A good friend of mine from I was born showed up at my home right before I left for Beijing．A．howB．whomC．whenD．which
A good friend of mine from I was born showed up at my home right before I left for Beijing．
A．howB．whom
C．whenD．which
相关考题：
执行以下程序段a$="abbacddcba"For i=6 To 2 Step -2X=Mid（a,i,i）Y=Left（a,i）z=Right（a,i）z=UCase（X Y z）Next iPrint z输出结果为（ ）。A．ABAB．BBABBAC．ABBABAD．AABAAB
下列程序段的结果为 ______。 A= "ABBACDDCBA" For I= 6 To 2 Step-2 X=Mid(A，I，I) Y=Left(A，I) Z=Right(A，I) Z=X Y Z Next I Print ZA．ABAB．AABAABC．BBABBAD．ABBABA
阅读下列C程序和程序说明，将应填入(n)处的字句写在对应栏内。【说明】下面是一个用C编写的快速排序算法。为了避免最坏情况，取基准记录pivot时，采用从left、right和mid=[(left+right)/2]中取中间值，并交换到right位置的办法。数组a存放待排序的一组记录，数据类型为T，left和right是待排序子区间的最左端点和最右端点。void quicksort (int a[], int left, int right) {int temp;if (left＜right) {hat pivot = median3 (a, left, right); //三者取中子程序int i = left, j = right-1;for(;;){while (i ＜j a[i] ＜ pivot) i++;while (i ＜j pivot ＜ a[j]) j--;if(i＜j){temp = a[i]; a[j] = a[i]; a[i] = temp;i++; j--;}else break;}if (a[i] ＞ pivot){temp = a[i]; a[i] = a[right]; a[right] = temp;}quicksort( (1) ); //递归排序左子区间quieksort(a,i+1 ,right); //递归排序右子区间}}void median3 (int a[], int left, int right){ int mid=(2);int k = left;if(a[mid] ＜ a[k])k = mid;if(a[high] ＜ a[k]) k = high; //选最小记录int temp = a[k]; a[k] = a[left]; a[left] = temp; //最小者交换到 leftif(a[mid] ＜ a[right]){temp=a[mid]; a[mid]=a[right]; a[right]=temp;}}消去第二个递归调用 quicksort (a,i+1,right)。 采用循环的办法:void quicksort (int a[], int left, int right) {int temp; int i,j;(3) {int pivot = median3(a, left, right); //三者取中子程序i = left; j = righi-1;for (;; ){while (i＜j a[i] ＜ pivot)i++;while (i＜j pivot ＜a[j]) j--;if(i ＜j) {temp = a[i]; a[j]; = a[i]; a[i]=temp;i++; j--;}else break;}if(a[i]＞pivot){(4);a[i]=pivot;}quicksoft ((5)); //递归排序左子区间left = i+1;}}
执行以下程序段 a$="abbacddcba" For i=6 To 2 Step-2 X=Mid(a,i,i) Y=Left(a,i) Z=Right(a,i) z=UCase(XYz) Next i Print z 输出结果为( )A．ABCB．BBABBAC．ABBABAD．AABAAB
下列程序段的结果为A="ABBACDDCBA"For i=6 To 2 Step-2X=Mid(A,i,i)Y=Left(A,i)Z=Right(A,i)Z=XYZNextPrint ZA．ABCB．AABAABC．BBABBAD．ABBABA
执行以下程序段 a$ ="abbacddcba" For i = 6 To 2 Step - 2 X = Mid(a， i，i) Y=Left(a， i) z=Right(a，i) z=UCase(X Y Z) Next i Print z 输出结果为A．ABCB．BBABBAC．ABBABAD．AABAAB
执行以下程序段 a$=“abbacddcba” For i=6 To 2 Step－2 X=Mid(a，i，i) Y=Left(a，i) z=Right(a, i) z=Ucase(X Y z) Next i Print z 输出结果为A．ABAB．BBABBAC．ABBABAD．AABAAB
下列程序段的结果为_______。 A="ABBACDDCBA" For I=6 To 2 Step -2 X=Mid(A，I，I) Y=Left(A，I) Z=Right(A，I) Z=X Y Z Next I Print ZA．ABAB．AABAABC．BBABBAD．ABBABA
执行以下程序段： a $="abbaedduba" For i=6 To 2 Step-2 X=Mid(a, i, i) Y=Left(a, i) z=Right(a, i) z=UCase(XYz) Next i Print z 输出结果为______。A．ABAB．BBABBAC．ABBABAD．AABAAB
下列程序段的结果为______。 A="ABBACDDCBA" For I=6 To 2 Step-2 X=Mid(A,I,I) Y=Left(A,I) Z=Right(A,I) Z=XYZ Next I Print ZA．ABAB．AABAABC．BBABBAD．ABBABA