单选题Given classes defined in two different files: What is required at line 5 in class SomeApp to use the process method of BitUtils?()A process(bytes);B BitUtils.process(bytes);C app.BitUtils.process(bytes);D util.BitUtils.process(bytes);E import util.BitUtils.*; process(bytes);F SomeApp cannot use the process method in BitUtils.

单选题
Given classes defined in two different files: What is required at line 5 in class SomeApp to use the process method of BitUtils?()
A

process(bytes);

B

BitUtils.process(bytes);

C

app.BitUtils.process(bytes);

D

util.BitUtils.process(bytes);

E

import util.BitUtils.*; process(bytes);

F

SomeApp cannot use the process method in BitUtils.


参考解析

解析: 暂无解析

相关考题:

You are writing a method to compress an array of bytes.The array is passed to the method in a parameter named document.You need to compress the incoming array of bytes and return the result as an array of bytes.Which code segment should you use?()A.B.C.D.

Given classes defined in two different files:1.package util;2.public class BitUtils{3.private static void process(byte[]b){}4.}1.package app;2.public class SomeApp{3.public static void main(String[]args){4.byte[]bytes=newbyte[256];5.//insert code here6.}7.}What is required at line 5 in class SomeApp to use the process method of BitUtils?()A.process(bytes);B.BitUtils.process(bytes);C.app.BitUtils.process(bytes);D.util.BitUtils.process(bytes);E.importutil.BitUtils.*;process(bytes);F.SomeApp cannot use the process method in BitUtils.

Givenclassesdefinedintwodifferentfiles:1.packageutil;2.publicclassBitUtils{3.publicstaticvoidprocess(byte[]){/*morecodehere*/}4.}1.packageapp;2.publicclassSomeApp{3.publicstaticvoidmain(String[]args){4.byte[]bytes=newbyte[256];5.//insertcodehere6.}7.}Whatisrequiredatline5inclassSomeApptousetheprocessmethodofBitUtils?()A.process(bytes);B.BitUtils.process(bytes);C.util.BitUtils.process(bytes);D.SomeAppcannotusemethodsinBitUtils.E.importutil.BitUtils.*;process(bytes);

Given classes defined in two different files:What is required at line 5 in class SomeApp to use the process method of BitUtils?() A.process(bytes);B.BitUtils.process(bytes);C.app.BitUtils.process(bytes);D.util.BitUtils.process(bytes);E.import util.BitUtils.*; process(bytes);F.SomeApp cannot use the process method in BitUtils.

UPSR protection switching is initiated by (), while BLSR is initiated by (). A. the K1 SONET byte; the K2 SONET byteB. the K2 SONET byte;the K1 SONET byteC. transmitter switching;receiver detectionD. Line Overhead bytes;Path Overhead bytesE. Path Overhead bytes;Line Overhead bytes

Usersofasite-to-siteVPNarereportingperformanceproblems.TheVPNconnectionemploysIPSecandGREandtraversesseveralEthernetsegments.TheVPNpacketsarebeing fragmentedastheytraversethelinks.Whatwouldbetwomethodstoovercomethisproblem?()A.EmploypathMTUdiscovery.B.SettheMTUhigherthan1500bytes.C.Turnoffpre-fragmentationforIPSec.D.SettheMTUvalueto1400bytes.

WhichofthefollowingistrueabouttheMPLSheaderanditsEXPfieldsize?() A.TheMPLSheaderis2bytes,andtheEXPfieldis3bitslong.B.TheMPLSheaderis1byte,andtheEXPfieldis3bitslong.C.TheMPLSheaderis4bytes,andtheEXPfieldis3bitslong.D.TheMPLSheaderis3bytes,andtheEXPfieldis3bitslong.

Refer to the exhibit. What is the meaning of the output MTU 1500 bytes?() A.Themaximumnumberofbytesthatcantraversethisinterfacepersecondis1500.B.Theminimumsegmentsizethatcantraversethisinterfaceis1500bytes.C.Theminimumpacketsizethatcantraversethisinterfaceis1500bytes.D.Themaximumpacketsizethatcantraversethisinterfaceis1500bytes.E.Themaximumframesizethatcantraversethisinterfaceis1500bytes.

