名词解释题双单体附加系（double monosomic additive line）
名词解释题
双单体附加系（double monosomic additive line）
参考解析
解析：
暂无解析
相关考题：
Which of the following depreciation methods provides for accelerated depreciation of an asset:A . Double declining balance.B . Straight line.C . Exponential depreciationD . Double sum of the years digitsE . Double increasing balance
43 Which of the following depreciation methods provides for accelerated depreciation of an asset: A. Double declining balance.B. Straight line.C. Exponential depreciationD. Double sum of the years digitsE. Double increasing balance
If it were as cheap and easy to get ________ here as in America, the British might double their time at the computer. (A) off line(B) online(C) internet(D) on line
Why are stage 1 and stage 2 interrelated by a double arrow line? Why are practice and reflection connected by a circle? (See Fihure 1.1 on Page 9 of the textbook)
To “EASE” A LINE means to ___ .A.cast offB.double up so that one line does not take all the strainC.pay out line to remove most of the tensionD.slack it off quickly
String name="Jane Doe";36.int$age=24;37.Double_height=123.5;38.double~temp=37.5;Which two are true?() A.Line 35 will not compile.B.Line 36 will not compile.C.Line 37 will not compile.D.Line 38 will not compile.
阅读下列C++程序和程序说明，将应填入(n)处的字句写在对应栏内。【说明】Point是平面坐标系上的点类，Line是从Point派生出来的直线类。include ＜iostream.h＞class Point{public:Point (int x, int y) ;Point (Point p) ;～Point();void set (double x, double y) ;void print();private:double X,Y;};Point::Point (int x, int y) //Point 构造函数{X=x; Y=y; }Point::Point ( (1) ) //Point 拷贝构造函数{X=p.X; Y=p.Y；}void Point::set (double x, double y){X=x; Y=y; }void Point::print(){cout＜＜' ('＜＜X＜＜","＜＜Y＜＜") "＜＜endl; }Point::～Point(){cout＜＜"Point 的析构函数被调用! "＜＜endl;class Line: public Point{public:Line (int x, int y, int k) ;Line (Line s) ;～Line();void set (double x, double y, double k)void print();private:double K;};(2)//Line 构造函数实现{ K=k;}(3)//Line 拷贝构造函数实现{K=s.K;}void Line::set (double x, double y, double k){ (4);K=k;}void Line::print(){cout＜＜" 直线经过点";(5);cout＜＜"斜率为: k="＜＜K＜＜endl;}Line: :～Line(){cout＜＜"Line 析构函数被调用! "＜＜endl;}void main(){Line 11 (1,1,2) ;11 .print();Linel2 (11) ;12.set (3,2,1) ;12.print();}
Given:Which two methods, inserted independently at line 17, correctly complete the Sales class?() A.double getSalesAmount() { return 1230.45; }B.public double getSalesAmount() { return 1230.45; }C.private double getSalesAmount() { return 1230.45; }D.protected double getSalesAmount() { return 1230.45; }
Given:35.Stringname=JaneDoe;36.int$age=24;37.Double_height=123.5;38.double~temp=37.5;Whichtwostatementsaretrue?() A.Line35willnotcompile.B.Line36willnotcompile.C.Line37willnotcompile.D.Line38willnotcompile.
使用VC6打开考生文件夹下的工程RevProj14。此工程包含一个源程序文件RevMain14.cpp，但该程序中类的定义有错误。请改正程序中的错误，使它能得到正确结果。注意，不要改动main函数，不得删行或增行，也不得更改程序的结构。源程序文件RevMain14.cpp中的程序清单如下：//RevMain14.cppinclude＜iostream＞include＜math＞using namespace std；class Point{private：double x；double y；public：Point(){}void Point(double x1,double y1){x=x1;y=y1;}void setvalue(double x,double y){x=x;y=y;}double getx (){return x;}double gety()}return y;}void print(){cout＜＜"x="＜＜x＜＜",y= "＜＜y＜＜end1;}～Point(){}};class Line{private:Point p1;Point p2;double width;public:Line(double x1,double y1,double x2,double y2,double d):p1(x1,y1),p2(x2,y2){width=d;}～Line(){}void displength(){double 1;1=sqrt((p1.getx{)-p2.getx())*(p1.getx()-p2-getx())+(p1.gety()-p2.gety())*(p1.gety()-p2.gety()));cout＜＜"the length of Line is "＜＜1＜＜end1;}};int main(){Line *p1;Line 1(5,15,25,35,0.5);p1=1;p1-＞displength();return 0;}
10. abstract public class Employee { 11. protected abstract double getSalesAmount（）； 12. public double getCommision（） { 13. return getSalesAmount（） * 0.15； 14. } 15. } 16. class Sales extends Employee { 17. // insert method here 18. } Which two methods， inserted independently at line 17， correctly complete the Sales class？（）A、 double getSalesAmount（） { return 1230.45； }B、 public double getSalesAmount（） { return 1230.45； }C、 private double getSalesAmount（） { return 1230.45； }D、 protected double getSalesAmount（） { return 1230.45； }
Given： 35.String #name = "Jane Doe"； 36.int $age = 24； 37.Double _height = 123.5； 38.double ~temp = 37.5； Which two statements are true？（）A、Line 35 will not compile.B、Line 36 will not compile.C、Line 37 will not compile.D、Line 38 will not compile.
Which of the following types of UPS would be used with equipment that is very sensitive to power fluctuations？（）A、Offline/StandbyB、Line interactiveC、RackmountD、Online/Double Conversion
1. public class returnIt （ 2. returnType methodA（byte x， double y） （ 3. return （short） x/y * 2； 4. ） 5. ） What is the valid returnType for methodA in line 2？（） A、 IntB、 ByteC、 LongD、 ShortE、 FloatF、 Double
11. double d = Math.random（）； Which is true about d after line 11？（） A、 d = 1.0B、 0.0 = d 1.0C、 0.0 = d Double.MAX_VALUED、 0.0 = d = Double.MAX_VALUEE、 Double.MIN_VALUE = d Double.MAX_VALUE
public class returnIt （ returnType methodA（byte x， double y） （ return （short） x/y * 2； ） ） What is the valid returnType for methodA in line 2？（）A、 IntB、 ByteC、 LongD、 ShortE、 FloatF、 Double
多选题Given: Which two methods, inserted independently at line 17, correctly complete the Sales class?（）Adouble getSalesAmount() { return 1230.45; }Bpublic double getSalesAmount() { return 1230.45; }Cprivate double getSalesAmount() { return 1230.45; }Dprotected double getSalesAmount() { return 1230.45; }
单选题public class returnIt （ returnType methodA（byte x， double y） （ return （short） x/y * 2； ） ） What is the valid returnType for methodA in line 2？（）A IntB ByteC LongD ShortE FloatF Double
单选题11. double d = Math.random（）； Which is true about d after line 11？（）A d = 1.0B 0.0 = d 1.0C 0.0 = d Double.MAX_VALUED 0.0 = d = Double.MAX_VALUEE Double.MIN_VALUE = d Double.MAX_VALUE
单选题The purpose of a bilge well is to（）.Aafford access to the shell through the double bottomsBcollect water to be pumped outCprovide access for the pneumercatorDprovide a base line for sounding measurements
名词解释题单体附加系（Monosomic additive line）