Either way, a permit and inspection would be required. (英译汉)
Either way, a permit and inspection would be required. (英译汉)
相关考题：
Oneofthekeydecisionmakingfactorsinaverycompetitiveopportunitywillbecost. CompanycomneedsanaggregaterPerfratingof120.Whatisthebestsolution?() A.Twop557016way1.9MHzmachinesB.Onep559032way1.65MHzmachinesC.Onep559532way1.65MHzmachinesD.Twop557016way1.65MHzmachines
如果允许来自子网172.30.16.0/24到172.30.31.0/24的分组通过路由器，则对应ACL语句应该是（ ）A. access-list 10 permit 172.30.16. 0 255.255. 0.0 B. access-list 10 permit 172.30.16. 0 0.0.2555.255 C. access-list 10 permit 172.30.16. 0 0.0.15.255D. access-list 10 permit 172.30.16. 0 255.255.240.0
According to RFC 2328, what is the stateful order in which an OSPF router transitions to a full adjacency with a neighbor router?() A. Down, Init, 2 - Way, Exstart, Exchange, Loading, and FullB. Down, Init, 2 - Wa y, Exchange, Exstart, Loading, and FullC. Down, 2 - Way, Init, Loading, Exstart, Exchange, and FullD. Down, 2 - Way, Init, Exchange, Exstart, Loading, and FullE. Down, Init, 2 - Way, Loading, Exstart, Exchange, and FullF. Down, 2 - Way, Init, Exstart, Exch ange, Loading, and Full
An access list was written with the four statements shown in the graphic.Which single access list statement will combine all four of these statements into a single statement that will have exactly the same effect？（）A.access-list10 permit 172.29.16.00.0.0.255B.access-list10 permit 172.29.16.00.0.1.255C.access-list10 permit 172.29.16.00.0.3.255D.access-list10 permit 172.29.16.00.0.15.255E.access-list10 permit 172.29.0.00.0.255.255
Which single access list statement will combine all four of these statements into a single statement that will have exactly the same effect()。 A.access-list 10 permit 172.29.16.0 0.0.0.255B.access-list 10 permit 172.29.16.0 0.0.1.255C.access-list 10 permit 172.29.16.0 0.0.3.255D.access-list 10 permit 172.29.16.0 0.0.15.255E.access-list 10 permit 172.29.0.0 0.0.255.255
That the ______ showed that the ship complied with the requirements of the said Convention.A.lookingB.seeingC.sightseeingD.inspection
下列选项中哪一条可以准确的匹配并代替以下四条访问控制列表（）（1）：access-list 10 permit172.29.16.00.0.0.255（2）：access-list 10 permit172.29.17.00.0.0.255（3）：access-lis t10 permit172.29.18.00.0.0.255（4）：access-list 10 permit172.29.19.00.0.0.255A.access-list 10 permit 172.29.16.00.0.0.255B.access-list 10 permit 172.29.16.00.0.1.255C.access-list 10 permit 172.29.16.00.0.3.255D.access-list 10 permit 172.29.16.00.0.15.255E.access-list 10 permit 172.29.16.0255.255.252.0
如果允许来自子网172.30.16.0/24到172.30.31.0/24的分组通过路由器，则对应ACL语句应该是（ ）。 A. access-list 10permit 172.30.16. 0255.255. 0.0B. access-list 10permit 172.30.16. 00.0.2555.255C. access-list 10permit 172.30.16. 00.0.15.255D. access-list 10permit 172.30.16. 0255.255.240.0
在配置PAT的过程中，定义内部本地地址范围正确的是：A．Router(config)#access-list 10 permit 192.168.1.0 0.0.0.255B．Router#access-list 10 permit 192.168.1.0 0.0.0.255C．Router(config)#access-list 10 permit 192.168.1.0 255.255.255.0D．Router#access-list 10 permit 192.168.1.0 255.255.255.0
匹配所有如下网络的单个访问列表语句是什么？ 192.168.16.0 192.168.17.0 192.168.18.0 192.168.19.0A．access-list 10 permit 192.168.16.0 0.0.3.255B．access-list 10 permit 192.168.16.0 0.0.0.255C．access-list 10 permit 192.168.16.0 0.0.15.255D．access-list 10 permit 192.168.0.0 0.0.15.255