Which two statements are true when the extended system ID feature is enabled? ()A、The BID is made up of the bridge priority value(two bytes) and bridge MAC address (six bytes).B、The BID is made up of the bridge priority (four bits), the system ID (12 bits), and a bridge MAC address (48 bits).C、The BID is made up of the system ID (six bytes) and bridge priority value (two bytes).D、The system ID value is the VLAN ID (VID).E、The system ID value is a unique MAC address allocated from a pool of MAC addresses assigned to the switch or module.F、The system ID value is a hex number used to measure the preference of a bridge in the spanning-tree algorithm.

What are disadvantages of Network Address Translation Transparency?()A、There is no disadvantage.B、It will add 16 bytes per packet of overhead(8 bytes UDP header, and 8 bytes of NON-IKE Marker).C、It will add 36 bytes per packet of overhead (20 bytes of IP header, 8 bytes of UDP header, 8 bytes of NON-IKE Marker).D、It will require that both crypto peers support this feature in the IOS version. Both crypto peers must also have this feature enabled.

UPSR protection switching is initiated by (), while BLSR is initiated by ().A、the K1 SONET byte; the K2 SONET byteB、the K2 SONET byte;the K1 SONET byteC、transmitter switching;receiver detectionD、Line Overhead bytes;Path Overhead bytesE、Path Overhead bytes;Line Overhead bytes

A router receives an IPv6 packet which is 2000 bytes in length. The MTU of the outgoing interface is 1500 bytes. What action will the router take?()A、forwards the packetB、fragments the packetC、drops the packet silentlyD、drops the packet and sends an ICMP message

Given classes defined in two different files: 1.package util; 2.public class BitUtils{ 3.private static void process(byte[]b){} 4.} 1.package app; 2.public class SomeApp{ 3.public static void main(String[]args){ 4.byte[]bytes=newbyte[256]; 5.//insert code here 6.} 7.} What is required at line 5 in class SomeApp to use the process method of BitUtils?()A、process(bytes);B、BitUtils.process(bytes);C、app.BitUtils.process(bytes);D、util.BitUtils.process(bytes);E、importutil.BitUtils.*;process(bytes);F、SomeApp cannot use the process method in BitUtils.

IS-IS的NET地址至少需要()bytes,其中,()bytes的(),()bytes的()和()bytes的(),最多为()bytes.

What are the header sizes for point-to-point and multi-point GRE(also known asmGRE) with tunnel key?()A、 4 bytes for bothB、 4 bytes, and 8 bytes respectivelyC、 8 bytes for bothD、 24 bytes for both

Given classes defined in two different files:  1. package util;  2. public class BitUtils {  3. private static void process(byte[] b) { }  4. }  1. package app;  2. public class SomeApp {  3. public static void main(String[] args) {  4. byte[] bytes = new byte[256];  5. // insert code here  6. }  7. }  What is required at line 5 in class SomeApp to use the process method of BitUtils?() A、 process(bytes);B、 BitUtils.process(bytes);C、 app.BitUtils.process(bytes);D、 util.BitUtils.process(bytes);E、 import util.BitUtils. *; process(bytes);F、 SomeApp cannot use the process method in BitUtils.

Given classes defined in two different files:  1. package util;  2. public class BitUtils {  3. public static void process(byte[]) { /* more code here */ }  4. }  1. package app;  2. public class SomeApp {  3. public static void main(String[] args) {  4. byte[] bytes = new byte[256];  5. // insert code here  6. }  7. }  What is required at line 5 in class SomeApp to use the process method of BitUtils?() A、 process(bytes);B、 BitUtils.process(bytes);C、 util.BitUtils.process(bytes);D、 SomeApp cannot use methods in BitUtils.E、 import util.BitUtils.*; process(bytes);

单选题Refer to the exhibit. What is the meaning of the output MTU 1500 bytes?()A Themaximumnumberofbytesthatcantraversethisinterfacepersecondis1500.B Theminimumsegmentsizethatcantraversethisinterfaceis1500bytes.C Theminimumpacketsizethatcantraversethisinterfaceis1500bytes.D Themaximumpacketsizethatcantraversethisinterfaceis1500bytes.E Themaximumframesizethatcantraversethisinterfaceis1500bytes.

