The marketing department()the last for the last six months.A. has summarizedB. summarizeC. was summarize
The marketing department()the last for the last six months.
A. has summarized
B. summarize
C. was summarize
相关考题：
Examine the structure of the EMPLOYEES table: EMPLOYEE_ID NUMBER Primary KeyFIRST_NAME VARCHAR2(25)LAST_NAME VARCHAR2(25)DEPARTMENT_ID NUMBERSALARY NUMBERWhat is the correct syntax for an inline view? （）A. SELECT a.last_name, a.salary, a.department_id, b.maxsal FROM employees a, (SELECT department_id, max(salary)maxsal FROM employees GROUP BY department_id) b WHERE a.department_id = b.department_id AND a.salary b.maxsal;B. SELECT a.last name, a.salary, a.department_id FROM employees a WHERE a.department_id IN (SELECT department_id FROM employees b GROUP BY department_id having salary = (SELECT max(salary) from employees))C. SELECT a.last_name, a.salary, a.department_id FROM employees a WHERE a.salary = (SELECT max(salary) FROM employees b WHERE a.department _ id = b.department _ id);D. SELECT a.last_name, a.salary, a.department_id FROM employees a WHERE (a.department_id, a.salary) IN (SELECT department_id, a.salary) IN (SELECT department_id max(salary) FROM employees b GROUP BY department_id ORDER BY department _ id);
ExhibitExamine the data in the EMPLOYEES and DEPARTMENTS tables.You want to retrieve all employees‘ last names, along with their manager‘s last names and their department names. Which query would you use?（）A. SELECT last_name, manager_id, department_name FROM employees e FULL OUTER JOIN department d ON (e.department_id = d.department_id);B. SELECT e.last_name, m.last_name, department_name FROM employees e LEFT OUTER JOIN employees m on ( e.managaer_id = m.employee_id) LEFT OUTER JOIN department d ON (e.department_id = d.department_id);C. SELECT e.last_name, m.last_name, department_name FROM employees e RIGT OUTER JOIN employees m on ( e.manager_id = m.employee_id) FULL OUTER JOIN department d ON (e.department_id = d.department_id);D. SELECT e.last_name, m.last_name, department_name FROM employees e LEFT OUTER JOIN employees m on ( e.manager_id = m.employee_id) RIGT OUTER JOIN department d ON (e.department_id = d.department_id);E. SELECT e.last_name, m.last_name, department_name FROM employees e RIGHT OUTER JOIN employees m on ( e.manager_id = m.employee_id) RIGHT OUTER JOIN departments d ON (e.department_id = d.department_id)F. SELECT last_name, manager_id, department_name FROM employees e JOIN department d ON (e.department_id = d.department_id);
Examine the structure of the EMPLOYEES and DEPARTMENTS tables:EMPLOYEESEMPLOYEE_ID NUMBERDEPARTMENT_ID NUMBERMANAGER_ID NUMBERLAST_NAME VARCHAR2(25)DEPARTMENTSDEPARTMENT_ID NUMBERMANAGER_ID NUMBERDEPARTMENT_NAME VARCHAR2(35)LOCATION_ID NUMBERYou want to create a report displaying employee last names, department names, and locations. Which query should you use to create an equi-join?（）A. SELECT last_name, department_name, location_id FROM employees , department ;B. SELECT employees.last_name, departments.department_name, departments.location_id FROM employees e, departments D WHERE e.department_id = d.department_id;C. SELECT e.last_name, d.department_name, d.location_id FROM employees e, departments D WHERE manager_id = manager_id;D. SELECT e.last_name, d.department_name, d.location_id FROM employees e, departments D WHERE e.department_id = d.department_id;
Click the Exhibit button and examine the data in the EMPLOYEES and DEPARTMENTS tables.You want to retrieve all employees‘ last names, along with their managers‘ last names and their department names. Which query would you use?（）A.SELECT last_name, manager_id, department_name FROM employees e FULL OUTER JOIN departments d ON (e.department_id = d.department_id);B.SELECT e.last_name, m.last_name, department_name FROM employees e LEFT OUTER JOIN employees m on ( e.manager_id = m.employee_id) LEFT OUTER JOIN departments d ON (e.department_id = d.department_id);C.SELECT e.last_name, m.last_name, department_name FROM employees e RIGHT OUTER JOIN employees m on ( e.manager_id = m.employee_id) LEFT OUTER JOIN departments d ON (e.department_id = d.department_id);D.SELECT e.last_name, m.last_name, department_name FROM employees e LEFT OUTER JOIN employees m on ( e.manager_id = m.employee_id) RIGHT OUTER JOIN departments d ON (e.department_id = d.department_id);E.SELECT e.last_name, m.last_name, department_name FROM employees e RIGHT OUTER JOIN employees m on ( e.manager_id = m.employee_id) RIGHT OUTER JOIN departments d ON (e.department_id = d.department_id);F.SELECT last_name, manager_id, department_name FROM employees e JOIN departments d ON (e.department_id = d.department_id) ;
已知last指向单向简单链表的尾结点，将s所指结点加在表尾，不正确的操作是____。A．last-＞next=s,last=s,last-＞next=NULL;B．last-＞next=s,s-＞next=NULL,last=s;C．s-＞next=NULL, last-＞next=s, s=last;D．s-＞next=NULL, last-＞next=s,last=s;
7、已知last指向单向简单链表的尾结点，将s所指结点加在表尾，正确的操作是____。A．s-＞next=s,last=s,last-＞next=NULL;B．last-＞next=s,s-＞next=NULL,last=s;C．s-＞next=NULL, last-＞next=s, s=last;D．s-＞next=last, last-＞next=NULL,last=s;
已知last指向单向简单链表的尾结点，将s所指结点插入在表尾，正确的操作是____。A．s-＞next=s,last=s,last-＞next=NULL;B．last-＞next=s,s-＞next=NULL,last=s;C．s-＞next=NULL, last-＞next=s, s=last;D．s-＞next=last, last-＞next=NULL,last=s;
已知last指向单向简单链表的尾结点，将s所指结点加在表尾，正确的操作是____。A．s-＞next=s,last=s,last-＞next=NULL;B．last-＞next=s,s-＞next=NULL,last=s;C．s-＞next=NULL, last-＞next=s, s=last;D．s-＞next=last, last-＞next=NULL,last=s;
2、已知last指向单向简单链表的尾结点，将s所指结点插入在表尾，正确的操作是____。A．s-＞next=s,last=s,last-＞next=NULL;B．last-＞next=s,s-＞next=NULL,last=s;C．s-＞next=NULL, last-＞next=s, s=last;D．s-＞next=last, last-＞next=NULL,last=s;
已知last指向单向简单链表的尾结点，将s所指结点加在表尾，不正确的操作是____。A．s-＞next=NULL, last-＞next=s,last=s;B．s-＞next=NULL, last-＞next=s, s=last;C．last-＞next=s,s-＞next=NULL,last=s;D．last-＞next=s,last=s,last-＞next=NULL;