 2
以下程序的输出结果是( )。 include main()fint x=0; sub(x,16,2); printf("%d\n", 以下程序的输出结果是( )。include<stdio.h>main()fint x=0;sub(x,16,2);printf("%d\n",x);}sub(int*a,int n,int k){if(k<=n) sub(a,n/2,2*k);*a+=k;}
有如下程序。 Private Sub Commandl_Click() Dim a As Single Dim b As Single a=5:b=4 Call Sub1 ( a,B)End Sub Sub Subl(x As Single, y As Single) t=x x=t\y y = t Mod y End Sub 在调用运行上述程序后,a和b的值分别为A.0 0B.1 1C.2D.1 2
当下行DTX功能开启时,手机向网络汇报的测量报告哪一个是合理的()。A、Rxlev_Sub=-83,Rxlev_Full=-67,RxQual_Sub=0,RxQual_Full=7B、Rxlev_Sub=-67,Rxlev_Full=-83,RxQual_Sub=0,RxQual_Full=7C、Rxlev_Sub=-83,Rxlev_Full=-67,RxQual_Sub=7,RxQual_Full=0D、Rxlev_Sub=-67,Rxlev_Full=-83,RxQual_Sub=7,RxQual_Full=0
阅读下列程序,回答问题: LDR R0, 0x22 LDR R1, 0x11 SUB R0, R0, R1 CMP R0, R1执行这段程序后,R0的值为()A、 0x22B、 0x33C、 0x11D、 0
class Super { public int i = 0; public Super(String text) { i = 1; } } public class Sub extends Super { public Sub(String text) { i = 2; } public static void main(String args[]) { Sub sub = new Sub(“Hello”); System.out.println(sub.i); } } What is the result?() A、 0B、 1C、 2D、 Compilation fails.
将硬盘C:///SUB下的全部文件(总长度超过5MB)备份到软盘,用()命令一定不可以。A、BACKUP C://SUB/*.*A:B、BACKUP C:///SUB A:C、COPY C:///SUB A:D、BACKUP C:///SUB B:
单选题class Super { public int i = 0; public Super(String text) { i = 1; } } public class Sub extends Super { public Sub(String text) { i = 2; } public static void main(String args[]) { Sub sub = new Sub(“Hello”); System.out.println(sub.i); } } What is the result?()A 0B 1C 2D Compilation fails.
单选题class super ( public int I = 0; public super (string text) ( I = 1 ) ) public class sub extends super ( public sub (string text) ( i= 2 ) public static void main (straing args) ( sub sub = new sub (“Hello”); system.out. PrintIn(sub.i); ) ) What is the result?()A Compilation will fail.B Compilation will succeed and the program will print “0”C Compilation will succeed and the program will print “1”D Compilation will succeed and the program will print “2”
单选题正态分布时,算术平均数、中位数、众数的关系为()Amsub0/sub<msube/sub<(xBmsub0/sub=msube/sub=(xCmsub0/sub>msube/sub>(xDmsube/sub<msub0/sub<(x
多选题下列表示中____的表示形式是正确的。ApUsub95/sub= 1%,vsubeff/sub =9 /pBpUsubr/sub= 1%,k=2 /pCpusubC/sub=0. 5% /pDpusubC/sub=±0 5%.k=1 /p
多选题设up为标准正态分布的p分位数,则有( )。Ausub0.49/sub>0 Busub0.3/sub<usub0.4 /subCusub0.5/sub=0 Dusub0.23/sub=-usub0.77 /subEusub0.5/sub=-usub0.5/sub
单选题已知某线声源长度为l0,在线声源垂直平分线上距线声源r0和r的分别为Lp(r0)和Lp(r),根据《环境影响评价技术导则声环境》,按公式Lp(r)=Lp(r0)-15lg(r/r0)近似计算该线声源的噪声影响时,应满足的条件是()。AprIsub0/sub且rsub0/subIsub0/sub /pBprIsub0/sub/3且rsub0/subIsub0/sub/3 /pCpIsub0/sub/3rspanI/spansub0/sub且Isub0/sub/3rsub0/subr0Isub0/sub /r0/pDp无条件限制 /p
填空题根据所测镜体反射率(R0)的平均值,可以绘制地质剖面的();根据()的变化可以判断沉积演化史。