The book is ________ next year. A. publishedB. publishingC. to be publishedD. to be publishing
The book is ________ next year.
A. published
B. publishing
C. to be published
D. to be publishing
相关考题：
以下选项中正确的语句组是A)char s[]; s="BOOK!";B)char *s; s={"BOOK!"};C)char s[10]; s="BOOK!";D)char *s; s="BOOK!";
（32）以下选项中正确的语句组是A）char s[];s=”BOOK!”; B） char *s;s={”BOOK!”};C）char s[10];s=”BOOK!”; D） char *s;s=”BOOK!”;
假定有“structBOOK{chartitle[40];floatprice;};BOOK*book;”，则正确的语句为()。A、BOOK*x=newbook;B、BOOKx={"C++Programming",27.0};C、BOOK*x=newBOOK;D、BOOK*x=book;
下列选项中正确的语句是（ ）。A.chars[]；s="BOOK!"；B.char*s；S={"BOOK!")；C.chars[10]；s="BOOK"；D.char*S；s="BOOK!"；
阅读下列函数说明和C++代码，回答问题[说明]对多个元素的聚合进行遍历访问时，需要依次推移元素，例如对数组通过递增下标的方式，数组下标功能抽象化、一般化的结果就称为迭代器(Iterator)。模式以下程序模拟将书籍(Book)放到书架(BookShelf)上并依次输出书名。这样就要涉及到遍历整个书架的过程。使用迭代器Iterator实现。图5-1显示了各个类间的关系。以下是C++语言实现，能够正确编译通过。[图5-1][C++代码]template (1) class Iterator{public:virtual bool hasNext() = 0;(2) Object* next() = 0;};class Book{//省略具体方法和属性};class BookShelf{private:vector books;public:BookShelf(){}Book* getBookAt(int index){return booksindex;}int getLength(){return books. size();}};templateclass BookshelfIterator : public (3) {private:BookShelf * bookShelf;int index;public:BookshelfIterator(BookShelf *bookShelf){this-bookShelf = bookShelf;index = 0;}bool hasNext(){//判断是否还有下一个元素if(index bookShelf-getLength()){return true;}else{return false;}}Objeot* next(){//取得下一个元素return bookShelf-getBookAt(index++);}};int main(){BookShelf bookShelf;//将书籍上架，省略代码Book *book;Iterator *it = new BookShelfIterator( (4) );while( (5) ){//遍历书架，输出书名book=(Book*)it-next();/*访问元素*/}return 0;}
假定有“structBOOK{chartitle[40]floatprice}book”,则正确的语句为( )。 A.BOOK&x=&bookB.BOOK&x=bookC.BOOK&x=newBOOKD.BOOK&x=BOOK
假定有“structBOOK{chartitle[40]floatprice}BOOK*book=newBOOK”,则正确的语句为( )。 A.strcpy(book->title,”WangTao”)B.strcpy(book.title,”WangTao”)C.strcpy(*book.title,”WangTao”)D.strcpy((*book)->title,”WangTao”)
假定有“structBOOK{chartitle[40]floatprice}BOOK*book”,则不正确的语句为( )。 A.BOOK*x=newbookB.BOOKx={"C++Programming", 27.0}C.BOOK*x=newBOOKD.BOOK*x=book
假定有“struct BOOK{char title[40]； float price；} book；”，则正确的语句为（）。Astruct BOOK x= book；Bstruct BOOK *x=book；Cstruct BOOK x=calloc（BOOK）；Dstruct BOOK *x=BOOK；