It is believed that the tradition of having a pine tree as a Christmas Tree comes from Germany.()
It is believed that the tradition of having a pine tree as a Christmas Tree comes from Germany.()
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finalclassTree｛privatestaticStringtree＝tree；StringgetTree（）｛returntree；｝｝classElmextendsTree｛privatestaticStringtree＝elm；publicstaticvoidmain（String[]args）｛newElm（）.go（newTree（））；｝voidgo（Treet）｛Strings＝t.getTree（）+Elm.tree+tree+（newElm（）.getTree（））；System.out.println（s）；｝｝结果为：（）A.elmelmelmelmB.treeelmelmelmC.treeelmtreeelmD.编译失败
现有：classTree{privatestaticStringtree=tree；StringgetTree（）{returntree；}}classElmextendsTree{privatestaticStringtree=elm；publicstaticvoidmain（String[]args）{newElm（）.go（newTree（））；}}voidgo（Treet）{Strings=t.getTree（）+Elm.tree+tree+（newElm（）.getTree（））；System.out.println（s）；}结果为：（）
阅读以下说明和C语言函数，将应填入(n)处的语句写在对应栏内。【说明】本程序利用非递归算法实现二叉树后序遍历。【函数】include＜stdio.h＞include＜stdlib.h＞typedef struct node{/*二叉树的结点数据结构类型*/char data;struct node *left;struct node *right;}BTREE;void SortTreelnsert(BTREE **tree, BTREE *s){if(*tree==NULL)*tree=s;elseif(s-＞data＜(*tree)-＞data)SortTreelnsert((1),s);else if(s-＞data＞=(*tree)-＞data)SortTreelnsert((2),s);}void TraversalTree(BTREE *tree){BTREE *stack[1 000],*p;int tag[1000],top=0;p=tree;do{while(p !=NULL){stack[++top]=p;(3);tag[top]=0; /*标记栈顶结点的左子树已进行过后序遍历*/}while(top＞0(4))/*栈顶结点的右子树是否被后序遍历过*/{p=stack[top--];putchar(p-＞data);}if(top＞0)/*对栈顶结点的右子树进行后序遍历*/{(5);tag[top]=1;}}while(top＞0);}void PrintSortTree(BTREE *tree){if(tree !=NULL){printSortTree(tree-＞left);putchar(tree-＞data);pdntSortTree(tree-＞right);}}main(){BTREE *root=NULL, *node;char ch;ch=getchar();while(ch !=''){node=(BTREE*)malloc(sizeof(BTREE));node-＞data=ch;node-＞left=node-＞right=NULL;SortTreelnsert(root, node);ch=getchar();}PrintSortTree(root);putchar('\n');TraversalTree(root);}
考虑如下代码：class Tree{}class Pine extends Tree{}class Oak extends Tree{}public class Forest {public static void main( String[] args ) {Tree tree = new Pine();if( tree instanceof Pine )System.out.println( "Pine" );if( tree instanceof Tree )System.out.println( "Tree" );if( tree instanceof Oak )System.out.println( "Oak" );elseSystem.out.println( "Oops" );}}则输出结果中有哪些?A.Pine B.Tree C.Forest D.Oops E.无输出
WhichtreeofthesearetypesofEthernetVirtueConnections(EVCs)intheMEFconcept?() A.multipart-to-multipointEVC（E-LAN）B.hubspokeEVC（E-Tree）C.pointtopointEVC（E-Line）D.rootedmultipointEVC（E-Tree）E.point-to-multipointEVC（E-Tree）
WhichthreeofthesearetypesofEthernetVirtualConnections(EVCs)intheMEFconcept?() A.rootedmultipointEVC（E-Tree）B.point-to-pointEVC（E-Line）C.point-to-multipointEVC（E-Tree）D.hubspokeEVC（E-Tree）E.multipoint-to-multipointEVC（E-LAN）
1、tree.add（6); tree.add（1); tree.add（1); 则遍历树集tree之后，可以输出1,1,6。（）