Look, there is an ______ tree by the wall. A appleB apple'sC apples'D apples

Look, there is an ______ tree by the wall.

A apple

B apple's

C apples'

D apples


相关考题:

finalclassTree{privatestaticStringtree=tree;StringgetTree(){returntree;}}classElmextendsTree{privatestaticStringtree=elm;publicstaticvoidmain(String[]args){newElm().go(newTree());}voidgo(Treet){Strings=t.getTree()+Elm.tree+tree+(newElm().getTree());System.out.println(s);}}结果为:()A.elmelmelmelmB.treeelmelmelmC.treeelmtreeelmD.编译失败

现有:classTree{privatestaticStringtree=tree;StringgetTree(){returntree;}}classElmextendsTree{privatestaticStringtree=elm;publicstaticvoidmain(String[]args){newElm().go(newTree());}}voidgo(Treet){Strings=t.getTree()+Elm.tree+tree+(newElm().getTree());System.out.println(s);}结果为:()

阅读以下说明和C语言函数,将应填入(n)处的语句写在对应栏内。【说明】本程序利用非递归算法实现二叉树后序遍历。【函数】include<stdio.h>include<stdlib.h>typedef struct node{/*二叉树的结点数据结构类型*/char data;struct node *left;struct node *right;}BTREE;void SortTreelnsert(BTREE **tree, BTREE *s){if(*tree==NULL)*tree=s;elseif(s->data<(*tree)->data)SortTreelnsert((1),s);else if(s->data>=(*tree)->data)SortTreelnsert((2),s);}void TraversalTree(BTREE *tree){BTREE *stack[1 000],*p;int tag[1000],top=0;p=tree;do{while(p !=NULL){stack[++top]=p;(3);tag[top]=0; /*标记栈顶结点的左子树已进行过后序遍历*/}while(top>0(4))/*栈顶结点的右子树是否被后序遍历过*/{p=stack[top--];putchar(p->data);}if(top>0)/*对栈顶结点的右子树进行后序遍历*/{(5);tag[top]=1;}}while(top>0);}void PrintSortTree(BTREE *tree){if(tree !=NULL){printSortTree(tree->left);putchar(tree->data);pdntSortTree(tree->right);}}main(){BTREE *root=NULL, *node;char ch;ch=getchar();while(ch !=''){node=(BTREE*)malloc(sizeof(BTREE));node->data=ch;node->left=node->right=NULL;SortTreelnsert(root, node);ch=getchar();}PrintSortTree(root);putchar('\n');TraversalTree(root);}

设有语句 int n,m; char a[5],b; cin>>n>>a>>m>>b; 为了分别将10和20分别赋给n和m,look赋给a,t赋给b,则正确的输入为A.10 "look" 20 't'<CR>B.10 "look" 10C.10 look 20 tD.10<CR>look20<CR>t<CR>

在考生文件夹中为HILL文件夹中的TREE.exe文件建立名为TREE的快捷方式。

WhichtreeofthesearetypesofEthernetVirtueConnections(EVCs)intheMEFconcept?() A.multipart-to-multipointEVC(E-LAN)B.hubspokeEVC(E-Tree)C.pointtopointEVC(E-Line)D.rootedmultipointEVC(E-Tree)E.point-to-multipointEVC(E-Tree)

WhichthreeofthesearetypesofEthernetVirtualConnections(EVCs)intheMEFconcept?() A.rootedmultipointEVC(E-Tree)B.point-to-pointEVC(E-Line)C.point-to-multipointEVC(E-Tree)D.hubspokeEVC(E-Tree)E.multipoint-to-multipointEVC(E-LAN)

Look! Here()the famous playerAcomesBcomeChad comeDcoming

tree.add(6); tree.add(1); tree.add(1); 则遍历树集tree之后,可以输出1,1,6。()

1、tree.add(6); tree.add(1); tree.add(1); 则遍历树集tree之后,可以输出1,1,6。()