I will______ tomorrow. A.cut my hairB.have my hair be cutC.have my hair cutD.ask someone cut my hair
I will______ tomorrow.
A.cut my hair
B.have my hair be cut
C.have my hair cut
D.ask someone cut my hair
相关考题：
请判断下面这些划线单词的词性，并在单词后面的空白处标记(属于Noun的填写1，属于Verb的填写2)。1.Make sure there is enough room to seat ________[2]everyone in the meeting.2.In the bus, a man offered his seat________[1] to an old lady with a huge bag.3.A discussion meeting should place________[2] tables into a circle or square, so that everyone can see each other.4.I found a place________[1] to park my car.5.The type of meeting will also help determine what other things need________[2] to be prepared, such as pens, notebooks, snacks, coffee and water.6.You also need________[1] to consider the equipment needs of the meeting.7.You can start to look for a meeting place that can met________[2] all your requirements.8.You need to determine if you are going to the sports meet________[1] tomorrow.
现有以下语句: i=1; for (;i＜=100;i++) sum+=i;A．for(i-1;;i++) { sum+--i; if(i==100) break; }B．for(i=1;i＜=100;) { sum+=i; i++; }C．i=1; for(;i＜=100;) { sum+=-i; }D．i=1; for(;;) { sum+=i; if(i==100) break; i++; }
与“for(i=0；i＜10；i++)putchar('a'+i)；”功能不同的语句是______。A．for(i=0；i＜10；)putchar('a'+(++i))；B．for(i=0；i＜10；)putchar('a'+(i++))；C．for(i=0；i＜10；putchar('a'+i)，i++)；D．for(i=0；i＜=9；i++)putchar('a'+i)；
根据(A/F,i，n)=i/[(1+i)n-1]，可以推断()成立。A:(A/F,i,n)+i=(A/P,i,n)B:(A/F,i,n)*i=(A/P,i,n)C:(A/F,i,n)+i=(P/A,i,n)D:(A/F,i,n)-i=(P/A,i,n)
int a[10]; 给数组a的所有元素分别赋值为1、2、3、……的语句是（）。A．for(i=1;i＜11;i++)a[i+1]=i;B．for(i=1;i＜11;i++)a[i-1]=i;C．for(i=1;i＜11;i++)a[i]=i;D．for(i=1;i＜11;i++)a[0]=1;
int a[10]; 给数组a的所有元素分别赋值为1、2、3、……的语句是（）。A．for(i=1;i＜11;i++)a[i]=i;B．for(i=1;i＜11;i++)a[i-1]=i;C．for(i=1;i＜11;i++)a[i+1]=i;D．for(i=1;i＜11;i++)a[0]=1;
以下哪个for语句是正确的？A．for(i=0; i＜10; i++);B．for(i=0; i＜10, i++);C．for(i=0, i＜10; i++);D．for(i=0, i＜10, i++);E．for(i=0; i＜10);F．for(i=0; i++);
int a[5]={1,0,3,4,-2}; 以下正确的打擂台算法求最小值的是A．int min,i; for(i=0;i＜5;i++) if(a[i]＜min) min=a[i];B．int min=a[0],i; for(i=0;i＜5;i++) if(a[i]＜min) min=a[i];C．int min=a[1],i; for(i=0;i＜5;i++) if(a[i]＞min) min=a[i];D．int min=a[0],i; for(i=1;i＜5;i++) if(a[i]＜min) min=a[i];