The problem is that all names other people and they are intensely personal?() A、fed onB、conjured upC、contributed toD、broke up
The problem is that all names other people and they are intensely personal?()
A、fed on
B、conjured up
C、contributed to
D、broke up
相关考题：
People with a strong( )are sometimes not easy to get along with. A. personB. personalityC. personificationD. personal
YouareimplementinganASP.NETpage.Client-sidescriptrequiresdata.YourapplicationincludesaclassnamedPersonwithaNamepropertyoftypestring.Thecode-behindfileofthepageincludesthefollowingcodesegment.YouneedtousetheJavaScriptSerializerclasstoserializeonlytheNamepropertyofeachiteminthepeoplelist.Whichcodesegmentshouldyouuse？（）A.JsonValue=json.Serialize（people.Select（p=p.Name））；B.varnames=frompersoninpeopleselectperson；JsonValue={+json.Serialize（names）+}；C.JsonValue=json.Serialize（people.SelectMany（p=Name.AsEnumerable（）））；D.varnames=frompersoninpeopleselectperson；JsonValue=json.Serialize（names）；
下面哪一个是错误的? A.使用len(列表名)测量元素的个数names_list=["zhangsan","lisi","wangwu"]print(len(names_list))B.使用列表名[下标]获取列表的某个元素，例如：names_list=["zhangsan","lisi","wangwu"]print(names_list[2])C.向列表中添加新元素有三个方法：append、extend、insert，例如：names_list=["zhangsan","lisi","wangwu"]names_list.append("zhaoliu")names_list.extend(["zhaoliu","liqi"])names_list.insert(1,"zhaoliu")print(names_list)D.已有列表nums=[11,22,33,44,55],使用while循环遍历列表nums=[11,22,33,44,55]i=0 whileiprint(nums[i])i+=1
According to news reports, personal __________of guns in the USA causes a lot of trouble.A.wealthB.possessionC.matterD.problem
针对下列程序段，需要（ ）个测试用例才可以满足语句覆盖的要求。switch（value）{case 0:other=30;break;case 1:other=50;break;case 2:other=300;case 3:other=other/value;break;default:other=other*value;}A.2B.3C.4D.5
1、针对下列程序段，需要（）个测试用例才可以满足语句覆盖的要求。 switch （value ) { case 0: other = 30; break; case 1: other = 50; break; case 2: other = 300; case 3: other = other/value; break; default: other = other * value; }A．2B．3C．4D．5
多选题：下面哪个是错误的用python实现存储n个人的姓名？A．names1=n*[0] for i in range(n): names1[i]=input('输入{}个人的姓名:'.format(i+1))B．names2=[] for i in range(n): names.append(input('输入{}个人的姓名:'.format(i+1)))C．names3=[] for i in range(n): name=input('输入{}个人的姓名:'.format(i+1)) names3+=nameD．names4=[] for i in range(n): names4[i]=input('输入{}个人的姓名:'.format(i+1))E．names5=[] for i in range(n): name=input('输入{}个人的姓名:'.format(i+1)) names5+=[name]