单选题Given classes defined in two different files:What is required at line 5 in class SomeApp to use the process method of BitUtils?()A process(bytes);B BitUtils.process(bytes);C util.BitUtils.process(bytes);D SomeApp cannot use methods in BitUtils.E import util.BitUtils.*; process(bytes);

单选题UPSR protection switching is initiated by (), while BLSR is initiated by ().Athe K1 SONET byte; the K2 SONET byteBthe K2 SONET byte;the K1 SONET byteCtransmitter switching;receiver detectionDLine Overhead bytes;Path Overhead bytesEPath Overhead bytes;Line Overhead bytes

单选题A router receives an IPv6 packet which is 2000 bytes in length. The MTU of the outgoing interface is 1500 bytes. What action will the router take?()Aforwards the packetBfragments the packetCdrops the packet silentlyDdrops the packet and sends an ICMP message

单选题Given classes defined in two different files:  1. package util;  2. public class BitUtils {  3. private static void process(byte[] b) { }  4. }  1. package app;  2. public class SomeApp {  3. public static void main(String[] args) {  4. byte[] bytes = new byte[256];  5. // insert code here  6. }  7. }  What is required at line 5 in class SomeApp to use the process method of BitUtils?()A process(bytes);B BitUtils.process(bytes);C app.BitUtils.process(bytes);D util.BitUtils.process(bytes);E import util.BitUtils. *; process(bytes);F SomeApp cannot use the process method in BitUtils.

单选题Given classes defined in two different files:  1. package util;  2. public class BitUtils {  3. public static void process(byte[]) { /* more code here */ }  4. }  1. package app;  2. public class SomeApp {  3. public static void main(String[] args) {  4. byte[] bytes = new byte[256];  5. // insert code here  6. }  7. }  What is required at line 5 in class SomeApp to use the process method of BitUtils?()A process(bytes);B BitUtils.process(bytes);C util.BitUtils.process(bytes);D SomeApp cannot use methods in BitUtils.E import util.BitUtils.*; process(bytes);

单选题Given classes defined in two different files: 1.package util; 2.public class BitUtils{ 3.private static void process(byte[]b){} 4.} 1.package app; 2.public class SomeApp{ 3.public static void main(String[]args){ 4.byte[]bytes=newbyte[256]; 5.//insert code here 6.} 7.} What is required at line 5 in class SomeApp to use the process method of BitUtils?()Aprocess(bytes);BBitUtils.process(bytes);Capp.BitUtils.process(bytes);Dutil.BitUtils.process(bytes);Eimportutil.BitUtils.*;process(bytes);FSomeApp cannot use the process method in BitUtils.

单选题What are the header sizes for point-to-point and multi-point GRE(also known asmGRE) with tunnel key?()A 4 bytes for bothB 4 bytes, and 8 bytes respectivelyC 8 bytes for bothD 24 bytes for both

多选题Which two statements are true when the extended system ID feature is enabled? ()AThe BID is made up of the bridge priority value(two bytes) and bridge MAC address (six bytes).BThe BID is made up of the bridge priority (four bits), the system ID (12 bits), and a bridge MAC address (48 bits).CThe BID is made up of the system ID (six bytes) and bridge priority value (two bytes).DThe system ID value is the VLAN ID (VID).EThe system ID value is a unique MAC address allocated from a pool of MAC addresses assigned to the switch or module.FThe system ID value is a hex number used to measure the preference of a bridge in the spanning-tree algorithm.

多选题What are disadvantages of Network Address Translation Transparency?()AThere is no disadvantage.BIt will add 16 bytes per packet of overhead(8 bytes UDP header, and 8 bytes of NON-IKE Marker).CIt will add 36 bytes per packet of overhead (20 bytes of IP header, 8 bytes of UDP header, 8 bytes of NON-IKE Marker).DIt will require that both crypto peers support this feature in the IOS version. Both crypto peers must also have this feature enabled.